Problem 116
Question
Identify the compound that exhibits tautomerism (a) 2 -butene (b) Lactic acid (c) 2-pentanone (d) Phenol
Step-by-Step Solution
Verified Answer
The compound 2-pentanone (c) exhibits tautomerism.
1Step 1: Identifying Tautomerism
Tautomerism is a form of isomerism where compounds exist in two forms that readily interconvert without breaking any bonds, commonly between keto and enol forms.
2Step 2: Analyzing 2-butene
2-butene is an alkene with a double bond between the second and third carbon atoms. It does not have the structural requirement of a hydrogen atom attached to a carbon adjacent to a carbonyl group, which is necessary for tautomerism.
3Step 3: Checking Lactic Acid
Lactic acid contains both a hydroxyl group (-OH) and a carbonyl group (C=O). However, the typical tautomeric shift requires an acidic hydrogen adjacent to a keto group (like in enolization), which lactic acid does not possess in the requisite structure for tautomerism.
4Step 4: Exploring 2-pentanone
2-pentanone is a ketone with the carbonyl group on the second carbon. It has hydrogen atoms on the carbon adjacent to the carbonyl group, allowing it to undergo keto-enol tautomerism.
5Step 5: Examining Phenol
Phenol contains a hydroxyl group bonded to an aromatic ring. While it can undergo keto-enol type transformations, they are not considered typical tautomerism as seen in keto-enol systems of aliphatic compounds, but rather resonance.
Key Concepts
Keto-Enol TautomerismOrganic Chemistry IsomerismStructural Requirements for Tautomerism
Keto-Enol Tautomerism
Keto-enol tautomerism is a specific type of tautomerism that involves the interconversion between a keto form and an enol form. These forms are structural isomers of each other. The keto form contains a carbonyl group \( (C=O) \) which is the characteristic functional group of ketones. Meanwhile, the enol form features an alcohol group \( (-OH) \) attached to a double-bonded carbon. Tautomerism between these forms involves the movement of a hydrogen atom and a shift in the position of a double bond.
The most well-known example of keto-enol tautomerism occurs in 2-pentanone, a ketone. In this compound:
The most well-known example of keto-enol tautomerism occurs in 2-pentanone, a ketone. In this compound:
- The carbonyl group at carbon-2 enables the compound to shift by moving an adjacent hydrogen atom, leading to the enol form.
- In the enol form, the former carbonyl oxygen now holds a hydrogen and the double bond shifts to between the carbonyl carbon and its adjacent carbon.
Organic Chemistry Isomerism
Isomerism in organic chemistry is the phenomenon where compounds have the same molecular formula but different structural or spatial arrangements. Tautomerism is a branch of structural isomerism involving the rearrangement of atoms within a molecule, leading to different possible forms.
Tautomerism fundamentally differs from other forms of isomerism such as geometric and optical isomerism:
Tautomerism fundamentally differs from other forms of isomerism such as geometric and optical isomerism:
- In geometric isomerism, different spatial arrangements occur due to restricted rotation around a double bond, like in 2-butene.
- Optical isomerism involves molecules that are mirror images of each other and affect the plane of polarized light.
Structural Requirements for Tautomerism
For a molecule to exhibit tautomerism, certain structural conditions must be met. These requirements ensure that atoms can rearrange to form different isomers, specifically tautomers.
In the case of keto-enol tautomerism:
In the case of keto-enol tautomerism:
- There must be a hydrogen atom attached to a carbon that is adjacent to a carbonyl group. This is crucial as this hydrogen moves to the oxygen in the enol form.
- This carbon is known as the alpha-carbon, and its hydrogen, the alpha-hydrogen, is mobile.
- The molecule should include a carbonyl group \( (C=O) \) that provides the site for keto to enol transformation through proton transfer.
Other exercises in this chapter
Problem 114
The number of stereoisomers possible for a compound of the molecular formula \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}(\mathrm{OH})-\mathrm{Me}\) is
View solution Problem 115
Out of the following, the alkene that exhibits optical isomerism is (a) 3-methyl-2pentene (b) 4 -methyl-1-pentene (c) 3-methyl-1-pentene (d) 2-methyl-2-pentene
View solution Problem 119
Match the columns: (p) Optically inactive compound (q) Optically active compound (r) Meso compound (s) Axis of symmetry present (t) Asymmetric compound
View solution Problem 128
\(\mu_{\mathrm{obs}}=\sum \mu_{\mathrm{i}} \mathrm{x}_{i} ;\) where \(\mu_{\mathrm{i}}\) is the dipole moment of stable conformer and \(\mathrm{x}_{\mathrm{i}}\
View solution