Problem 115
Question
Balance Precision A sensitive electronic balance can detect masses of \(1 \times 10^{-8}\) g. How many atoms of silver would be in a sample having this mass?
Step-by-Step Solution
Verified Answer
The sample contains approximately \(5.585 \times 10^{13}\) silver atoms.
1Step 1: Determine the mass of one silver atom
First, we need to find the mass of one silver atom. The atomic mass of silver (Ag) is approximately 107.87 amu (atomic mass units). To convert this into grams, note that 1 amu is equal to \(1.66053906660 \times 10^{-24}\) grams. Therefore, the mass of one silver atom is \(107.87 \times 1.66053906660 \times 10^{-24}\) g.
2Step 2: Calculate the mass of one silver atom in grams
Multiply the atomic mass of silver by the conversion factor: \(107.87 \times 1.66053906660 \times 10^{-24} = 1.79031 \times 10^{-22}\) grams. This is the mass of a single silver atom.
3Step 3: Calculate the number of silver atoms in the given mass
To find out how many atoms of silver are in a mass of \(1 \times 10^{-8}\) g, divide the mass of the sample by the mass of one silver atom: \( \frac{1 \times 10^{-8}}{1.79031 \times 10^{-22}} \approx 5.585 \times 10^{13}\) atoms.
Key Concepts
Grams to AMU ConversionAtomic Mass UnitMass of a Silver Atom
Grams to AMU Conversion
Understanding how to convert grams into atomic mass units (amu) is crucial in chemistry. The atomic mass unit is a smaller unit, better suited for expressing the minuscule masses of atoms and subatomic particles. One amu is defined as
For instance, if we know the atomic mass of silver (107.87 amu), we can convert it to grams by multiplying with the conversion factor. Hence, the process helps us contextualize atomic masses into the macroscopic world where grams are the common standard of measuring mass.
- \(1.66053906660 \times 10^{-24}\) grams.
For instance, if we know the atomic mass of silver (107.87 amu), we can convert it to grams by multiplying with the conversion factor. Hence, the process helps us contextualize atomic masses into the macroscopic world where grams are the common standard of measuring mass.
Atomic Mass Unit
The atomic mass unit (amu) is a fundamental concept in understanding atomic mass.
It represents the relative mass of atoms compared to a reference atom, which is carbon-12. For convenience,
Instead of expressing atomic masses in grams, which would be impractically small, chemists use amus to describe the mass of an atom.
It represents the relative mass of atoms compared to a reference atom, which is carbon-12. For convenience,
- one amu is defined as exactly \( \frac{1}{12} \) of the mass of one carbon-12 atom.
Instead of expressing atomic masses in grams, which would be impractically small, chemists use amus to describe the mass of an atom.
- Atomic masses in the periodic table, like silver's 107.87 amu, reflect this unit.
Mass of a Silver Atom
Knowing the mass of a silver atom can highlight the atomic scale and underscore why atomic mass units are essential.
Silver, with the chemical symbol Ag, has an atomic mass of 107.87 amu. By converting this atomic mass into grams, we can find the mass of a single silver atom.
The calculation uses the conversion factor
Such conversions allow scientists to relate atomic scale phenomena to macroscopic measurements, permitting insights into samples used in experiments that typical balances can measure, like the example given of a balance detecting masses in the order of \(10^{-8}\) grams.
Silver, with the chemical symbol Ag, has an atomic mass of 107.87 amu. By converting this atomic mass into grams, we can find the mass of a single silver atom.
The calculation uses the conversion factor
- \(107.87 \times 1.66053906660 \times 10^{-24} = 1.79031 \times 10^{-22}\) grams.
Such conversions allow scientists to relate atomic scale phenomena to macroscopic measurements, permitting insights into samples used in experiments that typical balances can measure, like the example given of a balance detecting masses in the order of \(10^{-8}\) grams.
Other exercises in this chapter
Problem 112
Convert each to mass in grams. \begin{equation}\begin{array}{l}{\text { a. } 4.22 \times 10^{15} \text { atoms } \mathrm{U}} \\ {\text { b. } 8.65 \times 10^{25
View solution Problem 114
Arrange from least to most in moles: \(3.00 \times 10^{24}\) atoms Ne, 4.25 mole \(\mathrm{Ar}, 2.69 \times 10^{24}\) atoms \(\mathrm{Xe}, 65.96 \mathrm{g} \mat
View solution Problem 116
A sample of a compound contains 3.86 g of sulfur and 4.08 g of vanadium. How many atoms of sulfur and vanadium does the compound contain?
View solution Problem 117
Which has more atoms, 10.0 g of C or 10.0 g of Ca? How many atoms does each have?
View solution