Problem 12
Question
Factor completely. $$q^{2}-22 q+121$$
Step-by-Step Solution
Verified Answer
The completely factored form of the given expression is \((q-11)^2\).
1Step 1: Identify the Form of the Perfect Square Trinomial
Observe that the expression $$q^2 - 22q + 121$$ resembles $$a^2 - 2ab + b^2$$, where \(a = q\). Our task is now to find \(b\).
2Step 2: Find the Value of b
We can find the value of \(b\) using the coefficient of the \(q\) term in the expression.
In our case, the coefficient is -22, and it represents -2ab. Since a = q, we have:
$$-22 = -2(q)(b)$$
Divide both sides by -2q:
$$\frac{-22}{-2q} = b$$
Now, insert the value of a:
$$\frac{-22}{-2(q)}=b$$
$$\frac{-11}{q}=b$$
$$11=-b$$
So, \(b=11\).
3Step 3: Write the Factored form of the Expression
Now that we have identified the values of \(a\) and \(b\), we can write the factored form of the given quadratic expression using the formula $$(a - b)^2$$.
In our case, \(a=q\) and \(b=11\), so the expression can be written as:
$$(q-11)^2$$
Therefore, the completely factored form of the given expression is $$(q-11)^2$$.
Key Concepts
Perfect Square TrinomialQuadratic ExpressionsFactoring Techniques
Perfect Square Trinomial
A perfect square trinomial is a special form of a quadratic expression. It takes on the form: \(a^2 - 2ab + b^2\) or \(a^2 + 2ab + b^2\). This expression arises when you square a binomial.
In simpler terms, a binomial is an expression with two terms, like \((a+b)\) or \((a-b)\). When you square these, you get something like \((a-b)^2 = a^2 - 2ab + b^2\).
A primary identifier of a perfect square trinomial is that it represents a squared binomial in its expanded form.
In simpler terms, a binomial is an expression with two terms, like \((a+b)\) or \((a-b)\). When you square these, you get something like \((a-b)^2 = a^2 - 2ab + b^2\).
A primary identifier of a perfect square trinomial is that it represents a squared binomial in its expanded form.
- The first term is a perfect square (\(a^2\))
- The third term is also a perfect square (\(b^2\))
- The middle term is twice the product of the first and last term's square roots (\(-2ab\) or \(+2ab\))
Quadratic Expressions
Quadratic expressions are polynomial expressions of the second degree. They typically look like \(ax^2 + bx + c\) where:
Quadratic expressions can come in various forms, including standard form, vertex form, and factored form. Understanding these forms allows you to solve quadratic equations and transform them to show different properties, such as roots or vertex location.
- \(a\), \(b\), and \(c\) are constants.
- \(x\) is a variable.
- \(a\) is not zero because it determines the quadratic nature.
Quadratic expressions can come in various forms, including standard form, vertex form, and factored form. Understanding these forms allows you to solve quadratic equations and transform them to show different properties, such as roots or vertex location.
Factoring Techniques
Factoring is a technique used to break down more complex expressions into simpler ones, particularly quadratic expressions. Recognizing patterns in quadratics allows us to use different techniques to factorize them effectively.
- **Factoring by grouping**: Useful when there is no clear standard pattern, but terms can be grouped to expose a common factor.
- **Difference of squares**: Where expressions fit \(a^2 - b^2 = (a+b)(a-b)\).
- **Perfect square trinomials**: As discussed, these can be written as \((a-b)^2\) or \((a+b)^2\).
- **Quadratic formula**: Utilized when other methods don't immediately apply; expressed as \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\).
- **Trial and error**: Sometimes, testing simple combinations of factors leads to a solution.
Other exercises in this chapter
Problem 11
Complete the factorization. $$c^{2}-14 c+45=(c-5)(\quad)$$
View solution Problem 12
Write an equation and solve. A rectangular painting is twice as long as it is wide. Find its dimensions if it has an area of \(12.5 \mathrm{ft}^{2}\)
View solution Problem 12
Factor by grouping. Find the polynomial which factors to \((3 x-8)(x+2)\)
View solution Problem 12
Solve each equation.. \((d+7)^{2}=0\)
View solution