Problem 113
Question
Which of the following is not possible? (a) \(\mathrm{ICH}_{2} \mathrm{COOH}+\mathrm{NaCl} \underset{\longrightarrow}{\text { Acetone }}{\longrightarrow} \mathrm{ClCH}_{2} \mathrm{COOH}+\mathrm{NaI}\) (b) \(\mathrm{ClCH}_{2} \mathrm{COOH}+\mathrm{NaI} \stackrel{\text { Acetone }}{\longrightarrow} \mathrm{ICH}_{2} \mathrm{COOH}+\mathrm{NaCl}\) (c) Both (a) and (b) (d) None of these
Step-by-Step Solution
Verified Answer
(a) is not possible under typical conditions.
1Step 1: Analyze Reaction (a)
The reaction (a) involves the transformation of \( \mathrm{ICH}_{2} \mathrm{COOH} \) into \( \mathrm{ClCH}_{2} \mathrm{COOH} \) by replacing iodine \( (\mathrm{I}) \) with chlorine \( (\mathrm{Cl}) \). This type of reaction is called halogen exchange or halide exchange, which often depends on the reactivity of the halide ions. In general, iodine is a better leaving group than chlorine, so the forward reaction where chlorine replaces iodine is feasible.
2Step 2: Analyze Reaction (b)
The reaction (b) involves the reverse process where chlorine \( (\mathrm{Cl}) \) is replaced by iodine \( (\mathrm{I}) \), transforming \( \mathrm{ClCH}_{2} \mathrm{COOH} \) to \( \mathrm{ICH}_{2} \mathrm{COOH} \). This reaction is more favorable compared to reaction (a) since iodine is a better leaving group than chlorine, making this exchange possible. In most halogen-exchange reactions, the equilibrium favors the formation of compounds with heavier halogens like iodine.
3Step 3: Evaluate Both Reactions
Since in most chemical reactions involving heavier halogens, the halogen exchange from \( \mathrm{ClCH}_{2} \mathrm{COOH} \) to \( \mathrm{ICH}_{2} \mathrm{COOH} \) (reaction b) is more favorable compared to the opposite direction (reaction a), reaction (b) is possible and more likely than reaction (a). However, reaction (a) is possible under some specific conditions with appropriate catalysts or reaction environments.
4Step 4: Determine Impossibility
In equilibrium conditions without specific catalysts or energy sources, replacing chlorine with iodine (reaction b) tends to happen faster and more commonly than replacing iodine with chlorine (reaction a). The question asks for what is "not possible," implying under normal or typical conditions. Since reaction (b) naturally favors the direction of iodine substitution due to the heavier halide, reaction (a) becomes the "not possible" reaction without additional conditions.
Key Concepts
Leaving Groups in Organic ChemistryReactivity of Halide IonsEquilibrium in Chemical Reactions
Leaving Groups in Organic Chemistry
In organic chemistry, the concept of leaving groups is crucial to understanding many reactions, including halogen exchange. A leaving group is a group of atoms that detaches from a molecule, taking its bonding electrons with it. The ability of a group to leave is essential in determining the rate and outcome of many chemical reactions.
For a group to be considered a good leaving group, it should be stable once it has left the molecule. Stability is often achieved when the leaving group is weakly basic, meaning it doesn't readily combine with protons. This stability allows the reaction to proceed smoothly, as there's less likelihood of the leaving group reattaching to its former molecule.
Halogens serve as common leaving groups. Among them, iodide ions (\( ext{I}^- \)) are typically better leaving groups than chloride ions (\( ext{Cl}^- \)). This is because iodide ions are larger, making them more able to stabilize the negative charge after detaching from the organic molecule. Therefore, in a halogen exchange, the preference is usually for reactions where iodine is expelled from the molecule and replaced by a less stable halide ion like chloride.
For a group to be considered a good leaving group, it should be stable once it has left the molecule. Stability is often achieved when the leaving group is weakly basic, meaning it doesn't readily combine with protons. This stability allows the reaction to proceed smoothly, as there's less likelihood of the leaving group reattaching to its former molecule.
Halogens serve as common leaving groups. Among them, iodide ions (\( ext{I}^- \)) are typically better leaving groups than chloride ions (\( ext{Cl}^- \)). This is because iodide ions are larger, making them more able to stabilize the negative charge after detaching from the organic molecule. Therefore, in a halogen exchange, the preference is usually for reactions where iodine is expelled from the molecule and replaced by a less stable halide ion like chloride.
Reactivity of Halide Ions
The reactivity of halide ions is a significant factor in halogen exchange reactions. In general, the reactivity of these ions is influenced by their ability to act either as nucleophiles or leaving groups.
- Nucleophilicity: In substitution reactions, where halogens replace each other, their ability to donate electron pairs (nucleophilicity) is important. Iodide ions (\( ext{I}^- \)) are more nucleophilic compared to chloride ions (\( ext{Cl}^- \)), meaning they are more effective in forming bonds with positively charged centers.
- Leaving Group Ability: As mentioned, iodide ions are better leaving groups due to their larger size and better charge stabilization, compared to smaller halide ions like chloride.
Equilibrium in Chemical Reactions
Equilibrium plays a critical role in determining the direction and extent of chemical reactions, including halogen exchange. When a reaction reaches equilibrium, the rate of the forward reaction equals the rate of the reverse reaction, leading to stable concentrations of reactants and products over time.
In halogen exchange reactions, equilibrium considers the inherent stability and reactivity of halide ions. The equilibrium will often favor the formation of the solution containing the heavier halogen, such as iodide, due to its superior leaving group ability. This is why, in the original exercise, reaction (b) dominates over reaction (a), under typical conditions.
The concept of equilibrium becomes particularly important when predicting reaction courses without additional energy inputs or catalysts. Under such natural conditions, the equilibrium will drive the reaction toward forming the product that involves expelling the better leaving group, maximizing overall system stability.
In halogen exchange reactions, equilibrium considers the inherent stability and reactivity of halide ions. The equilibrium will often favor the formation of the solution containing the heavier halogen, such as iodide, due to its superior leaving group ability. This is why, in the original exercise, reaction (b) dominates over reaction (a), under typical conditions.
The concept of equilibrium becomes particularly important when predicting reaction courses without additional energy inputs or catalysts. Under such natural conditions, the equilibrium will drive the reaction toward forming the product that involves expelling the better leaving group, maximizing overall system stability.
Other exercises in this chapter
Problem 112
Which of the following reaction is possible? (i) \(\mathrm{CH}_{3} \mathrm{COCl}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{CH}_{3} \mathrm{COOH}+\mathrm
View solution Problem 113
Grignard reagents are powerful nucleophiles and strong bases. They act as nucleophiles by attacking a variety of compounds including saturated and unsaturated c
View solution Problem 114
Acid amide do not undergo the usual properties of carbonyl, \(\mathrm{C}=\mathrm{O}\) group because (a) it is a weak base (b) it is a weak acid (c) it is amphot
View solution Problem 115
Grignard reagents are powerful nucleophiles and strong bases. They act as nucleophiles by attacking a variety of compounds including saturated and unsaturated c
View solution