Problem 113
Question
Many moderately large organic molecules containing basic nitrogen atoms are not very soluble in water as neutral molecules, but they are frequently much more soluble as their acid salts. Assuming that \(\mathrm{pH}\) in the stomach is \(2.5,\) indicate whether each of the following compounds would be present in the stomach as the neutral base or in the protonated form: nicotine, \(K_{b}=7 \times 10^{-7} ;\) caffeine, \(K_{b}=4 \times 10^{-14}\) strychnine, \(K_{b}=1 \times 10^{-6} ;\) quinine, \(K_{b}=1.1 \times 10^{-6} .\)
Step-by-Step Solution
Verified Answer
Nicotine, strychnine, and quinine are protonated; caffeine is neutral.
1Step 1: Understand the Problem
We need to determine in what form each compound is present in the stomach at a given pH of 2.5, namely neutral or protonated. Since we are dealing with basic nitrogen-containing compounds, these can gain a proton if the solution pH is lower than a certain threshold.
2Step 2: Calculate pKa from Kb
For each compound, calculate the \( ext{pKa}\) using the relationship between \( ext{pKb}\) and \( ext{pKa}\). The relationship is given by \(\text{pKa} + \text{pKb} = 14\). Use this to find \(\text{pKa}\) for each compound: - Nicotine: \(\text{pKa} = 14 - (-\log_{10}(7 \times 10^{-7})) \)- Caffeine: \(\text{pKa} = 14 - (-\log_{10}(4 \times 10^{-14})) \)- Strychnine: \(\text{pKa} = 14 - (-\log_{10}(1 \times 10^{-6})) \)- Quinine: \(\text{pKa} = 14 - (-\log_{10}(1.1 \times 10^{-6})) \)
3Step 3: Solve each compound for pKa
- Nicotine: \(\text{pKa} = 14 - 6.15 = 7.85\)- Caffeine: \(\text{pKa} = 14 - 13.4 = 0.6\)- Strychnine: \(\text{pKa} = 14 - 6 = 8\)- Quinine: \(\text{pKa} = 14 - 5.95 = 8.05\)
4Step 4: Compare with the Stomach pH
Compare the calculated \(\text{pKa}\) values with the pH of the stomach (2.5). If the \(\text{pKa}\) is greater than the \(\text{pH}\), the compound will be predominantly in the protonated form.- Nicotine: \(7.85 > 2.5\) so it's protonated.- Caffeine: \(0.6 < 2.5\) so it's neutral.- Strychnine: \(8 > 2.5\) so it's protonated.- Quinine: \(8.05 > 2.5\) so it's protonated.
Key Concepts
Organic CompoundspKa and pKb RelationshipAcid-Base ReactionsNitrogen-Containing Molecules
Organic Compounds
Organic compounds are molecules mainly composed of carbon along with other elements such as hydrogen, nitrogen, oxygen, and more. In our case, we focus on nitrogen-containing organic molecules like nicotine, caffeine, strychnine, and quinine.
These molecules often have varying degrees of solubility in water.
This means they can interact with water based on their structure and the environment they are in, such as the acid level or pH of the stomach.
These molecules often have varying degrees of solubility in water.
This means they can interact with water based on their structure and the environment they are in, such as the acid level or pH of the stomach.
- These molecules can exist in different forms: neutral or protonated.
- The form they take impacts how they dissolve or interact in the stomach's acidic surroundings.
pKa and pKb Relationship
The pKa and pKb are values that respectively measure how strong an acid or a base is. They are inversely related through the equation:\[\text{pKa} + \text{pKb} = 14\]This relationship is crucial in solving many chemical equilibria problems involving acids and bases.
For a base, we can find the pKa if we know the pKb, and vice versa. Here are the steps:
For a base, we can find the pKa if we know the pKb, and vice versa. Here are the steps:
- Calculate pKb from Kb using: \(\text{pKb} = -\log_{10}(K_b)\)
- Use the equation \(\text{pKa} + \text{pKb} = 14\) to find pKa
Acid-Base Reactions
Acid-base reactions are fundamental to understanding chemistry, especially when dealing with solubility and pH changes. When we examine basic nitrogen-containing molecules, these can participate in acid-base reactions where:
- A base accepts a proton in an acidic environment.
- This changes the molecule from a neutral to a protonated form. For an environment like the stomach, which has a pH of 2.5, many nitrogen-containing bases become protonated. To determine this:
- This changes the molecule from a neutral to a protonated form. For an environment like the stomach, which has a pH of 2.5, many nitrogen-containing bases become protonated. To determine this:
- Compare their pKa values against the ambient pH of the stomach.
- If pKa is greater than the ambient pH (2.5 for the stomach), the compound will accept a proton and become protonated.
Nitrogen-Containing Molecules
Nitrogen-containing molecules are prevalent in organic chemistry and have unique properties due to the presence of the nitrogen atom, which often serves as a basic site capable of accepting a proton.
These molecules include many common drugs and compounds like nicotine, caffeine, strychnine, and quinine, which have significant biological and medicinal relevance.
These molecules include many common drugs and compounds like nicotine, caffeine, strychnine, and quinine, which have significant biological and medicinal relevance.
- The presence of a nitrogen atom can significantly influence the behavior of these molecules, particularly in the presence of different pH levels, like in the human stomach.
- The ability of these molecules to become protonated can enhance their solubility in aqueous environments, impacting how they are absorbed in biological systems.
Other exercises in this chapter
Problem 110
Arrange the following \(0.10 \mathrm{M}\) solutions in order of increasing acidity: (i) \(\mathrm{HCOONH}_{4},\) (ii) \(\mathrm{NH}_{4} \mathrm{Br}\), (iii) \(\
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A \(0.25 M\) solution of a salt \(\mathrm{NaA}\) has \(\mathrm{pH}=9.29 .\) What is the value of \(K_{a}\) for the parent acid HA?
View solution Problem 114
The amino acid glycine \(\left(\mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}\right)\) can participate in the following equilibria in water: \(\mathrm
View solution Problem 115
The \(\mathrm{p} K_{\mathrm{b}}\) of water is (a) 1 (b) 7 (c) 14 (d) not defined (e) none of the above
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