Problem 113
Question
Simplify each exponential expression.Assume that variables represent nonzero real numbers. $$\frac{\left(2^{-1} x^{-2} y^{-1}\right)^{-2}\left(2 x^{-4} y^{3}\right)^{-2}\left(16 x^{-3} y^{3}\right)^{0}}{\left(2 x^{-3} y^{-5}\right)^{2}}$$
Step-by-Step Solution
Verified Answer
The simplified form of the given expression is \(\frac{x^{16}}{y^{16}}\).
1Step 1: Address Negative Exponents
Rewriting all the negative exponents to their reciprocal forms, the expression becomes: \(\frac{\left(2^{2} x^{4} y^{2}\right) \left(2^{-2} x^{8} y^{-6} \right) \left(16^{0} x^{0} y^{0}\right)}{\left(2^{2} x^{6} y^{-10}\right)}\)
2Step 2: Simplify the Zero Exponential Terms
Any number raised to the power of zero equals one. Therefore, the expression simplifies to: \(\frac{\left(2^{2} x^{4} y^{2}\right) \left(2^{-2} x^{8} y^{-6} \right)}{\left(2^{2} x^{6} y^{-10}\right)}\)
3Step 3: Simplify the expression using multiplication and division rules of exponents
The full expression simplifies to: \(4x^{12}y^{-4} \times \frac{1}{4}x^{16}y^{-12} \div 4x^{12}y^{-20}\) which further simplifies to: \(x^{12}y^{-4} \times x^{16}y^{-12} \div x^{12}y^{-10}\) resulting to: \(x^{16}y^{-16} \)
4Step 4: Convert Negative Exponents to Positive
The negative exponent rule states that we move the base with the negative exponent from the numerator to the denominator (or the from the denominator to the numerator) and change the sign of its exponent, thus the simplified expression is: \(\frac{x^{16}}{y^{16}}\)
Key Concepts
Negative ExponentsZero Exponent RuleSimplifying ExpressionsExponent Multiplication and Division Rules
Negative Exponents
When encountering negative exponents, it's important to remember what they signify. A negative exponent indicates the reciprocal or inversely proportional form of the number or variable. For example, if you see \(x^{-n}\), it can be rewritten as \(\frac{1}{x^n}\). This is a key rule in manipulating and simplifying expressions involving exponents.
- In the provided exercise, the expression \(2^{-1}x^{-2}y^{-1}\) becomes \(\frac{1}{2} \times \frac{1}{x^2} \times \frac{1}{y} = \frac{1}{2x^2y}\).
- By switching negative exponents to their reciprocal form, it becomes easier to simplify the entire expression by multiplication or division.
Zero Exponent Rule
The zero exponent rule is straightforward: any base raised to the power of zero is equal to one. This is because there are no factors of the base left, essentially leaving just a value of 1.
- For instance, \(16^0\), \(x^0\), and \(y^0\) all simplify to 1.
- This rule greatly simplifies terms in an expression and can even eliminate them if they are being multiplied by others.
Simplifying Expressions
Simplifying expressions is the process of making them as concise as possible. This often involves combining like terms, factoring out common factors, and utilizing rules for exponents.
In the exercise, once negative and zero exponents are addressed, you simplify using multiplication and division rules.
In the exercise, once negative and zero exponents are addressed, you simplify using multiplication and division rules.
- Combine powers of the same base: \(a^m \times a^n = a^{m+n}\).
- Divide powers with the same base: \( \frac{a^m}{a^n} = a^{m-n}\).
Exponent Multiplication and Division Rules
The manipulation of exponential expressions relies heavily on multiplication and division rules. Mastering these rules can significantly ease the process of handling expressions with different bases and exponents.
- Multiplication of Same Base: When multiplying powers with the same base, you add their exponents: \(x^a \times x^b = x^{a+b}\).
- Division of Same Base: When dividing like bases, subtract the exponents: \(\frac{x^a}{x^b} = x^{a-b}\).
Other exercises in this chapter
Problem 113
Simplify each expression. Assume that all variables represent positive numbers. $$ \left(\frac{x^{-\frac{5}{4} y^{\frac{1}{3}}}}{x^{-\frac{3}{4}}}\right)^{-6} $
View solution Problem 113
Perform the indicated operations. $$ \left(x^{n}+2\right)\left(x^{n}-2\right)-\left(x^{n}-3\right)^{2} $$
View solution Problem 113
Factor completely. $$ 2 x^{2}-7 x y^{2}+3 y^{4} $$
View solution Problem 113
Use the order of operations to simplify each expression. \(\frac{5 \cdot 2-3^{2}}{\left[3^{2}-(-2)\right]^{2}}\)
View solution