Problem 111
Question
Perform the indicated operations. $$ [(7 x+5)+4 y][(7 x+5)-4 y] $$
Step-by-Step Solution
Verified Answer
The result of the operation \((7x+5+4y)(7x+5-4y)\) is \(49x^2+70x+25 - 16y^2\).
1Step 1: Determine the format of the given problem
Check if the given expression follows the pattern of difference of squares \((a+b)(a-b)\). Here \(a\) is \(7x+5\) and \(b\) is \(4y\).
2Step 2: Apply the formula of difference of squares
Replace \(a\) and \(b\) in the formula. This gives \((7x+5)^2 - (4y)^2\).
3Step 3: Expand the squared terms
Solve \((7x+5)^2\) and \((4y)^2\). This result in \(49x^2+70x+25\) and \(16y^2\) respectively.
4Step 4: Subtract the squared terms
Now subtract the second term from the first one to get the final result: \(49x^2+70x+25 - 16y^2\).
Key Concepts
Difference of SquaresExpanding ExpressionsAlgebraic Operations
Difference of Squares
One of the most useful identities in algebra is the difference of squares formula. This formula states that for any expressions \(a\) and \(b\), the product of the sum and difference, \((a+b)(a-b)\), can be expressed as \(a^2-b^2\).
By comparing the initial expression \([(7x+5)+4y][(7x+5)-4y]\) to this structure, you can see that \(a = 7x+5\) and \(b = 4y\). Recognizing this pattern allows us to simplify the problem significantly by directly applying the identity, transforming it into \((7x+5)^2 - (4y)^2\).
The key advantage here is that it reduces a complicated multiplication problem into simpler squares, making it much easier to handle.
By comparing the initial expression \([(7x+5)+4y][(7x+5)-4y]\) to this structure, you can see that \(a = 7x+5\) and \(b = 4y\). Recognizing this pattern allows us to simplify the problem significantly by directly applying the identity, transforming it into \((7x+5)^2 - (4y)^2\).
The key advantage here is that it reduces a complicated multiplication problem into simpler squares, making it much easier to handle.
Expanding Expressions
Expanding expressions is an essential skill in algebra, allowing you to simplify and better understand equations. Once we have identified the expression as a difference of squares, we need to expand \((7x+5)^2\) and \((4y)^2\).
Let's break it down: expanding \((7x+5)^2\) involves squaring a binomial, which requires the use of another known formula: \((a+b)^2 = a^2 + 2ab + b^2\). Applying this, we have:
For \((4y)^2\), the process is straightforward: simply square \(4y\), resulting in \(16y^2\). Expanding both components helps to reveal the inner parts of the expression, making subtraction easier in subsequent steps.
Let's break it down: expanding \((7x+5)^2\) involves squaring a binomial, which requires the use of another known formula: \((a+b)^2 = a^2 + 2ab + b^2\). Applying this, we have:
- Calculate \( (7x)^2 = 49x^2 \)
- Calculate \( 2(7x)(5) = 70x \)
- Calculate \( 5^2 = 25 \)
For \((4y)^2\), the process is straightforward: simply square \(4y\), resulting in \(16y^2\). Expanding both components helps to reveal the inner parts of the expression, making subtraction easier in subsequent steps.
Algebraic Operations
Once you've expanded the terms using algebraic identities, the final step is to perform algebraic operations to obtain the solution. The primary operation in this task is subtraction.
Following our expansion, we need to subtract the result of \((4y)^2\) from \((7x+5)^2\):
Following our expansion, we need to subtract the result of \((4y)^2\) from \((7x+5)^2\):
- The expression becomes \(49x^2 + 70x + 25 - 16y^2\).
Other exercises in this chapter
Problem 110
Simplify each exponential expression.Assume that variables represent nonzero real numbers. $$\left(3 x^{-4} y z^{-7}\right)(3 x)^{-3}$$
View solution Problem 111
Simplify each expression. Assume that all variables represent positive numbers. $$ \left(49 x^{-2} y^{4}\right)^{-\frac{1}{2}}\left(x y^{\frac{1}{2}}\right) $$
View solution Problem 111
Factor completely. $$ (x-y)^{4}-4(x-y)^{2} $$
View solution Problem 111
Simplify each exponential expression.Assume that variables represent nonzero real numbers. $$\left(\frac{x^{3} y^{4} z^{5}}{x^{-3} y^{-4} z^{-5}}\right)^{-2}$$
View solution