Problem 115
Question
The following problems involve addition, subtraction, and multiplication of radical expressions, as well as rationalizing the denominator. Perform the operations and simplify, if possible. All variables represent positive real numbers. $$ \sqrt[4]{3 n^{2}} \sqrt[4]{27 n^{3}} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \( 3n\sqrt[4]{n} \).
1Step 1: Apply the Product Property of Radicals
The product property of radicals states \( \sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{a \cdot b} \). Apply this to the given expression: \( \sqrt[4]{3n^2} \cdot \sqrt[4]{27n^3} = \sqrt[4]{3n^2 \cdot 27n^3} \).
2Step 2: Simplify the Inside of the Radicals
Multiply the terms inside the radical: \( 3n^2 \cdot 27n^3 = 81n^5 \). So, we have \( \sqrt[4]{81n^5} \).
3Step 3: Simplify Using Perfect Powers
Notice that \( 81 \) is \( 3^4 \), which is a perfect fourth power, and rewrite \( n^5 \) as \( n^4 \cdot n \). The expression becomes \( \sqrt[4]{3^4n^4n} \).
4Step 4: Take Out Perfect Powers
Using the property \( \sqrt[n]{a^n} = a \), extract the perfect powers: \( \sqrt[4]{3^4} = 3 \) and \( \sqrt[4]{n^4} = n \). Thus, \( \sqrt[4]{81n^5} = 3n\sqrt[4]{n} \).
5Step 5: Complete the Simplification
The simplified form of the expression \( \sqrt[4]{3n^2} \cdot \sqrt[4]{27n^3} \) is \( 3n\sqrt[4]{n} \).
Key Concepts
Product Property of RadicalsSimplification of RadicalsRationalizing the Denominator
Product Property of Radicals
When dealing with radicals in multiplication, the Product Property of Radicals is your best friend. This property allows you to multiply two radicals together by joining them under a common radical sign. If you have radicals with the same index, like square roots or fourth roots, you can combine them easily.
For instance, let's take two fourth roots:
For instance, let's take two fourth roots:
- \( \sqrt[4]{a} \)
- \( \sqrt[4]{b} \)
- \( \sqrt[4]{a} \cdot \sqrt[4]{b} = \sqrt[4]{a \cdot b} \)
Simplification of Radicals
Simplifying radicals involves reducing them to their simplest form, which often means removing any perfect powers from under the radical sign. This is done to make the expression cleaner and easier to work with.
Let's simplify \( \sqrt[4]{81n^5} \). First, notice the number under the radical:
Let's simplify \( \sqrt[4]{81n^5} \). First, notice the number under the radical:
- Identify perfect powers: \( 81 \) can be written as \( 3^4 \), and among \( n^5 \), \( n^4 \) is a perfect fourth power.
- Rewrite the expression: So, \( \sqrt[4]{81n^5} \) becomes \( \sqrt[4]{3^4n^4n} \).
- Extract perfect powers: Take out \( 3 \) and \( n \), giving \( 3n\sqrt[4]{n} \).
Rationalizing the Denominator
Rationalizing the denominator is a technique used to eliminate radicals from the bottom part of a fraction. While the given step-by-step does not involve a fraction, understanding this process is beneficial for broader exercises.
Whenever a radical appears in a denominator, the goal is to remove it, achieving a rational number. Here's a basic idea on how to do it:
Whenever a radical appears in a denominator, the goal is to remove it, achieving a rational number. Here's a basic idea on how to do it:
- Multiply by a conjugate: If you have a simple square root, multiply both the numerator and the denominator by that radical. This results in a rational number in the denominator.
- Extend to higher roots: For more complex roots, multiply by the appropriate power to get rid of the radical (e.g., if you have \( \sqrt[4]{a} \), multiply by \( \sqrt[4]{a^3} \) to make \( a \) appear).
Other exercises in this chapter
Problem 115
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