Problem 12
Question
Find a polar representation for the complex number \(z\) and then identify \(\operatorname{Re}(z)\), \(\operatorname{Im}(z),|z|, \arg (z)\) and \(\operatorname{Arg}(z)\). $$ z=i \sqrt[3]{7} $$
Step-by-Step Solution
Verified Answer
\(\operatorname{Re}(z) = 0\), \(\operatorname{Im}(z) = \sqrt[3]{7}\), \(|z| = 7^{1/3}\), \(\arg(z) = \frac{\pi}{2}\), and \(\operatorname{Arg}(z) = \frac{\pi}{2}\).
1Step 1: Identify Real and Imaginary Parts
The given complex number is \(z = i \sqrt[3]{7}\). Here the real part is 0, since there is no real number part, and the imaginary part is \(\sqrt[3]{7}\). Thus, \(\operatorname{Re}(z) = 0\) and \(\operatorname{Im}(z) = \sqrt[3]{7}\).
2Step 2: Calculate the Magnitude of \(z\)
The magnitude (or modulus) \(|z|\) of a complex number \(z = a + bi\) is given by \(|z| = \sqrt{a^2 + b^2}\). Here, \(a = 0\) and \(b = \sqrt[3]{7}\). Thus, \(|z| = \sqrt{0^2 + (\sqrt[3]{7})^2} = \sqrt{7^{2/3}} = 7^{1/3}\).
3Step 3: Determine the Argument of \(z\)
The argument \(\arg(z)\) of a complex number given by \(z = a + bi\) is the angle \(\theta\) such that \(\tan(\theta) = \frac{b}{a}\). In this case, since \(a = 0\) and \(b = \sqrt[3]{7}\), the angle \(\theta\) that meets this criterion is \(\frac{\pi}{2}\), because it places our vector on the positive imaginary axis.
4Step 4: Calculate Principal Argument
The principal argument (denoted \(\operatorname{Arg}(z)\)) is the value of the argument \(\arg(z)\) that lies in the interval \( (-\pi, \pi] \). In our case, since \(\arg(z) = \frac{\pi}{2}\), \(\operatorname{Arg}(z) = \frac{\pi}{2}\), which naturally falls in the required interval.
Key Concepts
Real and Imaginary PartsMagnitude of Complex NumbersArgument of Complex NumbersPrincipal Argument
Real and Imaginary Parts
In complex numbers, we often encounter terms like "real part" and "imaginary part". A complex number is expressed as \( z = a + bi \), where \( a \) and \( b \) are real numbers. Here, \( a \) is the real part, and \( b \) is the imaginary part which is multiplied by the imaginary unit \( i \). In the given complex number \( z = i \sqrt[3]{7} \), we do not see any real component because there is no standalone number outside the imaginary part.
Thus, for \( z = i \sqrt[3]{7} \):
Thus, for \( z = i \sqrt[3]{7} \):
- The real part, \( \operatorname{Re}(z) = 0 \).
- The imaginary part, \( \operatorname{Im}(z) = \sqrt[3]{7} \).
Magnitude of Complex Numbers
The magnitude of a complex number, also known as the modulus, is like a distance in mathematics. It tells us how far the number is from the origin on the complex plane. Mathematically, if a complex number is expressed as \( z = a + bi \), the magnitude \( |z| \) is calculated using the Pythagorean theorem as \( |z| = \sqrt{a^2 + b^2} \).
For our complex number \( z = i \sqrt[3]{7} \), we establish:
For our complex number \( z = i \sqrt[3]{7} \), we establish:
- Real part \( a = 0 \).
- Imaginary part \( b = \sqrt[3]{7} \).
- Hence, \( |z| = \sqrt{0^2 + (\sqrt[3]{7})^2} = \sqrt{7^{2/3}} = 7^{1/3} \).
Argument of Complex Numbers
The argument of a complex number is an angle which indicates its direction with respect to the positive real axis on the complex plane. Given a complex number \( z = a + bi \), its argument \( \arg(z) \) is calculated using the formula \( \tan(\theta) = \frac{b}{a} \), where \( \theta \) represents the angle.
In the complex number \( z = i \sqrt[3]{7} \), we find:
In the complex number \( z = i \sqrt[3]{7} \), we find:
- \( a = 0 \)
- \( b = \sqrt[3]{7} \)
Principal Argument
The principal argument is a specialized kind of argument. It refers to the value of the angle \( \arg(z) \) that lies within the interval \((-\pi, \pi]\). It helps ensure that every complex number has a single, unique polar representation.
In our example, since the argument \( \arg(z) = \frac{\pi}{2} \) already lies within the set range \((-\pi, \pi]\), it also serves as the principal argument:
In our example, since the argument \( \arg(z) = \frac{\pi}{2} \) already lies within the set range \((-\pi, \pi]\), it also serves as the principal argument:
- \( \operatorname{Arg}(z) = \frac{\pi}{2} \)
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