Problem 12
Question
Evaluate the limit, if it exists. \( \displaystyle \lim_{x \to -3}\frac{x^2 + 3x}{x^2 - x - 12} \)
Step-by-Step Solution
Verified Answer
The limit is \(\frac{3}{7}\).
1Step 1: Factor the Expressions
First, let's factor both the numerator and the denominator. The numerator is \(x^2 + 3x\), and this can be factored as \(x(x + 3)\). The denominator is \(x^2 - x - 12\), which factors into \((x - 4)(x + 3)\).
2Step 2: Cancel Common Factors
Notice that both the numerator and the denominator have a common factor \((x + 3)\). Therefore, we can cancel this factor out, simplifying the expression to \(\frac{x}{x - 4}\).
3Step 3: Evaluate the Limit
Now, evaluate the limit of the simplified expression \(\lim_{x \to -3} \frac{x}{x - 4}\). Substitute \(-3\) into the expression: \(\frac{-3}{-3 - 4} = \frac{-3}{-7} = \frac{3}{7}\).
4Step 4: Conclude the Evaluation
Since the fractional value obtained does not lead to any indeterminate form or redefine the limits, the limit exists and is \(\frac{3}{7}\).
Key Concepts
Factoring PolynomialsSimplifying ExpressionsCanceling Common FactorsSubstitution in Limits
Factoring Polynomials
Factoring polynomials is an important first step in evaluating limits involving rational expressions. A polynomial is factored when it is expressed as a product of its constituent polynomials of lower degrees. This simplifies the expressions, making further calculations manageable. In the provided exercise, we begin by factoring the numerator and the denominator.
- **Numerator:** The expression is given as \(x^2 + 3x\). This can be factored by pulling out the common factor \(x\), resulting in \(x(x + 3)\).
- **Denominator:** The expression \(x^2 - x - 12\) requires finding two numbers that multiply to \(-12\) and add up to \(-1\). These numbers are \(-4\) and \(+3\), which leads to the factorization \((x - 4)(x + 3)\).
Simplifying Expressions
After factoring, the next step is simplifying the expression. Simplifying involves reducing the expression to its simplest form, which often means canceling out terms that are identical in both numerator and denominator. Simplification is crucial as it often prepares the expression for direct substitution.Once the polynomial is factored:
- The numerator \(x(x + 3)\) and the denominator \((x - 4)(x + 3)\) both include the common factor \((x + 3)\).
- This common factor can be canceled, simplifying the expression to \(\frac{x}{x - 4}\).
Canceling Common Factors
Canceling common factors is a key step in simplifying expressions, especially in rational functions. By removing the common factors, you segregate the terms directly affecting the limit's behavior from those that do not. This step is vital because it removes potential undefined points that arise when the approach to the limit involves division by zero.In our example:
- The numerator \(x(x + 3)\) and the denominator \((x - 4)(x + 3)\) contain the common factor \((x + 3)\).
- By canceling \((x + 3)\), we avoid division by zero and any associated indeterminate forms.
Substitution in Limits
Substitution is typically one of the last steps in evaluating a limit, especially after an expression is simplified. When substituting in limits, you directly substitute the approaching value into the simplified expression. This allows for clear and easy calculations.In the problem at hand:
- After simplification to \(\frac{x}{x - 4}\), the next step is to evaluate \(\lim_{x \to -3}\).
- By substituting \(-3\) into the expression, we get \(\frac{-3}{-3 - 4} = \frac{-3}{-7} = \frac{3}{7}\).
Other exercises in this chapter
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