Problem 114
Question
An expression is \((x-4)(x-3)\). Evaluate this expression when \(x=4\).
Step-by-Step Solution
Verified Answer
0
1Step 1: Identify the given expression
The expression given is \((x-4)(x-3)\). You will substitute the value of x to evaluate the expression.
2Step 2: Substitute the value of x
Given that \(x=4\), substitute 4 into the expression: \((4-4)(4-3)\).
3Step 3: Simplify each term inside the parentheses
Evaluate the terms inside the parentheses: \(4-4 = 0\) and \(4-3 = 1\).
4Step 4: Multiply the simplified terms
Now multiply the results: \(0 \times 1 = 0\).
5Step 5: Conclusion
The value of the expression \((x-4)(x-3)\) when \(x=4\) is \(0\).
Key Concepts
Substitution in AlgebraSimplifying ExpressionsAlgebraic Multiplication
Substitution in Algebra
Substitution in algebra is a fundamental process that involves replacing a variable with a given value. This makes it easier to simplify or solve expressions.
For example, in the given expression \((x-4)(x-3)\), we are asked to evaluate it when \(x=4\). To do this, we substitute 4 wherever we see \(x\) in the expression.
Substitution simply means:
For example, in the given expression \((x-4)(x-3)\), we are asked to evaluate it when \(x=4\). To do this, we substitute 4 wherever we see \(x\) in the expression.
Substitution simply means:
- Identify the variable in the expression.
- Replace the variable with the given value.
- Proceed to simplify the new, numerical expression.
Simplifying Expressions
Simplifying expressions is a crucial step to making algebraic problems more manageable. Simplification usually involves performing basic arithmetic operations:
- Addition and subtraction
- Multiplication and division
- \(4-4=0\)
- \(4-3=1\)
Algebraic Multiplication
Multiplication in algebra involves combining simplified terms to find the overall value of an expression. In this particular problem, after substituting \(x=4\) and simplifying the terms inside the parentheses, you get:\((0)(1)\).
The final step involves multiplying these terms together. In this case, multiplication is straightforward:
\(0 \times 1 = 0\).
Here’s a quick reminder when multiplying algebraic terms:
The final step involves multiplying these terms together. In this case, multiplication is straightforward:
\(0 \times 1 = 0\).
Here’s a quick reminder when multiplying algebraic terms:
- Always simplify inside parentheses first.
- Then multiply the simplified terms.
- Remember, any number multiplied by zero is zero.