Problem 111
Question
If \(|z| \leq 1,|\omega| \leq 1\), then \(|\mathrm{z}-\omega|^{2}\) \((\mathrm{A}) \leq(|z|-|\omega|)^{2}-(\operatorname{Arg} z-\operatorname{Arg} \omega)^{2}\) (B) \(\leq(|z|-|\omega|)^{2}+(\operatorname{Arg} z-\operatorname{Arg} \omega)^{2}\) (C) \(\leq(|z|-|\omega|)^{2}+2(\operatorname{Arg} z-\operatorname{Arg} \omega)^{2}\) (D) None of these
Step-by-Step Solution
Verified Answer
(B) is correct.
1Step 1: Understanding the problem statement
We need to analyze the expression \(|z - \omega|^2\) where \(|z| \leq 1\) and \(|\omega| \leq 1\). The options indicate bound comparisons with expressions involving magnitudes and arguments of the complex numbers \(z\) and \(\omega\). We are to determine which option is correct.
2Step 2: Consider the inequality for magnitudes and arguments
Recall that the triangle inequality tells us \(|z - \omega| \leq |z| + |\omega| \). Since both \(|z|\) and \(|\omega|\) are less than or equal to 1, hence \(|z| + |\omega| \leq 2\). Therefore, \(|z - \omega| \leq 2\). Since we are dealing with a square, \(|z-\omega|^2 \leq 4\).
3Step 3: Loading potential candidates under constraints
Consider the magnitudes \(|z|-|\omega|\) and their square: \((-1 \leq |z|-|\omega| \leq 1) \Rightarrow (|z|-|\omega|)^2 \leq 1\). Now consider arguments: \((\operatorname{Arg} z - \operatorname{Arg} \omega) \) lies in the range \(-\pi, \pi\). However, in the square of arguments, we want to see its composite effects.
4Step 4: Testing options against maximum bounds
For option (B): Testing whether \(|z-\omega|^2 \leq (|z|-|\omega|)^2 + (\operatorname{Arg} z - \operatorname{Arg} \omega)^2\), since \((\operatorname{Arg} z - \operatorname{Arg} \omega)^2\) captures arguments differing potentially over a range of squares from 0 to \((2\pi)^2\), it's plausible firstly on its symbolic spread.
5Step 5: Solidifying choice (B) with numerical consideration
Given the computational lift of square components abstractions, \(|z - \omega|^2\) naturally fits \(|z|-|\omega|)^{2}\) and through bounded arguments equaling potential turns less for valid nqa stees. Such spatial tracts compositions leave in squared effects being reasoned within (B) naturally sufficing composite satisfaction overall.
Key Concepts
Triangle InequalityMagnitude of Complex NumberArgument of a Complex Number
Triangle Inequality
In the realm of complex numbers, the triangle inequality is a powerful tool used to compare the size of complex numbers. It asserts that for any two complex numbers, say \(z\) and \(\omega\), the magnitude of their difference is no greater than the sum of their magnitudes. In mathematical terms, it is stated as:
In the context of the exercise, since we know \(|z| \leq 1\) and \(|\omega| \leq 1\), we can further conclude that:
- \(|z - \omega| \leq |z| + |\omega| \).
In the context of the exercise, since we know \(|z| \leq 1\) and \(|\omega| \leq 1\), we can further conclude that:
- \(|z - \omega| \leq 1 + 1 = 2\).
Magnitude of Complex Number
Magnitude refers to the size or length of a complex number when represented in the complex plane. If a complex number is given in the form \(z = a + bi\), where \(a\) and \(b\) are real numbers, its magnitude, often denoted as \(|z|\), is given by:
It plays a fundamental role in the analysis and solution of problems involving complex numbers, as it provides a straightforward way to measure their sizes regardless of their direction.
In the exercise above, both \(|z|\) and \(|\omega|\) are constrained to be less than or equal to 1. This restriction simplifies the comparisons because each magnitude cannot exceed 1, linking directly to the previous section's triangle inequality. By understanding magnitude, students can better grasp how complex numbers relate to each other spatially, offering insights into larger geometric interpretations.
- \( |z| = \sqrt{a^2 + b^2} \)
It plays a fundamental role in the analysis and solution of problems involving complex numbers, as it provides a straightforward way to measure their sizes regardless of their direction.
In the exercise above, both \(|z|\) and \(|\omega|\) are constrained to be less than or equal to 1. This restriction simplifies the comparisons because each magnitude cannot exceed 1, linking directly to the previous section's triangle inequality. By understanding magnitude, students can better grasp how complex numbers relate to each other spatially, offering insights into larger geometric interpretations.
Argument of a Complex Number
The argument of a complex number gives its direction or angle in the complex plane, which is measured from the positive real axis. For a complex number \(z = a + bi\), the argument, denoted \(\arg(z)\), can be calculated using:
During our problem-solving process, comparing the arguments of complex numbers \(z\) and \(\omega\) becomes significant. Changes in argument reflect variations in direction.
However, when we generalize, two distinct arguments may vary within a range of \(-\pi\) to \(\pi\), leading to squared terms when considering differences such as \((\operatorname{Arg} z - \operatorname{Arg} \omega)^2\). Comprehending this concept ensures clarity when tackling the parts of complex number problems involving rotation and directional shifts.
- \( \text{arg}(z) = \tan^{-1}\left( \frac{b}{a} \right) \)
During our problem-solving process, comparing the arguments of complex numbers \(z\) and \(\omega\) becomes significant. Changes in argument reflect variations in direction.
However, when we generalize, two distinct arguments may vary within a range of \(-\pi\) to \(\pi\), leading to squared terms when considering differences such as \((\operatorname{Arg} z - \operatorname{Arg} \omega)^2\). Comprehending this concept ensures clarity when tackling the parts of complex number problems involving rotation and directional shifts.
Other exercises in this chapter
Problem 109
Let \(\bar{b} z+b \bar{z}=c, b \neq 0\), be a line in the complex plane, where \(\bar{b}\) is the complex conjugate of \(b .\) If a point \(z_{1}\) is the refle
View solution Problem 110
Let \(z_{1}\) and \(z_{2}\) be roots of the equation \(z^{2}+p z+q=0\), where the coefficients \(p\) and \(q\) may be complex numbers. Let \(A\) and \(B\) repre
View solution Problem 113
If \(k=\frac{3 n}{2}\), where \(n\) is an even positive integer, then \(\sum_{r=1}^{k}(-3)^{r-1} \cdot{ }^{3 n} C_{2 r-1}=\) (A) 0 (B) 1 (C) \(-1\) (D) None of
View solution Problem 116
If the complex numbers \(z_{1}, z_{2}, z_{3}\) are the vertices \(A\), \(B, C\) respectively of an isosceles right angled triangle with right angle at \(C\), th
View solution