Problem 12
Question
(a) A particle of mass \(m\) constrained to lie in a given plane has a potential energy which is a function only of its distance \(r\) from a fixed point in the plane. Use the principle of least action to derive the equation $$ \phi=c_{1} \int \frac{d r}{\sqrt{r^{4}(E-V)-c_{1}^{2} r^{2}}} $$ of the particle's orbit, where \((r, \phi)\) are plane polar coordinates. (b) Apply part \((a)\) to the special case \(V=-\left(k^{2} / r\right) .\) Identify the orbit in each of the cases \(E>0, E=0, E<0\) (c) Solve the problem of part \((a)\), and subsequently that of part \((b)\), by the Hamilton-Jacobi method. SoLUTION: \(T=\frac{1}{2} m\left(\hat{r}^{2}+r^{2} \phi^{2}\right), p_{r}=m \dot{r}, p_{\phi}=m r^{2} \dot{\phi}\), $$ \begin{gathered} H=\left(\frac{1}{2 m}\right)\left[p_{r}^{2}+\left(\frac{p_{\phi}}{r}\right)^{2}\right]+V(r) \\ S^{*}=\alpha_{1} \phi+\int \sqrt{2 m(E-V)-\left(\frac{\alpha_{1}}{r}\right)^{2}} d r \end{gathered} $$ use the second of \((35)\) with \(i=1\)
Step-by-Step Solution
VerifiedKey Concepts
Principle of Least Action
The action, denoted as S, is a quantity that encapsulates the dynamics of the system and is defined as the integral over time of the Lagrangian, L, which itself is the difference between the kinetic and potential energies, T and V respectively. Mathematically, how the principle is applied can be expressed as:
\[ S = \int L \, dt \]
In the exercise given, the principle is utilized to derive an equation for the orbit of a particle in a plane, where the potential energy is a function of the distance from a fixed point. By finding where the action is stationary, we can determine the conditions that govern the behavior of the particle's motion within the plane.
Euler-Lagrange Equations
The general Euler-Lagrange equation for a variable q is given by:
\[ \frac{d}{dt}(\frac{\partial L}{\partial \dot{q}}) - \frac{\partial L}{\partial q} = 0 \]
Here, L is the Lagrangian, q is a generalized coordinate, and \(\dot{q}\) is the time derivative of q. In the example provided, by applying the Euler-Lagrange equation to the Lagrangian that incorporates kinetic and potential energies, we derive the equations that describe the motion of the particle when constrained to a plane, leading us to understand how the particle orbits in the given circumstances.
Hamilton-Jacobi Method
The key to this method is the Hamilton's principal function, S*, which can be thought of as an action that satisfies the Hamilton-Jacobi equation. For our exercise, S* takes on a specific form that involves integrals over the radial distance and depends on various constants and the potential energy function V(r).
By carefully manipulating this function, one can reduce the mechanics problem to solving a differential equation, the Hamilton-Jacobi equation. The provided solution shows this as an integral expression involving the energy E, potential V, and constants of integration, which when solved, yields the particle's trajectory in terms of its coordinates.
Particle Orbit in Plane Polar Coordinates
The equation derived from the principle of least action in the exercise pertains specifically to the trajectory of the particle in these coordinates. It relates the rate of change of the angular coordinate to the radial distance and hence encapsulates the essence of the particle's orbit. By solving the equation for different values of the energy E, we can discriminate between the types of orbits the particle might have—whether they are elliptical, parabolic, or hyperbolic trajectories—mirroring the solutions observed in celestial mechanics and orbital dynamics.