Problem 115
Question
Find the indicated partial sum of the series. \(\sum_{n=1}^{\infty} 4\left(-\frac{1}{2}\right)^{n}\) Third partial sum
Step-by-Step Solution
Verified Answer
The third partial sum (S3) of the given geometric series is 4.66667 or approximately \( \frac{14}{3} \).
1Step 1: Identify the series terms and common ratio
In this series, the first term 'a' is clearly 4 and the common ratio 'r' is \(-\frac{1}{2}\). So, we are trying to find the sum of the first three terms of the series 4, -2, and 1.
2Step 2: Use partial sum formula
To find the sum of the first three terms (n=3), we use the formula for the sum of the first 'n' terms of a geometric series, which is \( S_n = a (1 - r^n) / (1 - r) \). Substituting the identified values into the formula gives us \( S_3 = 4 * (1 - (-\frac{1}{2})^3) / {1 - (-\frac{1}{2})} \).
3Step 3: Solve for S3
Solving the equation gives us the third partial sum, S3. Perform the computations within the parentheses first, according to the order of operations (BIDMAS/BODMAS/PEDMAS rule), then proceed to the division. The result is the required third partial sum.
Other exercises in this chapter
Problem 114
Find the indicated partial sum of the series. \(\sum_{i=1}^{\infty} \frac{2}{3^{i}}\) Fifth partial sum
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Consider \(n\) independent trials of an experiment in which each trial has two possible outcomes, success or failure. The probability of a success on each trial
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Consider \(n\) independent trials of an experiment in which each trial has two possible outcomes, success or failure. The probability of a success on each trial
View solution Problem 116
Find the indicated partial sum of the series. \(\sum_{n=1}^{\infty} 8\left(-\frac{1}{4}\right)^{n}\) Fourth partial sum
View solution