Problem 119
Question
Suppose the charge for repairing an automobile averages \(\$ 200\) with a standard deviation of \(\$ 16\). If a \(10 \%\) \(\operatorname{tax}\) is added to the charge and then a \(\$ 15\) flat fee for environmental impact, what is the standard deviation of the charge to the car owner?
Step-by-Step Solution
Verified Answer
The standard deviation of the charge to the car owner is \$ 17.6.
1Step 1: Identify the Variables
The charge for repairing an automobile averages \$200 with a standard deviation of \$16. Thus, we know the standard deviation of the current charge \$x\$ is \$16. In this case the tax is 10\% which can be represented as 0.1, and the flat fee for environmental impact is \$15.
2Step 2: Formulate the Function
The new charge will be the old charge plus 10\% of the old charge and a fixed \$15 environmental fee. This will give us the function: \(y = 1.1x + 15\).
3Step 3: Calculate the Standard Deviation
From the properties of variance, we know that the variance of a function of a random variable is the square of the multiplier times the original variance, and the standard deviation is the square root of the variance. Since the standard deviation of the original charge is \$16 and the multiplier is 1.1, the standard deviation of the new charge is: \( \sqrt{ (1.1)^2 \times (16)^2 } = 1.1 \times 16 = 17.6 \)
Key Concepts
VarianceRandom VariablesStatisticsMathematical Functions
Variance
Variance is a key concept in statistics that measures how much a set of numbers is spread out. It tells us how much the individual numbers in a data set differ from the mean (average) of the set. The larger the variance, the more spread out the numbers are.
When the cost is adjusted for tax and a fee, the variance changes based on the multiplier used in the function, affecting the new calculation.
- Variance is calculated as the average of the squared differences from the mean.
- It is represented mathematically as \( \sigma^2 \).
When the cost is adjusted for tax and a fee, the variance changes based on the multiplier used in the function, affecting the new calculation.
Random Variables
Random variables are variables whose possible values are numerical outcomes of a random phenomenon. In our context, the cost of automobile repair can be viewed as a random variable. The price varies depending on numerous factors, capturing the inherent uncertainty in repair costs.
- A random variable can be discrete or continuous, depending on whether it takes on fixed or any value in an interval, respectively.
- In statistics, we often deal with transformations of random variables, such as adding taxes or fees.
Statistics
Statistics is a discipline concerned with collecting, analyzing, interpreting, presenting, and organizing data. It uses methods to understand and interpret data sets and predict future trends.
- Descriptive statistics summarize basic features of data, like mean and variance.
- Inferential statistics make predictions or inferences about a population based on a sample.
Mathematical Functions
Mathematical functions describe relationships between quantities. In our scenario, a function is used to calculate the new charge for car repairs after tax and fees.
- A function \( f(x) \) maps input (\(x\)) to an output, often expressed algebraically.
- The function \( y = 1.1x + 15 \) specifies how each original charge (\(x\)) is transformed into a new charge (\(y\)), factoring in the multiplier for tax and the additive fee for environmental impact.
Other exercises in this chapter
Problem 117
Suppose that \(Y\) is an exponential random variable with \(\lambda=2\) (recall Question 3.6.11). Find \(P[Y>\) \(E(Y)+2 \sqrt{\operatorname{Var}(Y)}] .\)
View solution Problem 118
Let \(X\) be a random variable with finite mean \(\mu\). Define for every real number \(a, g(a)=E\left[(X-a)^{2}\right]\). Show that $$ g(a)=E\left[(X-\mu)^{2}\
View solution Problem 121
If \(E(W)=\mu\) and \(\operatorname{Var}(W)=\sigma^{2}\), show that \(E\left(\frac{W-\mu}{\sigma}\right)=0\) and \(\operatorname{Var}\left(\frac{W-\mu}{\sigma}\
View solution Problem 122
. Suppose \(U\) is a uniform random variable over \([0,1]\). (a) Show that \(Y=(b-a) U+a\) is uniform over \([a, b]\). (b) Use part (a) and Theorem \(3.6 .2\) t
View solution