Problem 112
Question
Brass is a copper-zinc alloy. What is the mass in grams of a brass cylinder having a length of \(1.62\) in. and a diameter of \(0.514\) in. if the composition of the brass is \(67.0 \%\) copper and \(33.0 \%\) zinc by mass? The density of copper is \(8.92 \mathrm{~g} / \mathrm{cm}^{3}\), and the density of zinc is \(7.14 \mathrm{~g} / \mathrm{cm}^{3}\). Assume that the density of the brass varies linearly with composition.
Step-by-Step Solution
Verified Answer
The mass of the brass cylinder is approximately 45.89 grams.
1Step 1: Convert Dimensions to Metric Units
First, convert the dimensions of the brass cylinder from inches to centimeters, because the density is in grams per cubic centimeter. Use the conversion factor: 1 inch = 2.54 cm.Length of the cylinder in cm:\[ 1.62 \text{ in} \times 2.54 \text{ cm/in} = 4.1148 \text{ cm} \]Diameter of the cylinder in cm:\[ 0.514 \text{ in} \times 2.54 \text{ cm/in} = 1.30636 \text{ cm} \]
2Step 2: Calculate Cylinder's Volume
The volume \( V \) of a cylinder is given by:\[ V = \pi r^2 h \]where \( r \) is the radius and \( h \) is the height (length).First, find the radius in cm:\[ r = \frac{1.30636}{2} = 0.65318 \text{ cm} \]Next, calculate the volume:\[ V = \pi \times (0.65318)^2 \times 4.1148 \approx 5.509 \text{ cm}^3 \]
3Step 3: Determine Brass Density
Assume the density \( \rho \) of brass is a weighted average of the densities of copper and zinc. Use the given composition percentages:\[ \rho_{brass} = 0.67 \times 8.92 + 0.33 \times 7.14 \]Calculate:\[ \rho_{brass} = 5.9764 + 2.3562 = 8.3326 \text{ g/cm}^3 \]
4Step 4: Calculate Mass of the Cylinder
Now, use the formula for mass based on density and volume:\[ \text{Mass} = \text{Density} \times \text{Volume} \]Substitute the values:\[ \text{Mass} = 8.3326 \times 5.509 \approx 45.89 \text{ grams} \]
Key Concepts
Understanding Brass DensityVolume Calculation of a CylinderMetric Unit ConversionUnderstanding Weighted Average Density
Understanding Brass Density
Brass is a metal alloy made primarily of copper and zinc. The density of brass is not a fixed number because it depends on the proportion of copper and zinc present in the alloy.
The relationship between the density of brass and its composition is assumed to be linear, meaning it is directly affected by the densities of its constituent metals.
Copper has a density of \( 8.92 \ \text{g/cm}^3 \), while zinc has a density of \( 7.14 \ \text{g/cm}^3 \).
The relationship between the density of brass and its composition is assumed to be linear, meaning it is directly affected by the densities of its constituent metals.
Copper has a density of \( 8.92 \ \text{g/cm}^3 \), while zinc has a density of \( 7.14 \ \text{g/cm}^3 \).
- If brass contains more copper, it will have a density closer to 8.92 g/cm³.
- If it contains more zinc, the density will approach 7.14 g/cm³.
Volume Calculation of a Cylinder
Calculating the volume of a cylinder involves determining its base area and multiplying by its height. The basic formula for a cylinder's volume is: \[ V = \pi r^2 h \] Here, \( r \) is the radius of the base, and \( h \) is the height of the cylinder.
Given dimensions are typically in different units, such as inches, which need to be converted into centimeters or other metric units first.
The steps for calculating the volume of our brass cylinder are:
Given dimensions are typically in different units, such as inches, which need to be converted into centimeters or other metric units first.
The steps for calculating the volume of our brass cylinder are:
- Convert the height and diameter from inches to centimeters since density is provided in \( \text{g/cm}^3 \).
- Find the radius by halving the diameter.
- Use the formula with the converted dimensions to find the volume.
Metric Unit Conversion
Metric unit conversion is a fundamental step in solving problems with international unit standards. Often, measurements provided in inches need to be converted into centimeters, especially when dealing with densities given in \( \text{g/cm}^3 \).
The conversion factor between inches and centimeters is \( 1 \text{ inch} = 2.54 \text{ cm} \), which is crucial for consistent measurements.
Let's convert a few measurements:
The conversion factor between inches and centimeters is \( 1 \text{ inch} = 2.54 \text{ cm} \), which is crucial for consistent measurements.
Let's convert a few measurements:
- To convert 1.62 inches to centimeters: \[ 1.62 \times 2.54 = 4.1148 \ cm \]
- The diameter of 0.514 inches becomes: \[ 0.514 \times 2.54 = 1.30636 \ cm \]
Understanding Weighted Average Density
Weighted average density takes into account the proportion of each component in a mixture or alloy.
In a copper-zinc alloy like brass, knowing the proportion by mass for each element helps calculate the overall density of the material.
The formula for calculating weighted average density in a two-component alloy is:
In the example provided, the composition is understood as:
In a copper-zinc alloy like brass, knowing the proportion by mass for each element helps calculate the overall density of the material.
The formula for calculating weighted average density in a two-component alloy is:
- \( \rho = \text{(fraction of component 1)} \times \text{density of component 1} \)
- \( + \text{(fraction of component 2)} \times \text{density of component 2} \)
In the example provided, the composition is understood as:
- 67% copper translates to 0.67 in the formula
- 33% zinc translates to 0.33
Other exercises in this chapter
Problem 110
A \(125 \mathrm{~mL}\) sample of water at \(293.2 \mathrm{~K}\) was heated for \(8 \mathrm{~min}, 25 \mathrm{~s}\) so as to give a constant temperature increase
View solution Problem 111
A calibrated flask was filled to the \(25.00 \mathrm{~mL}\) mark with ethyl alcohol. By weighing the flask before and after adding the alcohol, it was determine
View solution Problem 113
Ocean currents are measured in Sverdrups \((\mathrm{sv})\) where \(1 \mathrm{sv}=10^{9} \mathrm{~m}^{3} / \mathrm{s}\). The Gulf Stream off the tip of Florida,
View solution Problem 114
The element gallium (Ga) has the second largest liquid range of any element, melting at \(29.78{ }^{\circ} \mathrm{C}\) and boiling at \(2204{ }^{\circ} \mathrm
View solution