Problem 110
Question
Phenol and benzoic acid can be distinguished by which tests? (1) Libermann nitroso test (2) Reaction with \(\mathrm{NaHCO}_{3}\) (3) Reaction with \(\mathrm{NaOH}\) (4) Ferric chloride test (a) 1,2 and 3 (b) 1,2 and 4 (c) 1,3 and 4 (d) 2,3 and 4
Step-by-Step Solution
Verified Answer
(b) 1,2 and 4
1Step 1: Understand Test Reactions for Phenol
Phenol reacts with \(\text{FeCl}_3\) to produce a violet color, indicating a positive reaction for phenol in the Ferric chloride test. It does not react with \(\text{NaHCO}_3\), and with NaOH, phenol forms a salt known as sodium phenoxide.
2Step 2: Understand Test Reactions for Benzoic Acid
Benzoic acid reacts with \(\text{NaHCO}_3\) to produce carbon dioxide gas due to its acidic nature, indicating a positive reaction for benzoic acid. It also reacts with NaOH to form sodium benzoate, but does not undergo the Ferric chloride test.
3Step 3: Libermann Nitroso Test
The Libermann nitroso test is typically used for detecting phenols. Benzoic acid does not react to this test.
4Step 4: Compare Tests to Distinguish Phenol and Benzoic Acid
To distinguish phenol from benzoic acid, look for tests where their reactions differ: \(\text{FeCl}_3\) test for phenol (positive), \(\text{NaHCO}_3\) for benzoic acid (positive), and \(\text{NaOH}\) test, which shows dissolution for both but does not distinguish them.
5Step 5: Determine Correct Answer Based on Distinguishing Reactions
Based on the distinct reactions: Phenol tests positive with \(\text{FeCl}_3\) and can be detected using the Libermann nitroso test, while benzoic acid reacts with \(\text{NaHCO}_3\). We compare options and choose combinations that include these distinguishing reactions.
Key Concepts
Libermann Nitroso TestFerric Chloride TestChemical Reaction with NaHCO\(_3\)
Libermann Nitroso Test
The Libermann nitroso test is particularly significant in identifying phenolic compounds. In this test, phenol reacts with sodium nitrite in an acidic medium to form a nitroso phenol. This compound can further react to form a deep green or blue colored complex once the solution is treated with an alkaline solution.
The reaction proceeds through several interesting steps.
The reaction proceeds through several interesting steps.
- First, an acidic solution of phenol and sodium nitrite generates nitroso phenol.
- When alkali is added, the complex turns green or blue, confirming the presence of phenolic groups.
Ferric Chloride Test
The ferric chloride test is a classic chemical test that identifies phenolic hydroxyl groups in phenols. When you add a few drops of ferric chloride (
FeCl_3) to a solution of phenol, a complex forms. This results in a color transition that is typically violet or purple.
Here’s how the test works:
Here’s how the test works:
- Phenol acts as a ligand to the ferric ion, forming a phenol-ferric complex.
- This complex is responsible for the distinctive color change visible in the test.
Chemical Reaction with NaHCO\(_3\)
The reaction with sodium bicarbonate (NaHCO_3) serves as a straightforward method to verify the presence of carboxylic acids in compounds like benzoic acid. When benzoic acid is treated with NaHCO_3, it reacts to release carbon dioxide gas. This reaction is evident through the effervescence (bubbling) observed.
- The chemical equation for this reaction is:\[ \text{C}_6\text{H}_5\text{COOH} + \text{NaHCO}_3 \rightarrow \text{C}_6\text{H}_5\text{COONa} + \text{H}_2\text{O} + \text{CO}_2 \uparrow \]
Other exercises in this chapter
Problem 108
In the titration between oxalic acid and \(\mathrm{KMnO}_{4}\) if \(\mathrm{H}_{2} \mathrm{SO}_{4}\) is not used in excess (a) A brown precipitate due to \(\mat
View solution Problem 109
Which of the following reaction is given by a primary amine? (1) Carbyl amine reaction (2) Mustard oil reaction (3) Reaction with ceric ammonium nitrate (4) Dia
View solution Problem 111
A green crystalline compound shows the following tests: (i) Its aqueous solution gives a dense white precipitate with Barium chloride solution (ii) Its aqueous
View solution Problem 112
\(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) is used as the indicator in the \(\mathrm{Fe}^{2 \oplus}-\) \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2 \opl
View solution