Problem 110
Question
The correct order of magnetic moment (spin only values in BM) among the following is (a) \(\left[\mathrm{MnCl}_{4}\right]^{2}>\left[\mathrm{CoCl}_{4}\right]^{2-}>\mathrm{Fe}\left(\mathrm{CN}_{6}\right)^{4}\) (b) \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4}>\left[\mathrm{MnCl}_{4}\right]^{2}>\left[\mathrm{CoCl}_{4}\right]^{2-}\) (c) \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}>\left[\mathrm{CoCl}_{4}\right]^{2}>\left[\mathrm{MnCl}_{4}\right]^{2-}\) (d) \(\left[\mathrm{MnCl}_{4}\right]^{2}>\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4^{-}}>\left[\mathrm{CoCl}_{4}\right]^{2}\) (Atomic number of \(\mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27, \mathrm{Ni}=28\) )
Step-by-Step Solution
Verified Answer
The correct order is option (a): \(\left[\mathrm{MnCl}_{4}\right]^{2-} > \left[\mathrm{CoCl}_{4}\right]^{2-} > \mathrm{Fe}(\mathrm{CN})_{6}^{4-}\).
1Step 1: Determine Electronic Configurations
Identify the electronic configurations of each central metal ion. For \(\left[\mathrm{MnCl}_{4}\right]^{2-}\), Mn is in the +2 oxidation state (\(3d^5\)). For \(\left[\mathrm{CoCl}_{4}\right]^{2-}\), Co is in the +2 oxidation state (\(3d^7\)).For \(\mathrm{Fe}\left(\mathrm{CN}_{6}\right)^{4-}\), Fe is in the +2 oxidation state (\(3d^6\)).
2Step 2: Identify Spin Pairing and Determine Unpaired Electrons
Use the fact that \(\mathrm{CN}^-\) is a strong field ligand and \(\mathrm{Cl}^-\) is a weak field ligand:* \(\left[\mathrm{MnCl}_{4}\right]^{2-}\): All 5 d-electrons unpaired.* \(\left[\mathrm{CoCl}_{4}\right]^{2-}\): 3 unpaired d-electrons.* \(\mathrm{Fe}(\mathrm{CN})_{6}^{4-}\): Strong field, all d-electrons paired.
3Step 3: Calculate Magnetic Moment
Use the formula for the spin-only magnetic moment \( \mu = \sqrt{n(n+2)} \), where \( n \) is the number of unpaired electrons:* \(\left[\mathrm{MnCl}_{4}\right]^{2-}\): \( \mu = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \text{ BM} \).* \(\left[\mathrm{CoCl}_{4}\right]^{2-}\): \( \mu = \sqrt{3(3+2)} = \sqrt{15} \approx 3.87 \text{ BM} \).* \(\mathrm{Fe}(\mathrm{CN})_{6}^{4-}\): \( \mu = \sqrt{0} = 0 \text{ BM} \).
4Step 4: Order Magnetic Moments
The magnetic moments in order from highest to lowest are:1. \(\left[\mathrm{MnCl}_{4}\right]^{2-}\) with 5.92 BM2. \(\left[\mathrm{CoCl}_{4}\right]^{2-}\) with 3.87 BM3. \(\mathrm{Fe}(\mathrm{CN})_{6}^{4-}\) with 0 BMThus, the correct order is \(\left[\mathrm{MnCl}_{4}\right]^{2-} > \left[\mathrm{CoCl}_{4}\right]^{2-} > \mathrm{Fe}(\mathrm{CN})_{6}^{4-}\).
Key Concepts
Spin-Only FormulaElectronic ConfigurationStrong and Weak Field Ligands
Spin-Only Formula
The spin-only formula is used to calculate the magnetic moment of a substance, mainly when considering compounds with unpaired electrons. This formula is particularly useful because it simplifies how we understand the magnetism in coordination compounds. The formula is given by \[ \mu = \sqrt{n(n+2)} \] where \( n \) represents the number of unpaired electrons.
The spin-only magnetic moment is measured in Bohr Magnetons (BM), which is a unit used to express magnetic moments of electrons, atoms, and molecules.
Therefore, using the spin-only formula, the calculated magnetic moment is approximately 5.92 BM, indicating strong magnetism. Understanding this concept helps in predicting the behavior of such complexes under a magnetic field.
The spin-only magnetic moment is measured in Bohr Magnetons (BM), which is a unit used to express magnetic moments of electrons, atoms, and molecules.
- It is important to note that the formula only accounts for spin magnetic moments, assuming no substantial contribution from orbital motion;
- The applicability is greatest in cases where orbital contribution is quened, which is often seen in transition metals.
Therefore, using the spin-only formula, the calculated magnetic moment is approximately 5.92 BM, indicating strong magnetism. Understanding this concept helps in predicting the behavior of such complexes under a magnetic field.
Electronic Configuration
Electronic configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. It forms the foundation for understanding the magnetic properties of metal complexes. The electronic configuration determines how magnetic a compound will be based on the number of unpaired electrons.
Consider the given compounds:
Consider the given compounds:
- \([\mathrm{MnCl}_{4}]^{2-}\): Manganese in a +2 oxidation state has an electronic configuration of \(3d^5\).
- \([\mathrm{CoCl}_{4}]^{2-}\): Cobalt in a +2 oxidation state has an electronic configuration of \(3d^7\).
- \(\mathrm{Fe}(\mathrm{CN})_{6}]^{4-}\): Iron in a +2 oxidation state has an electronic configuration of \(3d^6\).
- \([\mathrm{MnCl}_{4}]^{2-}\), having five unpaired electrons, represents a high spin complex.
- \([\mathrm{CoCl}_{4}]^{2-}\) shows three unpaired electrons.
- \(\mathrm{Fe}(\mathrm{CN})_{6}]^{4-}\), due to the presence of strong field ligands, results in a configuration where all electrons are paired.
Strong and Weak Field Ligands
Ligands play a significant role in determining the magnetic properties of coordination compounds by influencing spin states through their ability to cause electronic pairing. Ligands are generally categorized as either strong field or weak field, based on how they affect the distribution of d-electrons in metal ions.
- Strong field ligands, such as cyanide \(\mathrm{CN}^-\), are known to create a large energy gap between d-orbitals. This causes electrons to pair up in lower energy orbitals, which can lead to low-spin configurations.
- Conversely, weak field ligands like chloride \(\mathrm{Cl}^-\) create a smaller energy gap, allowing more unpaired electrons, thus leading to high-spin configurations.
- \([\mathrm{MnCl}_{4}]^{2-}\) utilizes weak field ligand \(\mathrm{Cl}^-\), retaining unpaired electrons, hence exhibits strong magnetism.
- \(\mathrm{Fe}(\mathrm{CN})_{6}]^{4-}\) includes the strong field ligand \(\mathrm{CN}^-\), leading to paired electrons and low magnetic moment.
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