Problem 12
Question
Expand each power. $$ (m+n)^{4} $$
Step-by-Step Solution
Verified Answer
The expansion is \(m^4 + 4m^3n + 6m^2n^2 + 4mn^3 + n^4\).
1Step 1: Identify the Binomial Theorem
The binomial theorem provides a way to expand a binomial raised to a power. It states that \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^{k}\) where \( \binom{n}{k} \) is the binomial coefficient.
2Step 2: Apply the Binomial Theorem
Using the binomial theorem, plug in \(a = m\), \(b = n\), and \(n = 4\).\[(m+n)^4 = \sum_{k=0}^{4} \binom{4}{k} m^{4-k} n^{k}\]
3Step 3: Calculate the Binomial Coefficients
Calculate each binomial coefficient for \(k = 0, 1, 2, 3, 4\):- \( \binom{4}{0} = 1\) - \( \binom{4}{1} = 4\) - \( \binom{4}{2} = 6\) - \( \binom{4}{3} = 4\) - \( \binom{4}{4} = 1\)
4Step 4: Expand the Binomial Expression
Plug these coefficients into the binomial expansion formula:\[(m+n)^4 = 1 \cdot m^4 + 4 \cdot m^3 \cdot n + 6 \cdot m^2 \cdot n^2 + 4 \cdot m \cdot n^3 + 1 \cdot n^4\]
5Step 5: Simplify the Expression
Combine and simplify the expression:\[(m+n)^4 = m^4 + 4m^3n + 6m^2n^2 + 4mn^3 + n^4\]
Key Concepts
Binomial ExpansionBinomial CoefficientAlgebraic Expressions
Binomial Expansion
The binomial expansion is a fundamental concept in algebra used to express the powers of a binomial as a sum of terms. The binomial expansion follows a systematic pattern governed by the binomial theorem. When you raise a binomial, such as \((m+n)\), to a power like 4, it generates a series of terms combined in a specific way.For \((m+n)^4\), the binomial expansion provides an expanded form that consists of terms with varying powers of \(m\) and \(n\). These terms are formed by applying the binomial theorem:
- Each term in the expansion is a unique combination of \(m\) and \(n\).
- The exponents of \(m\) and \(n\) in each term add up to 4, which is the power of the binomial.
- The number of terms in the expansion is one more than the power of the binomial, making it 5 in this case.
Binomial Coefficient
The binomial coefficient is crucial in determining the weights of each term in a binomial expansion. Represented as \( \binom{n}{k} \), it is a mathematical way to select \(k\) items from \(n\) items without consideration of order. In our scenario:
- The binomial coefficients for \((m+n)^4\) are calculated as follows:\(\binom{4}{0}\), \(\binom{4}{1}\), \(\binom{4}{2}\), \(\binom{4}{3}\), \(\binom{4}{4}\)
- When computed, these coefficients are 1, 4, 6, 4, and 1 respectively.
- These coefficients determine how each product of \(m\) and \(n\) in the expansion is scaled.
Algebraic Expressions
Algebraic expressions are composed of variables, numbers, and operations combined in a meaningful way. In the context of the binomial expansion, the algebraic expression \((m+n)^4\) represents a combination of terms brought together through addition.In the expanded form of \((m+n)^4\),
- Each term is an algebraic expression itself, consisting of products of variables raised to different powers.
- The expression is simplified by calculating and combining like terms, which involves applying arithmetic operations to consolidate them.
- The final simplified form of the expansion results in a neatly organized series of terms: \(m^4 + 4m^3n + 6m^2n^2 + 4mn^3 + n^4\).
Other exercises in this chapter
Problem 11
Find \(a_{1}\) for each arithmetic series described. $$ d=-2, n=12, S_{12}=96 $$
View solution Problem 12
Prove that each statement is true for all positive integers. \(8^{n}-1\) is divisible by 7
View solution Problem 12
Find the first five terms of each sequence. $$ a_{1}=2, a_{n+1}=a_{n}-n $$
View solution Problem 12
Write each repeating decimal as a fraction. \(0 . \overline{175}\)
View solution