Problem 12
Question
Apply the properties of logarithms to simplify each expression. Do not use a calculator. $$2^{\log _{2} 5}$$
Step-by-Step Solution
Verified Answer
The simplified expression is 5.
1Step 1: Understanding the Problem
We are given the expression \(2^{\log_{2} 5}\) and asked to simplify it using properties of logarithms. This involves recognizing how logarithms and exponents can be combined.
2Step 2: Apply the Power Rule of Logarithms
The power rule of logarithms is \(a^{\log_{a}(x)} = x\). Since the base of the exponent and the base of the logarithm are the same in our expression, we can directly apply this rule.
3Step 3: Implement the Power Rule
By applying the power rule \(a^{\log_{a}(x)} = x\) to our expression, we identify \(a = 2\) and \(x = 5\). Therefore, \(2^{\log_{2}5} = 5\).
4Step 4: Conclusion
The expression \(2^{\log_{2} 5}\) simplifies directly to 5 using the property of logarithms. This is a straightforward application of the power rule with matching bases.
Key Concepts
ExponentsPower RuleSimplifying Expressions
Exponents
An exponent refers to the number of times a number, known as the base, is multiplied by itself. For instance, in the expression \(a^n\), \(a\) is the base, and \(n\) is the exponent. Understanding exponents is crucial because they simplify expressions involving repeated multiplication.
- The number \(a^2\) means \(a\) multiplied by itself once: \(a \times a\).
- Similarly, \(a^3\) refers to \(a \times a \times a\).
Power Rule
The power rule is a property of logarithms that provides an essential shortcut for simplifying expressions where the base and logarithm are the same. The rule states that for any positive number \(a\) and any real number \(x\), then \(a^{\log_{a}(x)} = x\).
This rule works because it combines the operations of exponents and logarithms in a way that effectively "cancels out" their effects.
This rule works because it combines the operations of exponents and logarithms in a way that effectively "cancels out" their effects.
- The expression \(a^{\log_{a}(x)}\) read as "\(a\) raised to the power log base \(a\) of \(x\)," results in \(x\).
- This happens because logarithms answer the question, "To what power must the base \(a\) be raised, to produce \(x\)?"
Simplifying Expressions
Simplifying expressions involves reducing a mathematical statement to its simplest form. This process can make calculations easier and solutions more intuitive.
Key steps include:
Using such techniques not only helps in solving algebraic equations efficiently but also builds a sound foundation for advanced mathematics by focusing on understanding and applying core mathematical properties.
Key steps include:
- Identifying and applying relevant properties of operations, such as the power rule.
- Canceling terms that are opposites or inverses, like simplifying \(a^{\log_{a}(x)}\) to \(x\).
- Looking for patterns or standardized forms to use established shortcuts.
Using such techniques not only helps in solving algebraic equations efficiently but also builds a sound foundation for advanced mathematics by focusing on understanding and applying core mathematical properties.
Other exercises in this chapter
Problem 12
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Approximate with a calculator. Round your answer to four decimal places. $$e^{-\sqrt{2}}$$
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Write each logarithmic equation in its equivalent exponential form. $$1=\ln e$$
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