Problem 116
Question
Show that the distance between an object and its real image formed by a thin converging lens is always greater than or equal to four times the focal length of the lens.
Step-by-Step Solution
Verified Answer
Distance between object and image is always \( \geq 4f \) for real images.
1Step 1: Understanding Lens Formula
The lens formula is given by \( \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \), where \(f\) is the focal length of the lens, \(d_o\) is the object distance, and \(d_i\) is the image distance. A real image is formed when both \(d_o\) and \(d_i\) are positive.
2Step 2: Expressing Object and Image Distances
The distance between the object and its image is given by \(d = d_o + d_i\). This equation will be used to show that \(d \geq 4f\).
3Step 3: Deriving Inequality
Substitute the lens formula into the distance equation to express in terms of \(f\). Rearranging the lens formula gives \( d_o = \frac{fd_i}{d_i - f} \) and \( d_i = \frac{fd_o}{d_o - f} \). Substitute these into \( d = d_o + d_i \).
4Step 4: Substitute and Simplify
Substitute \(d_o\) and \(d_i\) into \(d = d_o + d_i\) to get:\[ d = \frac{fd_i}{d_i - f} + \frac{fd_o}{d_o - f} \].Simplify the expression and apply the constraint that both denominators must be positive, ensuring a real image is formed.
5Step 5: Applying Arithmetic Mean - Harmonic Mean Inequality
Apply the AM-HM inequality for the positive terms \( \frac{d_o}{f} \) and \( \frac{d_i}{f} \), implying \( \frac{d_o}{f} + \frac{d_i}{f} \geq 2 \sqrt{\frac{d_od_i}{f^2}} \). Given the lens formula, \(d_od_i = f(d_o + d_i) \), leading to at least \( 4f \), so \(d \geq 4f\).
6Step 6: Conclusion of Proof
We've shown that due to the AM-HM inequality and the lens formula, the distance \(d\) between the object and its image satisfies \(d \geq 4f\). This completes the proof.
Key Concepts
Lens FormulaReal ImageFocal LengthArithmetic Mean-Harmonic Mean Inequality
Lens Formula
The lens formula is a fundamental concept in optics that helps determine the relationship between the object distance, the image distance, and the focal length of a lens. The formula is represented as \( \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \), where:
- \( f \) is the focal length of the lens, indicating how strongly the lens converges light.
- \( d_o \) is the distance of the object from the lens.
- \( d_i \) is the distance of the real image from the lens.
Real Image
In the context of lenses, a real image is an image that is formed when light rays converge and actually pass through the image point. When dealing with converging lenses:
- A real image occurs when both the object and the image are on opposite sides of the lens.
- The image is inverted compared to the object.
- Real images can be exactly captured on a screen because the light physically converges at the location of the image.
Focal Length
The focal length \( f \) of a lens is a crucial parameter that defines its optical power. It tells us how strongly the lens can converge or diverge light rays. Here are some features of focal length:
- A shorter focal length means the lens is stronger, converging light more quickly.
- For converging lenses, the focal length is positive, indicating that the lens brings light to a focus.
- The focal length determines the size and position of the image formed by the lens.
Arithmetic Mean-Harmonic Mean Inequality
The arithmetic mean-harmonic mean (AM-HM) inequality is a mathematical concept used to relate different types of averages. In the proof mentioned, this inequality plays a key role:The AM-HM inequality states that for non-negative numbers \( a \) and \( b \), the following holds:\[\frac{a + b}{2} \geq \frac{2ab}{a + b}\]This inequality is applicable to the lens problem, with:
- \( a = \frac{d_o}{f} \) and \( b = \frac{d_i}{f} \).
- Substituting these values, it shows how the combined object and image distances relate to the focal length.
Other exercises in this chapter
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