Problem 115
Question
Show \(\overline{z w}=\bar{z} \bar{w}\).
Step-by-Step Solution
Verified Answer
The conjugate of a product equals the product of the conjugates: \(\overline{z w} = \overline{z} \overline{w}\).
1Step 1: Understand Complex Conjugates
To solve this, first recall the definition of the complex conjugate. If we have a complex number \(z = a + bi\), where \(a\) and \(b\) are real numbers and \(i\) is the imaginary unit, the complex conjugate \(\overline{z}\) is \(a - bi\). Similarly, for another complex number \(w = c + di\), its conjugate \(\overline{w} = c - di\).
2Step 2: Multiply the Complex Numbers
Next, multiply the complex numbers \(z\) and \(w\). If \(z = a + bi\) and \(w = c + di\), then \(zw = (a + bi)(c + di) = ac + adi + bci + bdi^2 = (ac - bd) + (ad + bc)i\), using \(i^2 = -1\).
3Step 3: Conjugate the Product
Take the conjugate of the product \(zw = (ac - bd) + (ad + bc)i\). The conjugate is \(\overline{zw} = (ac - bd) - (ad + bc)i\).
4Step 4: Multiply the Conjugates Individually
Now, multiply the conjugates \(\overline{z}\) and \(\overline{w}\). We have \(\overline{z} = a - bi\) and \(\overline{w} = c - di\), so \(\overline{z} \cdot \overline{w} = (a - bi)(c - di) = ac - adi - bci + bdi^2 = (ac - bd) - (ad + bc)i\). Again, use \(i^2 = -1\).
5Step 5: Compare the Results
Notice that in Step 3, the conjugate of the product is \((ac - bd) - (ad + bc)i\). In Step 4, the product of the conjugates is also \((ac - bd) - (ad + bc)i\). Therefore, the two expressions are equal: \(\overline{zw} = \overline{z} \cdot \overline{w}\).
Key Concepts
Understanding Complex NumbersThe Properties of Complex ConjugationMultiplication of Complex Numbers and Conjugation
Understanding Complex Numbers
Complex numbers are like a two-in-one combo, featuring both a real part and an imaginary part. Imagine them as ordered pairs composed of a real number and an imaginary number formulated with the imaginary unit, denoted by \( i \), where \( i^2 = -1 \). The basic format is \( z = a + bi \), where:
This forms a complex number into a point or a vector-like form in the coordinate grid, adding a useful level of abstraction and power to the number system suitable for various mathematical problems.
- \( a \) is the real part
- \( b \) is the imaginary part. It is crucial to remember that the imaginary component involves the unit \( i \)
This forms a complex number into a point or a vector-like form in the coordinate grid, adding a useful level of abstraction and power to the number system suitable for various mathematical problems.
The Properties of Complex Conjugation
Complex conjugation is a fascinating property that attaches a reflective nature to complex numbers. If you imagine a complex number \( z = a + bi \), its complex conjugate is \( \overline{z} = a - bi \).
To better understand, imagine reflecting the complex number across the real axis of the complex plane.
The imaginary part flips its sign, while the real part stays untouched.
No imaginary component due to how conjugation neutralizes the imaginary unit. Hence a helpful tool in various calculations.
To better understand, imagine reflecting the complex number across the real axis of the complex plane.
The imaginary part flips its sign, while the real part stays untouched.
- This operation is valuable in simplifying complex expressions
- It assists in solving equations where complex numbers are involved
No imaginary component due to how conjugation neutralizes the imaginary unit. Hence a helpful tool in various calculations.
Multiplication of Complex Numbers and Conjugation
Multiplication of complex numbers can initially seem a bit challenging, but it's a logical extension of the distributive property.
For two complex numbers, \( z = a + bi \) and \( w = c + di \), the product \( zw \) is obtained as follows: \[ zw = (a + bi)(c + di) = ac + adi + bci + bdi^2 \]
Remember, since \( i^2 = -1 \), the expression transforms to:
\( zw = (ac - bd) + (ad + bc)i \).
A captivating aspect is how multiplication and conjugation relate.
For two complex numbers, \( z = a + bi \) and \( w = c + di \), the product \( zw \) is obtained as follows: \[ zw = (a + bi)(c + di) = ac + adi + bci + bdi^2 \]
Remember, since \( i^2 = -1 \), the expression transforms to:
\( zw = (ac - bd) + (ad + bc)i \).
A captivating aspect is how multiplication and conjugation relate.
- Taking the conjugate of a product is the same as multiplying the conjugates individually
- This is expressed by \( \overline{zw} = \overline{z} \cdot \overline{w} \)
Other exercises in this chapter
Problem 114
Daphnia is a genus of zooplankton that comprises a number of species. The body growth rate of Daphnia depends on food concentration. A minimum food concentratio
View solution Problem 114
Show \(\overline{z+w}=\bar{z}+\bar{w}\)
View solution Problem 113
Show \(\overline{(\bar{z})}=z\)
View solution