Problem 114
Question
Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. Every decimal with a repeating pattern of digits is a rational number.
Step-by-Step Solution
Verified Answer
The statement is True. Every decimal with a repeating pattern of digits is a rational number, because it can be expressed as the quotient of two integers.
1Step 1: Understand the definition of a rational number
A rational number is defined as a number that can be expressed as the quotient of two integers, where the denominator is not zero. In other words, if a number can be written in a fraction form, it is a rational number.
2Step 2: Understand the characteristic of repeating decimals
A repeating decimal is a kind of decimal notation in which after some point, the same pattern of digits repeats indefinitely. This can also be expressed in fraction form, where the numerator and denominator are integers.
3Step 3: Validate the statement
Based on the understanding from Step 1 and Step 2, it's clear that a decimal number with a repeating pattern can indeed be expressed as the quotient of two integers - this is evident from the method of converting repeating decimals to fractions. Therefore, a decimal with a repeating pattern is indeed a rational number.
Other exercises in this chapter
Problem 113
Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. \(0.75=0.749999 \ldots \ldots\)
View solution Problem 113
In Exercises 113 and \(114,\) find the values of \(p\) for which the series converges. $$ \sum_{n=1}^{\infty}(-1)^{n}\left(\frac{1}{n^{p}}\right) $$
View solution Problem 114
In Exercises 113 and \(114,\) find the values of \(p\) for which the series converges. $$ \sum_{n=1}^{\infty}(-1)^{n}\left(\frac{1}{n+p}\right) $$
View solution Problem 115
Show that the series \(\sum_{n=1}^{\infty} a_{n}\) can be written in the telescoping form \(\sum_{n=1}^{\infty}\left[\left(c-S_{n-1}\right)-\left(c-S_{n}\right)
View solution