Problem 111
Question
Which one of the following pairs is not correctly matched? (a) \(>\mathrm{C}=\mathrm{O} \underset{\text { Clemmensen reduction }}{\longrightarrow}>\mathrm{CH}_{2}\) (b) \(-\mathrm{COCl} \longrightarrow-\mathrm{CHO}\) Rosenmund reduction (c) \(>\mathrm{C}=\mathrm{O} \underset{\text { Wolff }-\text { Kishner reduction }}{\longrightarrow}>\mathrm{CHOH}\) (d) \(-\mathrm{C} \equiv \mathrm{N} \longrightarrow-\mathrm{CHO}\) Stephen reduction
Step-by-Step Solution
Verified Answer
Option (c) is not correctly matched; Wolff-Kishner reduction reduces to CH2, not CHOH.
1Step 1: Review each reaction type
Each option describes a chemical reaction process, where specific functional groups undergo certain transformations. These reactions are well-defined named reactions in organic chemistry.
2Step 2: Clemmensen Reduction Analysis
The Clemmensen reduction is used to reduce carbonyl groups (C=O) to methylene groups (CH2) using zinc amalgam and hydrochloric acid. This matches option (a), which correctly transforms (C=O) to (CH2).
3Step 3: Rosenmund Reduction Analysis
The Rosenmund reduction is used to reduce acyl chloride (-COCl) to an aldehyde (-CHO) using hydrogen gas in the presence of a palladium catalyst poisoned with barium sulfate. Option (b) correctly describes this transformation.
4Step 4: Wolff-Kishner Reduction Analysis
The Wolff-Kishner reduction converts carbonyl groups (C=O) to methylene groups (CH2) using hydrazine and a strong base. Therefore, option (c) incorrectly shows (C=O) converting to (CHOH) when it should show (CH2).
5Step 5: Stephen Reduction Analysis
Stephen reduction is used to convert nitriles (–C≡N) to aldehydes (-CHO) by using stannous chloride and hydrochloric acid. Option (d) correctly matches this description.
Key Concepts
Clemmensen ReductionRosenmund ReductionWolff-Kishner ReductionStephen Reduction
Clemmensen Reduction
The Clemmensen reduction is an important reaction in organic chemistry, utilized primarily to convert carbonyl compounds (such as ketones and aldehydes) into hydrocarbons. The reaction uses zinc amalgam (a combination of zinc with mercury) and concentrated hydrochloric acid as catalysts.
The aim of this reduction is straightforward: it transforms a carbonyl group (C=O) into a methylene group (CH2). This can be particularly useful when desiring to reduce a ketone or an aldehyde without affecting other sensitive functional groups present in the molecule.
The aim of this reduction is straightforward: it transforms a carbonyl group (C=O) into a methylene group (CH2). This can be particularly useful when desiring to reduce a ketone or an aldehyde without affecting other sensitive functional groups present in the molecule.
- Typical conditions: Heating is often applied to facilitate the reaction.
- Limitations: Clemmensen reduction is not suitable for compounds containing acid-sensitive groups as harsh acidic conditions are required.
Rosenmund Reduction
The Rosenmund reduction provides a method to selectively reduce acyl chlorides (COCl) to aldehydes (CHO). This reaction utilizes hydrogen gas in the presence of a palladium catalyst. However, to ensure that the reaction does not reduce the aldehyde further to an alcohol, the palladium is poisoned using barium sulfate.
To execute a Rosenmund reduction, careful control of conditions is vital to maintain the presence of the aldehyde rather than reducing it all the way to an alcohol.
To execute a Rosenmund reduction, careful control of conditions is vital to maintain the presence of the aldehyde rather than reducing it all the way to an alcohol.
- Specificity: This reduction is specific to acyl chlorides and is often chosen for its reliability in aldehyde synthesis from acyl chlorides.
- Safety Note: Hydrogen gas handling should be executed with caution due to its flammable nature.
Wolff-Kishner Reduction
The Wolff-Kishner reduction is a chemical reaction that transforms carbonyl groups (such as ketones and aldehydes) into methylene groups (CH2). This is achieved by using hydrazine and a strong base, often potassium hydroxide, under basic conditions with heat.
The process occurs under neutral to basic conditions, making it suitable for substrates that are sensitive to acids.
The process occurs under neutral to basic conditions, making it suitable for substrates that are sensitive to acids.
- Major application: Used primarily for substrates where acidic conditions (like those in Clemmensen reduction) would lead to decomposition.
- Procedure: The reaction begins with the formation of a hydrazone, which then decomposes to form nitrogen gas and the target hydrocarbon.
Stephen Reduction
Stephen reduction is a special technique used to convert nitriles (e.g., CN) into aldehydes. The reaction involves the use of stannous chloride (SnCl2) and hydrochloric acid.
This reduction method is vital as it enables the conversion of nitrogen-containing organic compounds into aldehydes, opening pathways for various synthetic applications.
This reduction method is vital as it enables the conversion of nitrogen-containing organic compounds into aldehydes, opening pathways for various synthetic applications.
- Chemistry in action: The process works by initially converting the nitrile into an iminium salt, which is then hydrolyzed to yield the desired aldehyde.
- Importance: The Stephen reduction is extremely useful when working with nitriles, aiming to obtain aldehydes without over-reducing to alcohols.
Other exercises in this chapter
Problem 108
The most reactive compound towards formation of cyanohydrin on treatment with KCN followed by acidification is (a) p-nitrobenzaldehyde (b) p-hydroxybenzaldehyde
View solution Problem 110
If 3 -hexanone is reacted with \(\mathrm{NaBH}_{4}\) followed by hydrolysis with \(\mathrm{D}_{2} \mathrm{O}\), the product will be (a) \(\mathrm{CH}_{3} \mathr
View solution Problem 113
Predict the product 'B' in the sequence of reaction \(\mathrm{HC} \equiv \mathrm{CH} \frac{30 \% \mathrm{H}_{2} \mathrm{SO}_{4}}{\mathrm{HgSO}_{4}} \mathrm{~A}
View solution Problem 114
An organic compound 'A' has the molecular formula \(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O} .\) It undergoes iodoform test. When saturated with HCl it gives 'B
View solution