Problem 117
Question
The early Greeks believed that the most pleasing of all rectangles were golden rectangles, whose ratio of width to height is $$\frac{w}{h}=\frac{2}{\sqrt{5}-1}$$ (IMAGE CANT COPY) The Parthenon at Athens fits into a golden rectangle once the triangular pediment is reconstructed. Rationalize the denominator of the golden ratio. Then use a calculator and find the ratio of width to height, correct to the nearest hundredth, in golden rectangles.
Step-by-Step Solution
Verified Answer
So, the ratio of width to height in golden rectangles when the denominator is rationalized and calculated to the nearest hundredth is approximately 1.62.
1Step 1: Rationalize the denominator
To rationalize the denominator of the golden ratio \(\frac{2}{\sqrt{5}-1}\), multiply both the numerator and the denominator by the conjugate of the denominator, which is \(\sqrt{5}+1\). Remember, doing this does not change the value of the ratio, it just changes its form. This gives: \(\frac{2(\sqrt{5}+1)}{(\sqrt{5}-1)(\sqrt{5}+1)} = \frac{2\sqrt{5}+2}{5-1}\)
2Step 2: Simplify the expression
Simplify the right hand side to get: \( \frac{2\sqrt{5}+2}{4} = \frac{1}{2}(\sqrt{5}+1) \) which is the golden ratio with rationalized denominator.
3Step 3: Evaluate the ratio
Now, evaluate this ratio using a calculator. Set your calculator to the right mode, either degree or radian, according to its specification. Take special note of the decimal place to obtain the value to the nearest hundredth. This gives approximately 1.62.
Key Concepts
Rationalizing DenominatorsAlgebraic ExpressionsCalculator UseSimplifying Expressions
Rationalizing Denominators
Rationalizing the denominator of a fraction helps simplify expressions involving roots or radicals. When you have a denominator like \( \sqrt{5} - 1 \), its irrationality makes calculations awkward. To rationalize, multiply both the numerator and denominator by the conjugate of the denominator. For \( \sqrt{5} - 1 \), the conjugate is \( \sqrt{5} + 1 \). This uses the identity
- \((a - b)(a + b) = a^2 - b^2\).
- \( \frac{2}{\sqrt{5}-1} \times \frac{\sqrt{5}+1}{\sqrt{5}+1} = \frac{2(\sqrt{5}+1)}{(\sqrt{5})^2 - 1^2} \),
- which simplifies to \( \frac{2\sqrt{5} + 2}{4} \).
Algebraic Expressions
Algebraic expressions involve combining numbers with variables, often using operations like addition, subtraction, multiplication, and division. These expressions can include exponents, radicals, and constants altogether. When working on the golden ratio problem, we deal with the expression \( 2\sqrt{5} + 2 \).
- First, expressions are broken down using algebraic rules.
- Then they are combined to form a new expression, allowing for operations on it.
Calculator Use
Using a calculator effectively is vital for evaluating expressions accurately. When calculating the golden ratio to the nearest hundredth, input accuracy is essential:
- Ensure the calculator is in the correct mode, whether it be degree or radian, depending on the functions you'll use.
- Enter the expression carefully. For \( \frac{1}{2}(\sqrt{5}+1) \), key in each part ensuring you respect the operational hierarchy: calculate inside the square root first, then add, then multiply.
Simplifying Expressions
Simplifying mathematical expressions makes them easier to understand and work with. After rationalizing the denominator, proceed to simplify the resulting expression, \( \frac{2\sqrt{5} + 2}{4} \). This process involves:
- Breaking down the expression: separating terms.
- Combining like terms: simplifying \( \frac{2\sqrt{5} + 2}{4} \) as \( \frac{1}{2}(\sqrt{5} + 1) \).
Other exercises in this chapter
Problem 116
In each exercise, replace the boxed question mark with an integer that results in the given product. Some trial and error may be necessary. $$(x-?)(x-12)=x^{2}-
View solution Problem 116
Use the order of operations to simplify each expression. $$8-3[-2(5-7)-5(4-2)]$$
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In each exercise, replace the boxed question mark with an integer that results in the given product. Some trial and error may be necessary. $$(4 x+1)(2 x-?)=8 x
View solution Problem 117
Use the order of operations to simplify each expression. $$\frac{2(-2)-4(-3)}{5-8}$$
View solution