Problem 115
Question
Simplify. $$ \sqrt{\frac{96 p^{9}}{6 p}} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(4 p^4\).
1Step 1: Simplify the fraction inside the square root
First, simplify the fraction \(\frac{96 p^9}{6 p}\). Divide the coefficients and subtract the exponents of the same bases. \(\frac{96}{6} = 16\) and \(\frac{p^9}{p} = p^{8}\). The expression becomes \(\frac{96 p^9}{6 p} = 16 p^8\).
2Step 2: Apply the square root
Next, apply the square root to the simplified expression \(\frac{96 p^9}{6 p} = 16 p^8\). This means we need to find the square root of each term separately: \(\sqrt{16 p^8}\).
3Step 3: Simplify the square root
Simplify \(\sqrt{16 p^8}\). The square root of 16 is 4 because \(\sqrt{16} = 4\), and the square root of \(\ p^8 \) is \(\ p^4 \) because \(\sqrt{p^8} = p^4\). Therefore, \(\sqrt{16 p^8} = 4 p^4\).
Key Concepts
Square RootsFraction SimplificationExponent Rules
Square Roots
Square roots are numbers that produce a specified quantity when multiplied by themselves. They are denoted using the radical symbol (\sqrt{}). For any positive number \(a\), the principal square root is \(\sqrt{a}\) which means finding a number \(b\) such that \(b^2 = a\).
When applying square roots to expressions, it's necessary to handle each component individually. For instance, the square root of a product is the product of the square roots. For \(\sqrt{16 p^8}\), the square root of 16 is 4 because 4 \times 4 = 16.
Similarly, for \(p^8\), since \(p^8\) is equivalent to \(p^4 \times p^4\), the square root is \(p^4\). Combining these results gives us \(\sqrt{16 p^8} = 4 p^4\).
When applying square roots to expressions, it's necessary to handle each component individually. For instance, the square root of a product is the product of the square roots. For \(\sqrt{16 p^8}\), the square root of 16 is 4 because 4 \times 4 = 16.
Similarly, for \(p^8\), since \(p^8\) is equivalent to \(p^4 \times p^4\), the square root is \(p^4\). Combining these results gives us \(\sqrt{16 p^8} = 4 p^4\).
Fraction Simplification
Fraction simplification involves reducing fractions to their simplest form. Start by simplifying each part of the fraction. Take \(\frac{96 p^9}{6 p}\); both numerator and denominator share common factors. Divide 96 by 6 to get 16. Next, simplify \(p^9 \div p\). Using exponent rules (subtracting exponents with the same base), we get \(p^{9-1} = p^8\).
The fraction then simplifies to \(\frac{16 p^8}{1} = 16 p^8\). This earlier simplification makes applying further operations like square roots straightforward and quicker.
The fraction then simplifies to \(\frac{16 p^8}{1} = 16 p^8\). This earlier simplification makes applying further operations like square roots straightforward and quicker.
Exponent Rules
Exponent rules are essential for simplifying expressions with powers. Here's a quick overview of some essential rules:
In this problem, \(\frac{p^9}{p} = p^{9-1} = p^8\), exemplifies the quotient of powers rule. This enables simplifying complex fractional exponents effortlessly. By understanding and applying these rules, students can tackle sophisticated algebraic expressions with confidence.
- Product of Powers: \(a^m \times a^n = a^{m+n}\)
- Quotient of Powers: \(\frac{a^m}{a^n} = a^{m-n}\)
- Power of a Power: \( (a^m)^n = a^{m \times n}\)
In this problem, \(\frac{p^9}{p} = p^{9-1} = p^8\), exemplifies the quotient of powers rule. This enables simplifying complex fractional exponents effortlessly. By understanding and applying these rules, students can tackle sophisticated algebraic expressions with confidence.
Other exercises in this chapter
Problem 113
Simplify. $$ \sqrt{\frac{200 x^{7}}{2 x^{3}}} $$
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Simplify. $$ \sqrt{\frac{98 y^{11}}{2 y^{5}}} $$
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Simplify. $$ \sqrt{\frac{108 q^{10}}{3 q^{2}}} $$
View solution Problem 117
Simplify. $$ \sqrt{\frac{36}{35}} $$
View solution