Problem 115
Question
You wish to determine the weight percent of copper in a copper-containing alloy. After dissolving a 0.251 -g sample of the alloy in acid, an excess of KI is added, and the \(\mathrm{Cu}^{2+}\) and \(\hat{\mathrm{I}}^{-}\) ions undergo the reaction $$ 2 \mathrm{Cu}^{2+}(\mathrm{aq})+5 \mathrm{I}^{-}(\mathrm{aq}) \longrightarrow 2 \mathrm{CuI}(\mathrm{s})+\mathrm{I}_{3}^{-}(\mathrm{aq}) $$ The liberated \(I_{3}^{-}\) is titrated with sodium thiosulfate according to the equation \(\mathrm{I}_{3}^{-}(\mathrm{aq})+2 \mathrm{S}_{2} \mathrm{O}_{3}^{2-}(\mathrm{aq}) \longrightarrow \mathrm{S}_{4} \mathrm{O}_{6}^{2-}(\mathrm{aq})+3 \mathrm{I}^{-}(\mathrm{aq})\) (a) Designate the oxidizing and reducing agents in the two reactions above. (b) If 26.32 mL. of \(0.101 \mathrm{M} \mathrm{Na}_{2} \mathrm{S}_{2} \mathrm{O}_{3}\) is required for titration to the equivalence point, what is the weight percent of Cu in \(0.251-\mathrm{g}\) sample of the alloy?
Step-by-Step Solution
VerifiedKey Concepts
Titration
In the given exercise, titration is used to measure the amount of copper in an alloy. The reaction involves sodium thiosulfate as the titrant, which reacts with triiodide (\( \mathrm{I}_{3}^{-} \)) produced from the initial reaction with copper ions. As the titrant is added, it reacts with the \( \mathrm{I}_{3}^{-} \), reducing it back to iodide ions, and thus marking the end-point when no \( \mathrm{I}_{3}^{-} \) remains. By measuring how much titrant is used, we can calculate the amount of copper present.
Oxidizing and Reducing Agents
In the first reaction with copper and iodide ions, \( \mathrm{Cu}^{2+} \) acts as the oxidizing agent because it gains electrons from iodide ions to form \( \mathrm{CuI} \). The iodide \( \mathrm{I}^{-} \) is the reducing agent as it loses electrons to form \( \mathrm{I}_{3}^{-} \).
In the subsequent titration reaction with sodium thiosulfate, \( \mathrm{I}_{3}^{-} \) serves as the oxidizing agent, and \( \mathrm{S}_{2} \mathrm{O}_{3}^{2-} \) is the reducing agent. The triiodide ion is reduced to iodide, while the thiosulfate is oxidized to tetrathionate. Recognizing the roles of these agents helps in understanding how electrons are transferred and facilitates the calculation of reactant quantities.
Weight Percent Calculation
For the copper-containing alloy, the weight percent of copper is determined through the reactions with iodide and thiosulfate. First, the moles of \( \mathrm{I}_{3}^{-} \) produced are calculated from the volume and concentration of sodium thiosulfate used in titration.
The stoichiometry of the reaction tells us that two moles of \( \mathrm{Cu}^{2+} \) produce one mole of \( \mathrm{I}_{3}^{-} \), allowing us to calculate the moles of copper in the sample. With the moles of copper and its molar mass (63.55 g/mol), we find the mass of copper in the sample. Using the formula: \[ \text{Weight percent of Cu} = \left( \frac{\text{Mass of Cu}}{\text{Total Mass}} \right) \times 100 \], we determine the weight percent of copper, providing a clear picture of its concentration in the alloy.