Problem 12
Question
Exer. 5-40: Find the amplitude, the period, and the phase shift and sketch the graph of the equation. $$ y=3 \cos \left(x+\frac{\pi}{6}\right) $$
Step-by-Step Solution
Verified Answer
Amplitude: 3, Period: \(2\pi\), Phase Shift: \(-\frac{\pi}{6}\), graph is left by \(\frac{\pi}{6}\).
1Step 1: Identify the Amplitude
The cosine function given is in the form \( y = a \cos(bx + c) \). In this equation, \( a = 3 \), which represents the amplitude. Therefore, the amplitude is 3.
2Step 2: Determine the Period
The period of a cosine function in the standard form \( y = a \cos(bx + c) \) is given by \( \frac{2\pi}{b} \). Here, \( b = 1 \), so the period of the function is \( \frac{2\pi}{1} = 2\pi \).
3Step 3: Calculate the Phase Shift
The phase shift of a function \( y = a \cos(bx + c) \) is given by \( -\frac{c}{b} \). In the given equation, \( c = \frac{\pi}{6} \) and \( b = 1 \), so the phase shift is \( -\frac{\pi}{6} \). This indicates a shift to the left by \( \frac{\pi}{6} \) units.
4Step 4: Sketch the Graph
With the amplitude, period, and phase shift identified, sketch the graph of the function. The graph of \( y = 3\cos(x + \frac{\pi}{6}) \) will have a maximum value of 3, a minimum value of -3, a period of \( 2\pi \), and will start \( \frac{\pi}{6} \) units to the left of the y-axis compared to the standard cosine graph.
Key Concepts
AmplitudePeriodPhase Shift
Amplitude
When dealing with trigonometric functions like cosine, the amplitude is a crucial component that determines how tall or short the graph appears. The amplitude is the distance from the middle of the wave to its peak or trough.
- In the standard cosine function formula, \(y = a \cos(bx + c)\), the amplitude is represented by \(a\).
- For the equation \(y = 3\cos\left(x+\frac{\pi}{6}\right)\), the amplitude is \(3\). This means that the graph will reach 3 units above and 3 units below the center line, or midline, of the graph.
Period
The period of a trigonometric function indicates how long it takes for the function to complete one full cycle of its pattern. Essentially, it tells us how 'stretched' or 'compressed' the graph of the function is.
- For the cosine function \(y = a \cos(bx + c)\), the period is calculated using the formula \(\frac{2\pi}{b}\).
- In our equation \(y = 3 \cos\left(x+\frac{\pi}{6}\right)\), the value of \(b\) is 1, giving us a period of \(\frac{2\pi}{1} = 2\pi\).
Phase Shift
The phase shift of a trigonometric function tells us how much the graph is shifted to the left or right compared to its standard position. This happens when we adjust where the function 'starts' its cycle on the x-axis.
- The phase shift is found using the formula \(-\frac{c}{b}\) in the function \(y = a \cos(bx + c)\).
- For \(y = 3 \cos\left(x+\frac{\pi}{6}\right)\), \(b = 1\) and \(c = \frac{\pi}{6}\). Hence, the phase shift is \(-\frac{\pi}{6}\).
Other exercises in this chapter
Problem 11
Find the exact radian measure of the angle. (a) \(450^{\circ}\) (b) \(72^{\circ}\) (c) \(100^{\circ}\)
View solution Problem 12
Exer. 9-16: Let \(P\) be the point on the unit circle \(U\) that corresponds to \(t\). Find the coordinates of \(P\) and the exact values of the trigonometric f
View solution Problem 12
Find the period and sketch the graph of the equation. Show the asymptotes. $$ y=\tan \frac{1}{2} x $$
View solution Problem 12
Find the exact value. (a) \(\tan 330^{\circ}\) (b) \(\tan \left(-225^{\circ}\right)\)
View solution