Problem 113
Question
The reagent used for the preparation of higher ethers from halogenated ethers is (a) sodium alkoxide (b) Grignard reagent (c) concutrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (d) dry silver oxide
Step-by-Step Solution
Verified Answer
The reagent used is sodium alkoxide (option a).
1Step 1: Understanding Ethers
Ethers are a class of organic compounds that have an oxygen atom connected to two alkyl or aryl groups. In this exercise, we are focused on preparing higher ethers, which means forming ethers with longer or more complex carbon chains.
2Step 2: Identifying the Role of Reagents
The reagent needed must facilitate the conversion of halogenated ethers to higher ethers. For this, a reagent that can effectively replace the halogen atom with an alkoxide ion is ideal, as the alkoxide can act as a nucleophile, attacking the carbon the halogen is attached to.
3Step 3: Analyzing Sodium Alkoxide
Sodium alkoxide is commonly used in the Williamson Ether Synthesis, where it reacts with halogenated compounds to form ethers through a nucleophilic substitution reaction. It is suitable for the preparation of both simple and higher ethers.
4Step 4: Evaluating the Options
Let's assess the options: - (a) Sodium alkoxide is known for its use in ether synthesis.- (b) Grignard reagent typically forms alcohols and is not suitable for ether preparation.- (c) Concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\) is used for dehydration reactions, not ether synthesis.- (d) Dry silver oxide is not commonly used for ether synthesis.
5Step 5: Selecting the Correct Answer
Based on the analysis, sodium alkoxide is the reagent that directly facilitates the preparation of ethers from halogenated ethers through the Williamson synthesis approach. It fits the requirement for forming higher ethers.
Key Concepts
Ether SynthesisSodium AlkoxideNucleophilic Substitution Reaction
Ether Synthesis
In organic chemistry, ether synthesis is a fundamental method for creating organic compounds where an oxygen atom links two carbon-containing groups. The Williamson Ether Synthesis is a classic approach used to produce ethers efficiently. This process involves the reaction of an alkoxide ion with a primary alkyl halide or tosylate, forming a new ether linkage.
Key traits of this synthesis include:
Key traits of this synthesis include:
- Simultaneous **nucleophilic attack** and **leaving group departure**, resulting in direct production of an ether.
- Applicable to create both **simple** and **more complex ethers** with varying chain lengths.
Sodium Alkoxide
Sodium alkoxides are pivotal in the Williamson Ether Synthesis due to their role as a reactive nucleophile. When a sodium atom binds with an alkoxide ion, it forms a strong base capable of displacing a halide ion in a substitution reaction.
Sodium alkoxides are tailored for effectiveness based on the type of ether being prepared:
Sodium alkoxides are tailored for effectiveness based on the type of ether being prepared:
- Common types include **sodium methoxide** (\( ext{CH}_3 ext{ONa} \)) and **sodium ethoxide** (\( ext{C}_2 ext{H}_5 ext{ONa}\)), selected based on the desired ether.
- These compounds are typically synthesized in situ from alcohols treated with sodium metal.
Nucleophilic Substitution Reaction
Nucleophilic substitution reactions are integral to the formation of ethers in organic chemistry, especially in the context of the Williamson Ether Synthesis. In this reaction type, a nucleophile is attracted to an electrophilic center, such as a carbon atom attached to a leaving group like a halide.
The **nucleophile** (in this case, the alkoxide ion) initiates the reaction:
The **nucleophile** (in this case, the alkoxide ion) initiates the reaction:
- The process involves **bimolecular substitution (SN2 reaction)**, where the nucleophile attacks the substrate carbon, forcing the simultaneous ejection of the leaving group.
- This results in the formation of a new bond between the oxygen of the alkoxide and the substrate carbon, leading to the creation of the ether.
Other exercises in this chapter
Problem 111
In the reaction sequence, \(\mathrm{Z}\) will be Glycerol \(\stackrel{\mathrm{KHSO}_{4} / \Delta}{\longrightarrow} \mathrm{X} \stackrel{\mathrm{Zn}-\mathrm{Hg}
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A compound is soluble in concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\). It does not decolourize bromine in carbon tetrachloride but is oxidized by chromic anh
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Vinyl carbinol is (a) \(\mathrm{HO}-\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{CH}_{2}\) (b) \(\mathrm{CH}_{3}-\mathrm{C}\left(\mathrm{CH}_{2} \mathrm{OH}\right)=\math
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