Problem 113
Question
Hydrogen cyanide, HCN, is a poisonous gas. The lethal dose is approximately \(300 \mathrm{mg}\) HCN per kilogram of air when inhaled. (a) Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring \(3.5 \times 4.5 \times 2.5 \mathrm{~m}\). The density of air at \(26^{\circ} \mathrm{C}\) is \(0.00118 \mathrm{~g} / \mathrm{cm}^{3} .(\mathbf{b})\) If the \(\mathrm{HCN}\) is formed by reaction of NaCN with an acid such as \(\mathrm{H}_{2} \mathrm{SO}_{4}\), what mass of NaCN gives the lethal dose in the room? $$ 2 \mathrm{NaCN}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+2 \mathrm{HCN}(g) $$ (c) HCN forms when synthetic fibers containing Orlon \(^{\circledast}\) or Acrilan \(^{\circledast}\) burn. Acrilan \(^{\circledast}\) has an empirical formula of \(\mathrm{CH}_{2} \mathrm{CHCN}\), so HCN is \(50.9 \%\) of the formula by mass. A rug measures \(3.5 \times 4.5 \mathrm{~m}\) and contains \(850 \mathrm{~g}\) of Acrilan \(^{\circledast}\) fibers per square yard of carpet. If the rug burns, will a lethal dose of HCN be generated in the room? Assume that the yield of HCN from the fibers is \(20 \%\) and that the carpet is \(50 \%\) consumed.
Step-by-Step Solution
VerifiedKey Concepts
Chemical Reactions
- Reactants are substances that start the reaction (here, NaCN and \( H_2SO_4 \)).
- Products are the new substances formed (here, \( Na_2SO_4 \) and \( HCN \)).
- Stoichiometry reveals the proportions of each substance used and produced based on the balanced equation.
Molar Mass Calculations
- To find the molar mass of a compound, sum the atomic masses of all atoms in the formula. Oxygen has an atomic mass of about 16, so O in HCN contributes 16 units, for example.
- For hydrogen cyanide, \( HCN \): \[ \text{Molar mass} = \text{H} + \text{C} + \text{N} = 1.01 + 12.01 + 14.01 = 27.03 \, \text{g/mol} \]
- The molar mass of \( NaCN \) is about 49.01 g/mol, combining sodium (Na), carbon (C), and nitrogen (N).
Density Conversion
- The given density of air is \(0.00118 \text{ g/cm}^3\).
- When converting to \( \text{kg/m}^3\): - Multiply by 1000 (to move from grams to kilograms). - Multiply by 1,000,000 because \(1 \text{ m}^3 = 1,000,000 \text{ cm}^3\).
- The converted density is: \[0.00118 \text{ g/cm}^3 \times 1000 \times 1,000,000 = 1.18 \text{ kg/m}^3\]