Problem 111
Question
How do you determine if an equation in \(x\) and \(y\) defines \(y\) as a function of \(x ?\)
Step-by-Step Solution
Verified Answer
An equation in \(x\) and \(y\) defines \(y\) as a function of \(x\) if and only if each value of \(x\) corresponds to exactly one value of \(y\). One way to test this is to analyze the equation and check that for each \(x\), there is only one possible \(y\). If unsure, plotting the equation and ensuring it passes the vertical line test can help.
1Step 1: Understanding the concept of a function
In Mathematics, a function can be defined as a special relation where every input (\(x\)) gives a unique output (\(y\)). This means, for a given value of \(x\), there should only be one corresponding value of \(y\).
2Step 2: Analyzing the given equation
The given equation should be inspected to see if every input \(x\) produces exactly one output \(y\). If there are instances where a single value of \(x\) leads to multiple distinct possible values of \(y\), then the equation does not define \(y\) as a function of \(x\).
3Step 3: Plotting the given equation (Optional)
If the equation appears complicated to analyze by inspection, plotting it on a graph can be useful. For an equation in \(x\) and \(y\) to define a function, it must pass the vertical line test. If a vertical line drawn at any value of \(x\) on the graph intersects the curve at more than one point, then the equation does not define \(y\) as a function of \(x\).
Other exercises in this chapter
Problem 110
Begin by graphing the cube root function, \(f(x)=\sqrt[3]{x} .\) Then use transformations of this graph to graph the given function. $$g(x)=\sqrt[3]{x-2}$$
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Determine whether each statement makes sense or does not make sense, and explain your reasoning.I used a function to model data from 1990 through 2015 .I have t
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The graph of the linear function \(5 x+6 y-30=0\) is a line passing through the point (6,0) with slope \(-\frac{5}{6}\).
View solution Problem 111
Begin by graphing the cube root function, \(f(x)=\sqrt[3]{x} .\) Then use transformations of this graph to graph the given function. $$h(x)=\frac{1}{2} \sqrt[3]
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