Problem 112
Question
Why doesn't the equation \(x=x+1\) have a real-number solution?
Step-by-Step Solution
Verified Answer
The equation is a contradiction; no real number satisfies \(x = x + 1\).
1Step 1: Understanding the Problem
The equation \(x = x + 1\) implies that a number is equal to itself plus one. Our goal is to determine if there is any real number \(x\) that satisfies this condition.
2Step 2: Subtracting x from Both Sides
We simplify the equation by subtracting \(x\) from both sides: \(x - x = (x + 1) - x\) which becomes \(0 = 1\).
3Step 3: Analyzing the Result
The simplified equation \(0 = 1\) is a contradiction because zero cannot equal one. This means there is no value for \(x\) that satisfies the initial equation.
Key Concepts
Real NumbersSolving EquationsContradictions in Algebra
Real Numbers
Real numbers are a fundamental concept in mathematics. They include all the numbers you can find on a regular number line. This encompasses:
- Whole numbers: like 0, 1, 2, 3, and so on.
- Integers: which are whole numbers that can be positive, negative, or zero, such as -3, -2, -1, 0, 1, 2, 3, etc.
- Rational numbers: numbers that can be expressed as the fraction of two integers, like \( \frac{1}{2} \) or -3.
- Irrational numbers: numbers that cannot be written as a simple fraction, such as \( \sqrt{2} \) or \( \pi \).
Solving Equations
Solving equations is about finding the values that make an equation true. To solve equations, one has to manipulate them to find the variable's value. Typically, operations such as addition, subtraction, multiplication, and division are used while ensuring that each operation is applied to both sides of the equation equally.
For instance, in a simple equation like \(x + 2 = 5\), you subtract 2 from both sides to isolate \(x\): \[ x + 2 - 2 = 5 - 2 \] resulting in \(x = 3\). Skipping any operation or applying it unequally can lead to incorrect solutions.
When solving more complex equations, these basic principles hold true, even if the steps become more elaborate. The goal is always to get the variable on one side of the equation and the numbers on the other.
For instance, in a simple equation like \(x + 2 = 5\), you subtract 2 from both sides to isolate \(x\): \[ x + 2 - 2 = 5 - 2 \] resulting in \(x = 3\). Skipping any operation or applying it unequally can lead to incorrect solutions.
When solving more complex equations, these basic principles hold true, even if the steps become more elaborate. The goal is always to get the variable on one side of the equation and the numbers on the other.
Contradictions in Algebra
In algebra, a contradiction is a statement that is impossible or mathematically false. These arise when an equation, through logical simplification, reveals an impossibility—such as claiming two unequal numbers are the same.
The classic contradiction example is the equation \(x = x + 1\). If we simplify this by subtracting \(x\) from both sides, we end up with \(0 = 1\). This is a contradiction because zero and one are not equal.
The classic contradiction example is the equation \(x = x + 1\). If we simplify this by subtracting \(x\) from both sides, we end up with \(0 = 1\). This is a contradiction because zero and one are not equal.
- Contradictions indicate that there is no solution within the set of numbers being considered—such as the set of real numbers in this case.
- Recognizing contradictions is vital as they signify that either there are no solutions or perhaps the problem boundary conditions need reevaluating.
Other exercises in this chapter
Problem 112
a. \(-3(-4 t)(-2)\) b. \(-3(-4 t)-2\)
View solution Problem 112
Evaluate \(2 a_{2}^{2}+3 a_{3}^{3}+4 a_{4}^{4}\) for \(a_{2}=2, a_{3}=3,\) and \(a_{4}=4\)
View solution Problem 113
a. \(6 a+6 a+6 a\) b. \(6 a+6 b+6 c\)
View solution Problem 113
Explain what the statement \(x-y=x+(-y)\) means.
View solution