Problem 112
Question
Suppose \(f(x)\) is differentiable \(x=1\) and \(\lim _{h \rightarrow 0} \frac{1}{h} f(1+h)=5\), then \(f^{\prime}(1)\) equals \([2005]\) (A) 3 (B) 4 (C) 5 (D) 6
Step-by-Step Solution
Verified Answer
The correct option is (C) 5.
1Step 1: Understanding the Differentiation and the Limit
We need to evaluate the derivative of the function at the point where it's differentiable, particularly at \(x=1\). According to the definition of a derivative, \( f'(x) \) is given by \[ f'(1) = \lim_{h \to 0} \frac{f(1+h) - f(1)}{h} \] We are given that \( \lim_{h \to 0} \frac{1}{h} f(1+h) = 5 \). This expression can be transformed to relate it to the derivative definition.
2Step 2: Relating Given Limit to Derivative Definition
The given expression \( \lim_{h \to 0} \frac{1}{h} f(1+h) \) resembles the derivative definition but lacks the term \( -\frac{f(1)}{h} \). To make it fit the definition, consider breaking down the term: \[ \frac{1}{h} f(1+h) = \frac{f(1+h) - f(1) + f(1)}{h} \] Thus: \[ \frac{1}{h} f(1+h) = \frac{f(1+h) - f(1)}{h} + \frac{f(1)}{h} \] Taking the limit as \( h \to 0 \): \[ \lim_{h \to 0} \frac{f(1+h) - f(1)}{h} + \lim_{h \to 0} \frac{f(1)}{h} = 5 \]
3Step 3: Evaluate the Limits and Solve for Derivative
By the derivative definition, we know:\[ \lim_{h \to 0} \frac{f(1+h) - f(1)}{h} = f'(1) \] \( f(1) \) is a constant, making \( \lim_{h \to 0} \frac{f(1)}{h} = 0 \).Thus:\[ f'(1) + 0 = 5 \] Hence, \( f'(1) = 5 \).
4Step 4: Determine the Correct Option
The calculated derivative \( f'(1) = 5 \) matches option (C) in the provided choices. Therefore, we conclude that the correct answer is \(5\).
Key Concepts
Understanding DifferentiationExploring LimitsDefining the DerivativeIntroduction to Functional Analysis
Understanding Differentiation
Differentiation is a fundamental concept in calculus, used to find the rate at which a function is changing at any given point. It is akin to finding the slope of a tangent line to a curve on a graph. This tells us how the function behaves around a specific value of its input.
- The process of differentiation applies to a function, resulting in a new function, known as the derivative.
- The derivative indicates the instantaneous rate of change and can reveal much about the function, such as its increasing or decreasing nature.
Exploring Limits
Limits are central to calculus, enabling us to determine the value that a function approaches as the input approaches a given point. Understanding limits is essential for defining derivatives and integrals.
- In calculus, the limit of a function when approaching a point describes the behavior of the function nearby.
- The concept of limits allows us to handle values that the function cannot reach directly.
Defining the Derivative
The derivative is defined as the limit of the average rate of change of the function as the interval approaches zero. Mathematically, for a function \( f(x) \) at point \( x = a \), it is defined as:
\[f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}\]
\[f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}\]
- This definition represents the idea of calculating the slope of a tangent line at a given point on the function's graph.
- The derivative is the foundational tool for calculating things like velocity in physics, which is the rate of change of position over time.
Introduction to Functional Analysis
Functional analysis is a branch of mathematical analysis dealing with function spaces and their properties. This broad area of study provides powerful tools for understanding phenomena described by differential equations and other operations on functions.
- It involves studying spaces of functions and transforming functions to explore algebraic structures and topology.
- Functional analysis bridges finite-dimensional spaces, like vectors, with infinite-dimensional space, offering insights into both theoretical and practical problems.
Other exercises in this chapter
Problem 108
If \(x^{y}=e^{x-y}\), then \(\frac{d y}{d x}\) is: [2002] (A) \(\frac{1+x}{1+\log x}\) (B) \(\frac{1-\log x}{1+\log x}\) (C) not defined (D) \(\frac{\log x}{(1+
View solution Problem 110
If \(f(x)=x\), then the value of \(f(1)-\frac{f^{\prime}(1)}{1 !}+\frac{f^{\prime \prime}(1)}{2 !}-\frac{f^{\prime \prime \prime}(1)}{3 !}+\ldots+\frac{(-1)^{n}
View solution Problem 113
If \(f\) is a real-valued differentiable function satisfying \(|f(x)-f(y)| \leq(x-y)^{2}, x, y \in R\) and \(f(0)=0\), then \(f(1)\) equals [2005] (A) \(-1\) (B
View solution Problem 114
The set of points where \(f(x)=\frac{x}{1+|x|}\) is differentiable is (A) \((-\infty, 0) \cup(0, \infty)\) (B) \((-\infty,-1) \cup(-1, \infty)\) (C) \((-\infty,
View solution