Problem 112
Question
Under what conditions is the pressure exerted by a real gas less than that predicted for an ideal gas?
Step-by-Step Solution
Verified Answer
Answer: The pressure exerted by a real gas is less than the pressure exerted by an ideal gas under the following conditions: 1) The ratio of the number of moles squared (n^2) multiplied by the attractive forces parameter (a) to the volume squared (V^2) is large, and 2) the ratio of the number of moles (n) multiplied by the temperature (T) and finite size parameter (b) to the product of the volume (V) and the quantity (V-nb) is small. These conditions generally occur at low temperatures and high pressures, as the volume is low, and the attractive forces between molecules have a more significant impact on the overall pressure exerted by the real gas.
1Step 1: Ideal Gas Equation
Recall the ideal gas equation, which is given by:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
For an ideal gas, the pressure is given by:
P_ideal = (nRT) / V
2Step 2: Van der Waals Equation
The van der Waals equation is a more accurate equation for real gases. It is given by:
(P + (n^2a/V^2))(V-nb) = nRT
Where P is pressure, V is the volume, n is the number of moles, R is the gas constant, T is temperature, a is a parameter that accounts for the attractive forces between molecules, and b is a parameter related to the finite size of the molecules. The pressure exerted by a real gas is given by:
P_real = ((nRT) / (V-nb)) - (n^2 * a/V^2)
Under what conditions is the pressure exerted by a real gas less than the pressure exerted by an ideal gas?
This happens when:
P_real < P_ideal
3Step 3: Compare the ideal and real gas equations
Now we will substitute the expressions of P_ideal and P_real from Step 1 and Step 2 into the inequality and simplify.
((nRT) / (V-nb)) - (n^2 * a/V^2) < (nRT) / V
4Step 4: Solve the inequality
To solve the inequality, let's first subtract (nRT) / (V-nb) from both sides:
- (n^2 * a/V^2) < (nRT) / V - (nRT) / (V-nb)
Now we will combine the terms on the right-hand side by finding a common denominator:
- (n^2 * a/V^2) < [nRT(V-nb) - nRT(V)] / (V(V-nb))
Simplify the numerator:
- (n^2 * a/V^2) < -nRTnb / (V(V-nb))
Multiply both sides of the inequality by -1 and recall that multiplying an inequality by a negative number reverses the direction of the inequality:
(n^2 * a/V^2) > nRTnb / (V(V-nb))
5Step 5: Determine the conditions under which the inequality is true
Analyzing the inequality derived in Step 4, pressure exerted by a real gas (P_real) is less than the pressure exerted by an ideal gas (P_ideal) under the following conditions:
1. The ratio of the number of moles squared (n^2) multiplied by the attractive forces parameter (a) to the volume squared (V^2) is large.
2. The ratio of the number of moles (n) multiplied by the temperature (T) and finite size parameter (b) to the product of the volume (V) and the quantity (V-nb) is small.
These conditions generally occur at low temperatures and high pressures, as the volume is low, and the attractive forces between molecules have a more significant impact on the overall pressure exerted by the real gas.
Other exercises in this chapter
Problem 109
Ammonia is produced industrially from the reaction of hydrogen with nitrogen under pressure in a sealed reactor. What is the percent decrease in total pressure
View solution Problem 111
Why do real gases behave non-ideally at very low temperatures and very high pressures?
View solution Problem 113
Why do the values of the van red Walls constant \(b\) of the noble gas elements increase with atomic number?
View solution Problem 114
Why does the value of the constant \(a\) in the van der Weals equation generally increase with the molar mass of the gas?
View solution