Problem 112
Question
Oxalic acid is heated with concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\). When the resultant gases are passed over red hot carbon, \(\mathrm{X}\) is obtained. \(\mathrm{X}\) is (a) \(\mathrm{CO}\) (b) \(\mathrm{CO}_{2}\) (c) \(\mathrm{C}_{2} \mathrm{H}_{4}\) (d) \(\mathrm{CH}_{4}\)
Step-by-Step Solution
Verified Answer
X is CO (carbon monoxide).
1Step 1: Understand the Reaction
When oxalic acid (
C_2H_2O_4) is heated with concentrated
H_2SO_4, it decomposes to form formic acid,
CO, and
CO_2.
2Step 2: Identify the Second Reaction
The gases formed, which are
CO
and
CO_2, are then passed over red hot carbon. Analyze the interaction of these gases with carbon.
3Step 3: Determine the Role of Carbon in the Reaction
Red hot carbon reacts with
CO_2
to form
CO. The reaction,
CO_2
+
C
→
2CO, causes any
CO_2
to convert to additional
CO.
4Step 4: Conclude the Reaction Outcome
Since the reaction with red hot carbon converts all
CO_2
to
CO
and
CO
remains unchanged, the final resulting gas is
CO.
Key Concepts
Thermal DecompositionInteraction with CarbonGas Reactions with CarbonCarbon Monoxide Formation
Thermal Decomposition
Oxalic acid (
C_2H_2O_4) is a fascinating compound, primarily because of its behavior when heated. When we apply heat to oxalic acid in the presence of concentrated
H_2SO_4, a thermal decomposition takes place. This means that the oxalic acid breaks down into simpler substances due to the heat energy applied. The process results in the formation of formic acid along with two gases, carbon monoxide (
CO
) and carbon dioxide (
CO_2
).
The decomposition is initiated by the strong dehydrating nature of concentrated sulfuric acid. It removes water from the oxalic acid, thereby accelerating its breakdown. This step is crucial in understanding how oxalic acid transitions from a stable state to emitting gases upon heating.
To grasp this concept thoroughly, visualize thermal decomposition as an intricate dance of breaking bonds and forming new ones. Here, even without external oxygen, oxalic acid decomposes due to the heat and chemical influence of H_2SO_4 :
The decomposition is initiated by the strong dehydrating nature of concentrated sulfuric acid. It removes water from the oxalic acid, thereby accelerating its breakdown. This step is crucial in understanding how oxalic acid transitions from a stable state to emitting gases upon heating.
To grasp this concept thoroughly, visualize thermal decomposition as an intricate dance of breaking bonds and forming new ones. Here, even without external oxygen, oxalic acid decomposes due to the heat and chemical influence of H_2SO_4 :
- Release of CO and CO_2 gases.
- Formation of formic acid as a byproduct.
Interaction with Carbon
Once oxalic acid has decomposed to release carbon monoxide (
CO
) and carbon dioxide (
CO_2
), the next step is their interaction with carbon. When these gases are passed over a bed of red hot carbon, an interesting transformation happens.
Red hot carbon serves as a reducing agent, meaning it tends to donate electrons and engage in chemical reactions which reduce another substance. When CO_2 comes into contact with red hot carbon, it reacts to form additional carbon monoxide. This happens because carbon itself combines with the oxygen in the carbon dioxide to produce more CO .
This is essentially a reduction reaction where the carbon reduces CO_2 to CO :
Red hot carbon serves as a reducing agent, meaning it tends to donate electrons and engage in chemical reactions which reduce another substance. When CO_2 comes into contact with red hot carbon, it reacts to form additional carbon monoxide. This happens because carbon itself combines with the oxygen in the carbon dioxide to produce more CO .
This is essentially a reduction reaction where the carbon reduces CO_2 to CO :
- CO_2 + C ightarrow 2CO.
Gas Reactions with Carbon
The interaction of gases like
CO
and
CO_2
with red hot carbon is a classic example of gas-solid reactions in chemistry. These reactions are driven significantly by temperature, and the presence of red hot carbon accelerates the reaction processes. High temperature provides the kinetic energy necessary for the reactants to overcome potential energy barriers, facilitating the transformation of
CO_2
into
CO
.
At this elevated temperature, the gases and carbon particles are able to collide with enough energy to break existing bonds, allowing the formation of new ones. This enables all available CO_2 molecules to participate in the redox reaction, further producing carbon monoxide. Because of this reaction:
At this elevated temperature, the gases and carbon particles are able to collide with enough energy to break existing bonds, allowing the formation of new ones. This enables all available CO_2 molecules to participate in the redox reaction, further producing carbon monoxide. Because of this reaction:
- CO remains unreacted.
- All CO_2 is converted to CO.
Carbon Monoxide Formation
The culmination of these reactions — from the decomposition of oxalic acid to the interaction with carbon — results in the exclusive formation of carbon monoxide (
CO
). This process highlights the importance of each reaction step, as they transform initial reactants into desired products.
By converting all CO_2 into CO during its passage over red hot carbon, the final gas mixture produced contains CO exclusively. This process can be summarized as follows:
By converting all CO_2 into CO during its passage over red hot carbon, the final gas mixture produced contains CO exclusively. This process can be summarized as follows:
- Oxalic acid decomposes to release CO and CO_2.
- Red hot carbon converts CO_2 to additional CO.
- Ultimately resulting in the generation of pure CO.
Other exercises in this chapter
Problem 109
Which of the following is an explosive compound? (a) \(\mathrm{XeOF}_{2}\) (b) \(\mathrm{XeF}_{2}\) (c) \(\mathrm{XeO}_{3}\) (d) \(\mathrm{XeOF}_{4}\)
View solution Problem 111
\(\mathrm{H}_{2} \mathrm{SO}_{4}\) is not used for the preparation of \(\mathrm{CO}_{2}\) from marble chips because (a) calcium sulphate is sparingly soluble an
View solution Problem 114
In the following sequence of reaction the product formed \(\mathrm{A}\) and the necessary conditions \(\mathrm{B}\) are \(\mathrm{PbS} \stackrel{\text { Heat }}
View solution Problem 115
Borax is converted into B by following steps Borax \(\stackrel{\mathrm{A}}{\longrightarrow} \mathrm{H}_{3} \mathrm{BO}_{3} \stackrel{\Delta}{\longrightarrow} \m
View solution