Problem 115
Question
If equilibrium constant for the reaction, \(\mathrm{XO}^{-}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(1) \rightleftharpoons \mathrm{HXO}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})\) is \(0.36 \times 10^{-6}\) then find the value of dissociation constant \(\left(\mathrm{K}_{2}\right)\) for \(\mathrm{HXO} ?\) (a) \(0.36 \times 10^{-8}\) (b) \(2.8 \times 10^{-8}\) (c) \(2.8 \times 10^{-10}\) (d) \(0.36 \times 10^{-6}\)
Step-by-Step Solution
Verified Answer
The dissociation constant \( K_2 \) for \( \mathrm{HXO} \) is approximately \( 2.8 \times 10^{-8} \).
1Step 1: Identify the given equilibrium constant
In the reaction \( \mathrm{XO}^{-} + \mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{HXO} + \mathrm{OH}^{-} \), we are given the equilibrium constant \( K = 0.36 \times 10^{-6} \). This constant is for the equilibrium involving the base \( \mathrm{XO}^{-} \).
2Step 2: Understand the relationship between equilibrium constants
The equilibrium constant for the base reaction \( K_b = K_{eq} = 0.36 \times 10^{-6} \). The relationship between \( K_a \) of the acid \( \mathrm{HXO} \) and \( K_b \) of the base \( \mathrm{XO}^{-} \) is given by \( K_w = K_a \cdot K_b \), where \( K_w \) is the ion-product constant of water \( 1.0 \times 10^{-14} \).
3Step 3: Calculate the dissociation constant \( K_2 \)
To find \( K_2 \) for \( \mathrm{HXO} \), use the equation \( K_2 = \frac{K_w}{K_b} \). Substituting the known values: \[ K_2 = \frac{1.0 \times 10^{-14}}{0.36 \times 10^{-6}} = 2.778 \times 10^{-8} \].
4Step 4: Choose the closest answer
From the calculation in step 3, \( K_2 \approx 2.78 \times 10^{-8} \). The closest option to this value is (b) \( 2.8 \times 10^{-8} \).
Key Concepts
Dissociation ConstantBase Ionization ConstantWater Ion-Product Constant
Dissociation Constant
The dissociation constant, often referred to in formulas as \( K_a \), is a crucial concept in acid-base chemistry. It measures the strength of an acid in solution.
When an acid dissolves in water, it disassociates into its constituent ions. The dissociation constant quantifies this process, providing insight into how completely an acid dissociates into its ions.
When an acid dissolves in water, it disassociates into its constituent ions. The dissociation constant quantifies this process, providing insight into how completely an acid dissociates into its ions.
- For strong acids, \( K_a \) is large because they dissociate almost entirely.
- For weak acids, \( K_a \) is smaller, indicating partial dissociation.
Base Ionization Constant
The base ionization constant, or \( K_b \), is similarly important but applies to bases instead of acids. It measures the extent to which a base dissociates in water to form hydroxide ions \( \text{OH}^- \).
This constant plays a vital role in understanding the basicity of a compound and thus its ability to accept protons.
This constant plays a vital role in understanding the basicity of a compound and thus its ability to accept protons.
- Bases with a high \( K_b \) are considered strong bases because they robustly form hydroxide ions.
- Bases with lower \( K_b \) values are identified as weak bases.
- In this exercise, the base \( \mathrm{XO}^- \) has an ionization constant \( K_b \) equal to \( 0.36 \times 10^{-6} \). This is essential for determining the acidic nature of the complementary acid \( \mathrm{HXO} \) by using its relationship with \( K_a \) and the water ion-product constant \( K_w \).
Water Ion-Product Constant
The water ion-product constant, \( K_w \), is a foundational constant in the study of aqueous solutions. It represents the autoionization of water, which is an equilibrium process where water partially ionizes into hydrogen and hydroxide ions.
In our problem, \( K_w \) is used to calculate the dissociation constant \( K_2 \) for \( \mathrm{HXO} \) with the base ionization constant \( K_b \) of \( \mathrm{XO}^- \), offering insights into the strength and behavior of these chemical species.
- \( K_w \) at 25°C is approximately \( 1.0 \times 10^{-14} \).
In our problem, \( K_w \) is used to calculate the dissociation constant \( K_2 \) for \( \mathrm{HXO} \) with the base ionization constant \( K_b \) of \( \mathrm{XO}^- \), offering insights into the strength and behavior of these chemical species.
Other exercises in this chapter
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