Problem 115
Question
Furry Finances. A pet insurance policy has a monthly rate that is a function of the age of the insured dog or cat. For pets whose age does not exceed \(4,\) the monthly cost is \(\$ 20 .\) The cost then increases by \(\$ 2\) for each successive year of the pet's age. $$\begin{array}{cc} \text { Age Not Exceeding } & \text { Monthly cost } \\ \hline 4 & \$ 20 \\ 5 & \$ 22 \\ 6 & \$ 24 \end{array}$$ The cost schedule continues in this manner for ages not exceeding \(10 .\) The cost for pets whose ages exceed 10 is \(\$ 40 .\) Use this information to create a graph that shows the monthly cost of the insurance, \(f(x),\) for a pet of age \(x,\) where the function's domain is [0,14]
Step-by-Step Solution
Verified Answer
The function would be defined as follows: \(f(x) = 20\) for \(0 \leq x \leq 4\), \(f(x) = 20 + 2(x - 4)\) for \(4 < x \leq 10\) and \(f(x) = 40\) for \(10 < x \leq 14\). The graph will be piecewise linear with jump discontinuities at x=4, x=10 and x=11.
1Step 1: Define Function for Ages 0 to 4
For a pet whose age x does not exceed 4, the monthly cost of the insurance is a constant and it is $20. This can be written as \(f(x) = 20\) for \(0 \leq x \leq 4\).
2Step 2: Define Function for Ages 5 to 10
For a pet with age x between 5 and 10, the monthly cost of the insurance increases with each year by $2, so the cost at age x is the cost at age 4 plus $2 for each extra year. This can be written as \(f(x) = 20 + 2(x - 4)\) for \(4 < x \leq 10\) .
3Step 3: Define Function for Ages Exceeding 10
For a pet with age x exceeding 10, the monthly cost of the insurance is $40. This can be written as \(f(x) = 40\) for \(10 < x \leq 14\).
4Step 4: Graphing the Function
Plot these three function definitions on the interval [0, 14]. Draw a filled dot at the points (4,20), (5,22), (10,30) and (11,40) because these values are included, while for x=4, x=10 and x=11 draw empty dots at the ends of the other function definitions to indicate exclusiveness.
Key Concepts
Domain and RangeFunction NotationGraphing Functions
Domain and Range
When dealing with piecewise functions like in the pet insurance problem, understanding the domain and range is crucial. The **domain** refers to all the allowable input values for the function, in this case, the ages of the pets. Here, the domain is
- [0, 14], means a pet can be between 0 and 14 years old.
- 20, 22, 24, ..., 30, and 40.
- From 0 to 4 years, the cost is 20, so the range at this interval is just one value: 20.
- From over 4 to 10 years, the cost increases by 2 for each year over 4 until it reaches 30, making the range 20, 22, 24, ..., 30.
- Finally, for pets older than 10 up to 14, the cost is fixed at 40, thus only 40 is included here in the range.
Function Notation
Function notation offers a way to express relationships between inputs and outputs succinctly. This problem involves a function denoted by
- \( f(x) \).
- For ages 0 to 4, the function is constant: \( f(x) = 20 \).
- For ages 5 to 10, the increment function takes over, growing linerally: \( f(x) = 20 + 2(x - 4) \). This indicates the base cost plus an additional \( 2(x - 4) \) for each year beyond four.
- For ages over 10, simplicity returns with \( f(x) = 40 \), a fixed cost for older pets.
Graphing Functions
Graphing functions provides a visual insight into how piecewise functions operate. Here, you need to create a piecewise graph that clearly shows different segments of ages and costs. Here's a step-by-step example of graphing:
- Start with the first segment, where \( f(x) = 20 \) from ages 0 to 4. This is a horizontal line at 20.
- Next, from ages 5 to 10, plot the increasing function \( f(x) = 20 + 2(x - 4) \). This line begins at 22 and increases until it reaches 30 at age 10.
- Lastly, plot the constant line \( f(x) = 40 \) for ages over 10 up to 14, representing the flat rate for older pets.
Other exercises in this chapter
Problem 114
Explain how the vertical line test is used to determine whether a graph represents a function.
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Begin by graphing the cube root function, \(f(x)=\sqrt[3]{x} .\) Then use transformations of this graph to graph the given function. $$r(x)=\frac{1}{2} \sqrt[3]
View solution Problem 115
Explain how to identify the domain and range of a function from its graph.
View solution Problem 115
Prove that the equation of a line passing through \((a, 0)\) and \((0, b)(a \neq 0, b \neq 0)\) can be written in the form \(\frac{x}{a}+\frac{y}{b}=1\) Why is
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