Problem 111
Question
To determine whether a frog can judge distance by means of the amount its lens must move to focus on an object, researchers covered one eye with an opaque material. An insect was placed in front of the frog, and the distance that the frog snapped its tongue out to catch the insect was measured with high-speed video. The experiment was repeated with a contact lens over the eye to determine whether the frog could correctly judge the distance under these conditions. If such an experiment is performed twice, once with a lens of power -9-D and once with a lens of power -15-D, in which case does the frog have to focus at a shorter distance, and why? (a) With the -9-D lens; because the lenses are diverging, the lens with the longer focal length creates an image that is closer to the frog. (b) With the -15-D lens; because the lenses are diverging, the lens with the shorter focal length creates an image that is closer to the frog. (c) With the -9-D lens; because the lenses are converging, the lens with the longer focal length creates a larger real image. (d) With the -15-D lens; because the lenses are converging, the lens with the shorter focal length creates a larger real image.
Step-by-Step Solution
VerifiedKey Concepts
Diverging Lens
- These lenses are typically thinner at the center than at the edges.
- They are characterized by having a negative focal length.
- Diverging lenses are commonly used to correct nearsightedness.
Lens Power
\[ P = \frac{1}{f} \]where \( P \) is the power in diopters and \( f \) is the focal length in meters.
- A negative power indicates a diverging lens.
- Higher absolute values of lens power mean a stronger lens.
- For instance, a -15-D lens has more power than a -9-D lens.
Focal Length
- It is negative for diverging lenses.
- Shorter focal lengths indicate stronger lenses, providing bigger divergence.
- In our example, a focal length associated with -15-D is shorter than -9-D.
Virtual Image
- Virtual images are upright compared to the object.
- Formed on the same side as the object in diverging lenses.
- The size of the virtual image can vary based on the lens's focal length.