Problem 119
Question
Students in a psychology class took a final examination. As part of an experiment to see how much of the course content they remembered over time, they took equivalent forms of the exam in monthly intervals thereafter. The average score for the group, \(f(t),\) after \(t\) months was modeled by the function $$f(t)=88-15 \ln (t+1), \quad 0 \leq t \leq 12$$ a. What was the average score on the original exam? b. What was the average score after 2 months? 4 months? 6 months? 8 months? 10 months? one year? c. Sketch the graph of \(f\) (either by hand or with a graphing utility). Describe what the graph indicates in terms of the material retained by the students.
Step-by-Step Solution
Verified Answer
a. Average score on original exam was 88. b. Average scores after 2,4,6,8,10 months and 1 year are approximately 70.79, 61.68, 56.59, 53.15, 50.31 and 48.05 respectively. The graph of function \(f(t)\) shows a decreasing trend implying that the students' recall ability of course content decreases over time due to the natural 'forgetting' curve.
1Step 1: Calculating Average Scores
a. The average score on the original exam is \(f(0) = 88 − 15 \ln(0 + 1) = 88 − 15 \ln(1) = 88− 0 = 88\). b. By substituting the appropriate values of \(t\) in the function \(f(t)\), the average scores at different intervals can be calculated: After 2 months: \(f(2) = 88 - 15 \ln(2+1) = approx 70.794\), After 4 months: \(f(4) = 88 - 15 \ln(4+1) = approx 61.685\), After 6 months: \(f(6) = 88 - 15 \ln(6+1) = approx 56.594\), After 8 months: \(f(8) = 88 - 15 \ln(8+1) = approx 53.15\), After 10 months: \(f(10) = 88 - 15 \ln(10+1) = approx 50.312\), After 1 year : \(f(12) = 88 - 15 \ln(12+1) = approx 48.059\)
2Step 2: Drawing the Graph and Infering Material Retention
c. The graph of the function should show a gradual decrease, as it indicates the average scores are decreasing over time. The graph indicates that the students' ability to recall course content decreases over time, which is natural, due to the 'Forgetting Curve'.
Key Concepts
Logarithmic FunctionExponential DecayAverage Score CalculationGraph Interpretation
Logarithmic Function
A logarithmic function is a mathematical relationship that uses a logarithm to model a variety of phenomena, particularly those related to growth or decay. In our exercise, the average score of students over time is modeled by a logarithmic function:\[ f(t) = 88 - 15 \ln(t+1) \]The logarithm in this function, specifically the natural logarithm denoted by \( \ln \), helps to capture the rate at which the students forget information.
- The constant 88 represents the starting score, when no time has passed.
- The term \(-15 \ln(t+1)\) models the rate of decrease in scores as time increases.
Exponential Decay
Exponential decay refers to a process where a quantity decreases at a rate proportional to its current value. This idea is subtly captured in our original exercise through the logarithmic function.Though not strictly an exponential decay, the average score function \(f(t)\) illustrates how the logarithmic function can model similar fluid processes with diminishing returns.
- The scores start high and decrease steadily.
- In this model, the scores decrease less sharply as time goes on, indicating a gradual retention loss.
Average Score Calculation
Average score calculation is central to analyzing the students' performance over time. By substituting different time values \(t\) into the function \(f(t)\), you can calculate the average score at various intervals.For example:
- For \(t=0\), the original score is \(f(0) = 88\).
- At \(t=2\) months, \(f(2) \approx 70.794\).
- At \(t=4\) months, \(f(4) \approx 61.685\).
Graph Interpretation
Graph interpretation is a fundamental skill to visualize and understand mathematical functions' meaning and implications in real-world contexts. For the function \(f(t)\), plotting on a graph provides a clear picture of the students' memory retention.
- The graph displays a downward curve, illustrating the "Forgetting Curve," where scores decrease over months.
- Initial retention drops are more dramatic, but tend to slowly flatten over time, demonstrating diminishing returns in the rate of score decrease.
Other exercises in this chapter
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