Problem 12
Question
Factor. $$ x 2+4 x+3 $$
Step-by-Step Solution
Verified Answer
The factored form is \((x + 1)(x + 3)\).
1Step 1: Identify the Polynomial
The given polynomial is a quadratic equation in the form of \( ax^2 + bx + c \). Here, \( a = 1 \), \( b = 4 \), and \( c = 3 \).
2Step 2: Confirm Leading Coefficient
Notice that the leading coefficient \( a = 1 \), which simplifies the factoring process as we focus primarily on the middle term and constant.
3Step 3: Product-Sum Method
To factor the quadratic \( x^2 + 4x + 3 \), find two numbers that multiply to \( ac \) (which is 3) and add up to \( b \) (which is 4). These numbers are 1 and 3.
4Step 4: Rewrite the Middle Term
Rewrite the expression \( x^2 + 4x + 3 \) using the numbers found: \( x^2 + 1x + 3x + 3 \).
5Step 5: Group Terms
Group the expression into two pairs: \((x^2 + 1x) + (3x + 3)\).
6Step 6: Factor Each Group
Factor out the greatest common factor from each group: \(x(x + 1) + 3(x + 1)\).
7Step 7: Apply the Distributive Property
Notice that \((x + 1)\) is a common factor, factor it out: \((x + 1)(x + 3)\).
8Step 8: Verify Factored Form
Multiply \((x + 1)(x + 3)\) to verify: \((x + 1)(x + 3) = x^2 + 3x + x + 3 = x^2 + 4x + 3\), confirming the factorization is correct.
Key Concepts
Product-Sum MethodPolynomial EquationsDistributive Property
Product-Sum Method
The product-sum method is an efficient strategy used to factor quadratic expressions of the form \( ax^2 + bx + c \). This method is especially straightforward when the leading coefficient, \( a \), is 1. The core idea is to find two numbers that multiply to give the product of \( a \) and \( c \), and simultaneously add up to \( b \).
- Identify the coefficients: In our example, \( a = 1 \), \( b = 4 \), and \( c = 3 \).
- Calculate \( ac \), which in this case is \( 1 \times 3 = 3 \).
- Find two numbers that multiply to 3 and add to 4. These numbers are 1 and 3.
Polynomial Equations
Polynomial equations encompass expressions consisting of variables and coefficients involving only the operations of addition, subtraction, multiplication, and non-negative integer exponents.
- The degree of a polynomial refers to the highest exponent; for example, \( x^2 + 4x + 3 \) is a quadratic polynomial because its highest power is 2.
- In solving polynomial equations, particularly quadratics, factorization is a favored technique as it simplifies the expressions into smaller, manageable parts.
- Each of these smaller parts, or factors, can be set to zero to find solutions to the equation, also known as 'roots'.
Distributive Property
The distributive property is a fundamental principle in algebra which allows you to expand or simplify expressions. It states that \( a(b + c) = ab + ac \). This property is viable both "backward" in expanding and "forward" in factoring.In the context of factoring quadratics, the distributive property enables us to factor out common terms from an expression.
- When we broke down the expression \((x^2 + 1x) + (3x + 3)\) into \(x(x + 1) + 3(x + 1)\), the property helped us recognize \((x + 1)\) as a common factor.
- We applied the distributive property "backwards" to factor \((x + 1)\) from both grouped terms, resulting in the product \((x + 1)(x + 3)\).
- This demonstration shows that recognizing common factors first can ease the complexity of a polynomial.
Other exercises in this chapter
Problem 12
Determine the GCF of all the terms. $$ 14 x, 21 $$
View solution Problem 12
Factor. $$ 4 x 2-20 x+25 $$
View solution Problem 12
Factor completely. $$ 9 x_{2}-121 $$
View solution Problem 13
The product of two consecutive positive even integers is 120 . Find the integers.
View solution