Problem 111
Question
In Exercises 111–113, perform the indicated operations. $$[(7 x+5)+4 y][(7 x+5)-4 y]$$
Step-by-Step Solution
Verified Answer
The simplified version of the given expressions is: \( 14x + 10 \)
1Step 1: Identify the binomial expressions
In this problem, \( (7x + 5 + 4y) \) and \( (7x + 5 - 4y) \) are the binomial expressions.
2Step 2: Apply the difference of squares formula
The difference of squares formula is given by \( a^2 - b^2 = (a + b)(a - b) \). In this context, \( a = (7x + 5 + 4y) \) and \( b = (7x + 5 - 4y) \), implies that \( a - b = 0 \) and \( a + b = 2(7x + 5) \).
3Step 3: Simplify the expression
Simplify the expression via distributing the '2' within the brackets, this gives us \( 2*7x + 2*5 = 14x + 10 \).
Key Concepts
Binomial ExpressionsDifference of SquaresSimplificationDistributive Property
Binomial Expressions
Binomial expressions are algebraic expressions that contain exactly two terms.
They are often connected by a plus (+) or minus (-) sign. In the exercise given, we have two binomial expressions:
Binomials are the fundamental pieces that later combine to form bigger algebraic structures. Being able to identify and manipulate these expressions helps build a strong foundation in algebra.
They are often connected by a plus (+) or minus (-) sign. In the exercise given, we have two binomial expressions:
- \((7x + 5 + 4y)\)
- \((7x + 5 - 4y)\)
Binomials are the fundamental pieces that later combine to form bigger algebraic structures. Being able to identify and manipulate these expressions helps build a strong foundation in algebra.
Difference of Squares
The difference of squares is a special algebraic identity that simplifies the product of two conjugate binomials.
It is represented by the formula: \(a^2 - b^2 = (a + b)(a - b)\).
In our problem, the expression is naturally set up to use this formula.
This results in an elegant simplification.
It is represented by the formula: \(a^2 - b^2 = (a + b)(a - b)\).
In our problem, the expression is naturally set up to use this formula.
- The structure \([(7x + 5) + 4y][(7x + 5) - 4y]\) fits exactly the difference of squares pattern.
- This concept enables us to simplify the expression efficiently without performing direct multiplication.
This results in an elegant simplification.
Simplification
Simplification involves rewriting an expression in a more concise or easily interpretable form.
In this exercise, the application of the difference of squares formula allows the expression to be condensed from its original form. By observing \((a + b)(a - b)\) as part of the difference of squares formula, it reduces
This process is key in algebra for revealing simpler truths from more complex expressions.
In this exercise, the application of the difference of squares formula allows the expression to be condensed from its original form. By observing \((a + b)(a - b)\) as part of the difference of squares formula, it reduces
- to a simpler mathematical form: \(a^2 - b^2\).
- This further simplifies down to \((14x + 10)\) using distributive property.
This process is key in algebra for revealing simpler truths from more complex expressions.
Distributive Property
The distributive property is a fundamental principle in arithmetic and algebra, crucial for simplifying expressions.
It states that multiplying a single term by terms inside a parenthesis can be done individually to each term. Mathematically, this is expressed as \(a(b + c) = ab + ac\).
In the context of our exercise, the simplification step emerges from distributing:
Mastering it aids in manipulating and simplifying a wide range of algebraic problems.
It states that multiplying a single term by terms inside a parenthesis can be done individually to each term. Mathematically, this is expressed as \(a(b + c) = ab + ac\).
In the context of our exercise, the simplification step emerges from distributing:
- Here, distributing "2" gives \(14x + 10\).
- This property breaks down a potentially complex multiplication into simple, manageable terms.
Mastering it aids in manipulating and simplifying a wide range of algebraic problems.
Other exercises in this chapter
Problem 111
Simplify each exponential expression. Assume that variables represent nonzero real numbers. $$\left(\frac{x^{3} y^{4} z^{5}}{x^{-3} y^{-4} z^{-5}}\right)^{-2}$$
View solution Problem 111
In Exercises \(111-114\), simplify each expression. Assume that all variables represent positive numbers. $$\left(49 x^{-2} y^{4}\right)^{-\frac{1}{2}}\left(x y
View solution Problem 111
Use the order of operations to simplify each expression. $$8^{2}-16 \div 2^{2} \cdot 4-3$$
View solution Problem 112
$$\text { Factor completely.}$$ $$(x+y)^{4}-100(x+y)^{2}$$
View solution