Problem 117
Question
Which of the following conditions may lead to a nonspontaneous change? (a) \(\Delta \mathrm{H}=-\mathrm{ve} ; \Delta \mathrm{S}=+\mathrm{ve}\) (b) \(\Delta \mathrm{H}=-\mathrm{ve} ; \Delta \mathrm{S}=-\mathrm{ve}\) (c) \(\Delta \mathrm{H}\) and \(\Delta \mathrm{S}\) are both \(+\mathrm{ve}\) (d) \(\Delta \mathrm{H}=+\mathrm{ve} ; \Delta \mathrm{S}=-\mathrm{ve}\)
Step-by-Step Solution
Verified Answer
Condition (d) leads to a nonspontaneous change.
1Step 1: Understand the Parameters
First, to determine the spontaneity of a reaction, we need to see how the Gibbs free energy change (G) is affected by the enthalpy change (H) and the entropy change (S). The formula is given by: \[\Delta G = \Delta H - T \Delta S\]where \(T\) is the temperature in Kelvin.
2Step 2: Analyzing Condition (a)
For condition (a):- \(\Delta H = -\text{ve}\) and \(\Delta S = +\text{ve}\) - Substituting these into the formula results in a negative \(\Delta G\), which typically means the process is spontaneous at all temperatures.
3Step 3: Analyzing Condition (b)
For condition (b):- \(\Delta H = -\text{ve}\) and \(\Delta S = -\text{ve}\) - Here, \(\Delta G = \Delta H - T \Delta S\) can be negative or positive depending on the size of \(T) \Delta S\) versus \(\Delta H\). It may be nonspontaneous at higher temperatures when \(T \Delta S\) is larger than \(\Delta H\).
4Step 4: Analyzing Condition (c)
For condition (c):- \(\Delta H = +\text{ve}\) and \(\Delta S = +\text{ve}\)- \(\Delta G\) can be negative when \(T \Delta S\) exceeds \(\Delta H\), typically spontaneous at high temperatures, but nonspontaneous at low temperatures.
5Step 5: Analyzing Condition (d)
For condition (d):- \(\Delta H = +\text{ve}\) and \(\Delta S = -\text{ve}\)- In this case, \(\Delta G\) will be positive as both terms contribute to a positive value, making it nonspontaneous at all temperatures.
6Step 6: Conclusion
The conditions in (d) inherently lead to a nonspontaneous change since both \(\Delta H\) is positive and \(\Delta S\) is negative, ensuring a positive \(\Delta G\) under all temperature conditions.
Key Concepts
Enthalpy ChangeEntropy ChangeSpontaneity of Reactions
Enthalpy Change
What is enthalpy change, and why is it important? Enthalpy change, symbolized as \( \Delta H \), refers to the heat absorbed or released during a chemical reaction at constant pressure. It's crucial for understanding how energy moves in and out of a system.
Key points to consider:
Understanding how \( \Delta H \) plays a role in Gibbs Free Energy equations helps determine the favorability of reactions. It works alongside entropy in the formula \( \Delta G = \Delta H - T \Delta S \).
Key points to consider:
- A negative \( \Delta H \) (exothermic) indicates heat is released, which can favor spontaneity.
- A positive \( \Delta H \) (endothermic) means heat is absorbed, often opposing spontaneity.
Understanding how \( \Delta H \) plays a role in Gibbs Free Energy equations helps determine the favorability of reactions. It works alongside entropy in the formula \( \Delta G = \Delta H - T \Delta S \).
Entropy Change
Entropy, symbolized as \( \Delta S \), measures the disorder or randomness in a system. Imagine your room. A messy room with clothes everywhere has high entropy, while a tidy room has low entropy.
Here's why it matters:
Entropy interacts with enthalpy in the Gibbs Free Energy equation to identify whether a reaction will happen by itself or not. It shows how changes in system organization affect the reaction's favorability.
Here's why it matters:
- If \( \Delta S \) is positive, the system becomes more disordered, often favoring spontaneity.
- If \( \Delta S \) is negative, the system becomes more ordered, which may not favor spontaneity.
Entropy interacts with enthalpy in the Gibbs Free Energy equation to identify whether a reaction will happen by itself or not. It shows how changes in system organization affect the reaction's favorability.
Spontaneity of Reactions
Spontaneity of reactions refers to a reaction's ability to occur without external intervention. The Gibbs Free Energy equation \( \Delta G = \Delta H - T \Delta S \) helps determine this.
Consider these:
It's a balancing act: enthalpy and entropy fight for favorability. This dynamic relationship elucidates why certain reactions spontaneously occur while others don't under specific conditions.
Consider these:
- A negative \( \Delta G \) means the reaction is spontaneous, proceeding on its own.
- A positive \( \Delta G \) indicates nonspontaneous reactions, needing energy input.
It's a balancing act: enthalpy and entropy fight for favorability. This dynamic relationship elucidates why certain reactions spontaneously occur while others don't under specific conditions.
Other exercises in this chapter
Problem 115
The dissociation energies of \(\mathrm{CH}_{4}\) and \(\mathrm{C}_{2} \mathrm{H}_{6}\) to convert them into gaseous atoms are 360 and \(620 \mathrm{kcal} \mathr
View solution Problem 116
Calculate \(\mathrm{Q}\) and \(\mathrm{W}\) for the isothermal reversible expansion of one mole of an ideal gas from an initial pressure of \(1.0\) bar to a fin
View solution Problem 118
Which of the following relations are correct? (a) \(\mathrm{H}=\mathrm{G}+\mathrm{TS}\) (b) \(\mathrm{E}=\mathrm{H}+\mathrm{PV}\) (c) \(\Delta \mathrm{E}=\mathr
View solution Problem 119
Which of the following is /are true about the isothermal expansion of an ideal gas? (a) \(\Delta \mathrm{U}=0\) (b) \(\Delta \mathrm{T}=0\) (c) \(\mathrm{q}=2.3
View solution