Problem 115
Question
In the following sequence of reactions. Identify (C) here? \(\mathrm{FeCO}_{3} \stackrel{\text { Heat in air }}{\longrightarrow}(\mathrm{A}) \stackrel{\text { Boil with } \mathrm{HCl}}{\longrightarrow}(\mathrm{B}) \stackrel{\mathrm{K}_{\mathrm{Fe}}(\mathrm{CN})_{6}}{\longrightarrow}(\mathrm{C})\) (a) \(\mathrm{K}_{3} \mathrm{Fe}(\mathrm{CN})_{6}\) (b) \(\mathrm{Fe}(\mathrm{CNS})_{3}\) (c) \(\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}\) (d) Both (b) and (c)
Step-by-Step Solution
Verified Answer
The compound (C) is \(\mathrm{Fe}_{4}[\mathrm{Fe}(\mathrm{CN})_{6}]_{3}\), option (c).
1Step 1: Identify Compound A
The first reaction involves heating iron(II) carbonate (\(\mathrm{FeCO}_{3}\)) in air. Heating in air typically results in the decomposition of metal carbonates into metal oxides. Therefore, \(\mathrm{FeCO}_{3}\) when heated in air forms iron(II) oxide (\(\mathrm{FeO}\)) and carbon dioxide. Thus, compound (A) is \(\mathrm{FeO}\).
2Step 2: Identify Compound B
Next, compound (A), which is \(\mathrm{FeO}\), is boiled with hydrochloric acid (HCl). Metal oxides react with acids to form salt and water. Thus, \(\mathrm{FeO}\) reacts with \(\mathrm{HCl}\) to form iron(II) chloride \(\mathrm{FeCl}_2\) and water. Therefore, compound (B) is \(\mathrm{FeCl}_2\).
3Step 3: Identify Compound C
The last step involves treating compound (B), \(\mathrm{FeCl}_2\), with potassium ferricyanide \(\mathrm{K}_3\mathrm{Fe}(\mathrm{CN})_6\). Iron(II) ions react with ferricyanide anions to form a complex salt known as Prussian blue, which is \(\mathrm{Fe}_4[\mathrm{Fe}(\mathrm{CN})_6]_3\). Thus, compound (C) is \(\mathrm{Fe}_4[\mathrm{Fe}(\mathrm{CN})_6]_3\).
Key Concepts
Metal Carbonate DecompositionComplex Ion FormationSalt Formation Reaction
Metal Carbonate Decomposition
Metal carbonate decomposition is a key chemical reaction that involves the breakdown of metal carbonates into metal oxides and carbon dioxide when heated. This process often requires heat because the energy input helps to break the bonds in the carbonate compounds.
When iron(II) carbonate, \( \mathrm{FeCO}_{3} \), is heated in air, it undergoes decomposition to form iron(II) oxide, \( \mathrm{FeO} \), and releases carbon dioxide gas, \( \mathrm{CO}_2 \). This can be represented as:
Additionally, recognizing metal carbonate decomposition reactions is essential for predicting how different compounds behave under certain conditions, like heating.
When iron(II) carbonate, \( \mathrm{FeCO}_{3} \), is heated in air, it undergoes decomposition to form iron(II) oxide, \( \mathrm{FeO} \), and releases carbon dioxide gas, \( \mathrm{CO}_2 \). This can be represented as:
- \( \mathrm{FeCO}_{3} \rightarrow \mathrm{FeO} + \mathrm{CO}_{2} \)
Additionally, recognizing metal carbonate decomposition reactions is essential for predicting how different compounds behave under certain conditions, like heating.
Complex Ion Formation
Complex ion formation is a fascinating area in chemistry where metal ions bond with other molecules or ions to form complex compounds. These complexes consist of a central metal ion surrounded by organic or inorganic ligands. This process is crucial in the study of coordination chemistry.
In our example, the compound \( \mathrm{FeCl}_2 \), which is the intermediate product, reacts with potassium ferricyanide \( \mathrm{K}_3\mathrm{Fe}(\mathrm{CN})_6 \). This reaction leads to the formation of a complex ion known as Prussian blue, \( \mathrm{Fe}_4[\mathrm{Fe}(\mathrm{CN})_6]_3 \). Here:
In our example, the compound \( \mathrm{FeCl}_2 \), which is the intermediate product, reacts with potassium ferricyanide \( \mathrm{K}_3\mathrm{Fe}(\mathrm{CN})_6 \). This reaction leads to the formation of a complex ion known as Prussian blue, \( \mathrm{Fe}_4[\mathrm{Fe}(\mathrm{CN})_6]_3 \). Here:
- Iron(II) ions in \( \mathrm{FeCl}_2 \) interact with ferricyanide anions to form an intricate network of atoms.
- This forms the iconic blue complex, commonly utilized in pigments and analytical chemistry due to its distinct color.
Salt Formation Reaction
Salt formation is a chemical process where acids react with bases, resulting in salt and often water. A classic example is the reaction between metal oxides or hydroxides and acids.
In the given sequence, the iron(II) oxide \( \mathrm{FeO} \) from the decomposition reaction then reacts with hydrochloric acid \( \mathrm{HCl} \) to form iron(II) chloride \( \mathrm{FeCl}_2 \) and water. This can be illustrated as follows:
The ability to predict the products of salt formation reactions is key to controlling chemical processes, developing new compounds, and understanding the behavior of reactants under different conditions. Salt formation reactions like this are basic yet crucial for students to master in chemistry.
In the given sequence, the iron(II) oxide \( \mathrm{FeO} \) from the decomposition reaction then reacts with hydrochloric acid \( \mathrm{HCl} \) to form iron(II) chloride \( \mathrm{FeCl}_2 \) and water. This can be illustrated as follows:
- \( \mathrm{FeO} + 2 \mathrm{HCl} \rightarrow \mathrm{FeCl}_2 + \mathrm{H}_2\mathrm{O} \)
The ability to predict the products of salt formation reactions is key to controlling chemical processes, developing new compounds, and understanding the behavior of reactants under different conditions. Salt formation reactions like this are basic yet crucial for students to master in chemistry.
Other exercises in this chapter
Problem 113
Which of the following compounds is expected to be coloured? (a) \(\mathrm{Ag}, \mathrm{SO}_{4}\) (b) \(\mathrm{CuF}_{2}\) (c) \(\mathrm{MgF}_{2}\) (d) \(\mathr
View solution Problem 114
When \(\mathrm{Zn}\) metal is added to \(\mathrm{CuSO}_{4}\) solution, \(\mathrm{Cu}\) is precipitated it is due to (a) ionization of \(\mathrm{CuSO}_{4}\) (b)
View solution Problem 116
\(\mathrm{CuSO}_{4}\) decolourize on addition of \(\mathrm{KCN}\), the product is (a) \(\left[\mathrm{Cu}(\mathrm{CN})_{4}\right]^{2}\) (b) \(\mathrm{Cu}^{2+}\)
View solution Problem 117
Froth floatation process may be used to increase the concentration of the mineral in (a) chalcopyrites (b) bauxite (c) haematite (d) calamine
View solution