Problem 111
Question
Show that the equation \(r=a \cos \theta+b \sin \theta\) where \(a\) and \(b\) are real numbers, describes a circle. Find the center and radius of the circle.
Step-by-Step Solution
Verified Answer
If so, determine the center and radius of the circle.
Answer: Yes, the polar equation \(r = a\cos\theta + b\sin\theta\) describes a circle. The center of the circle is \(\left(\frac{ab}{a^2 + b^2}, \frac{b^2 - a^2}{a^2 + b^2}\right)\), and the radius is \(r = \sqrt{h^2 + k^2 + r^2 - h^2 - k^2}\), where \(h = \frac{ab}{a^2 + b^2}\) and \(k = \frac{b^2 - a^2}{a^2 + b^2}\).
1Step 1: Simplify the equation using trigonometric identities
To do this, we need to manipulate the equation into the standard form of a circle's equation: \((x-h)^2 + (y-k)^2 = r^2\). Firstly, we square the given equation and use the Pythagorean identity:
\(r^2 = a^2\cos^2\theta + b^2\sin^2\theta + 2ab\cos\theta\sin\theta\)
since \(\sin^2\theta+\cos^2\theta = 1\).
2Step 2: Convert polar form to rectangular form
Keep in mind that \(r^2 = x^2 + y^2\). We use the relationships \(x = r\cos\theta\) and \(y = r\sin\theta\). Substituting these into the equation, we get:
\(x^2 + y^2 = a^2(\frac{x^2}{x^2 + y^2}) + b^2(\frac{y^2}{x^2 + y^2}) + 2ab(\frac{x}{x^2 + y^2})\times(\frac{y}{x^2 + y^2})\)
Now, we can simplify this equation by multiplying through by \((x^2 + y^2)\):
\(x^2(x^2 + y^2) = a^2 x^2 + b^2 y^2 + 2ab xy\)
3Step 3: Rearrange the equation to the standard circle equation form
We want to manipulate the equation into the form \((x-h)^2 + (y-k)^2 = r^2\). To do this, complete the square for the x and y terms. The rearranged equation becomes:
\((x^2 - 2h x) + (y^2 - 2k y) = r^2 - h^2 - k^2\)
where \(h = \frac{ab}{a^2 + b^2}\) and \(k = \frac{b^2 - a^2}{a^2 + b^2}\). Comparing this with the standard circle equation, we find that the center of the circle is \(C(h, k)\) and radius is \(r = \sqrt{h^2 + k^2 + r^2 - h^2 - k^2}\).
To conclude, the given equation \(r = a\cos\theta + b\sin\theta\) describes a circle with center \(C(\frac{ab}{a^2 + b^2}, \frac{b^2 - a^2}{a^2 + b^2})\) and radius \(r = \sqrt{h^2 + k^2 + r^2 - h^2 - k^2}\).
Key Concepts
Circle EquationTrigonometric IdentitiesRectangular Coordinates
Circle Equation
The circle equation is fundamental in geometry and arises from the more general concept of conic sections. A standard formula for a circle can be expressed as \( (x-h)^2 + (y-k)^2 = r^2 \). In this representation:
- \(x\) and \(y\) denote any arbitrary point on the circle.
- \((h, k)\) is the center of the circle.
- \(r\) is the radius of the circle, representing the constant distance from any point on the circle to its center.
Trigonometric Identities
Trigonometric identities are tools that relate the angles and sides of triangles in a unit circle, often simplifying complex trigonometric expressions. A useful identity for circles is the Pythagorean identity: \( \sin^2\theta + \cos^2\theta = 1 \), which applies to any angle \( \theta \). This identity is among the most fundamental in trigonometry and serves as a cornerstone for deriving various other identities. In this exercise, we used it to transform the polar equation into a squared form, facilitating conversion to rectangular coordinates. This step is crucial for finding the standard circle equation. Additional identities often used include:
- \( \sin(2\theta) = 2\sin\theta \cos\theta \)
- \( \cos(2\theta) = \cos^2\theta - \sin^2\theta \)
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, are defined using perpendicular axes traditionally labeled as "x" and "y". In a 2D plane, these coordinates help pinpoint the exact location of a point using a pair \( (x, y) \), where:
- \(x\) represents the horizontal distance from the origin.
- \(y\) represents the vertical distance from the origin.
- \( x = r\cos\theta \)
- \( y = r\sin\theta \)
Other exercises in this chapter
Problem 110
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Find the equation in Cartesian coordinates of the lemniscate \(r^{2}=a^{2} \cos 2 \theta,\) where \(a\) is a real number.
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Without using a graphing utility, determine the symmetries (if any) of the curve \(r=4-\sin (\theta / 2)\).
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