Problem 110
Question
In the reaction \(\mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{g}) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq}), K=1.0 \times\) \(10^{5}\) at \(25^{\circ} \mathrm{C} .\) Would you expect a greater amount of product or reactant?
Step-by-Step Solution
Verified Answer
There will be a greater amount of product (\(H_{2}O_{2}(aq)\)) at equilibrium.
1Step 1: Understand the reaction
In this reaction, hydrogen peroxide gas, \( H_{2}O_{2}(g) \), is converted into aqueous hydrogen peroxide, \( H_{2}O_{2}(aq) \). This reaction can go both ways, meaning the gas can become aqueous, or the aqueous form can become a gas.
2Step 2: Understand the implications of K
The equilibrium constant, K, is a measure of the ratio of concentrations of products to reactants at equilibrium. If K > 1, there are more products than reactants at equilibrium, since the numerator (products) would be larger than the denominator (reactants). If K < 1, there are more reactants than products.
3Step 3: Apply K to this reaction
In this case, K=1.0x\(10^{5}\), which is much larger than 1. Therefore, at equilibrium, there would be more product (\(H_{2}O_{2}(aq)\)) than reactant (\(H_{2}O_{2}(g)\)).
Key Concepts
Equilibrium ConstantHydrogen PeroxidePhase Equilibrium
Equilibrium Constant
The equilibrium constant, often denoted as \( K \), provides insight into the balance of a chemical reaction at equilibrium. It depicts the ratio of the concentrations of products to the concentrations of reactants. The formula for \( K \) is:
In our example reaction, \( K = 1.0 \times 10^{5} \), a very large number, indicating a significant presence of products in comparison to reactants.This means the equilibrium position is shifted towards the formation of aqueous hydrogen peroxide over its gaseous form.
- \( K = \frac{[products]}{[reactants]} \)
In our example reaction, \( K = 1.0 \times 10^{5} \), a very large number, indicating a significant presence of products in comparison to reactants.This means the equilibrium position is shifted towards the formation of aqueous hydrogen peroxide over its gaseous form.
Hydrogen Peroxide
Hydrogen Peroxide, with the chemical formula \( H_2O_2 \), is a compound well-known for its bleaching and disinfecting properties.It exists in different phases, including liquid, gas, and aqueous solution.
🔍 **Characteristics:**
🔍 **Characteristics:**
- In Gas Phase: At higher temperatures or low pressures, hydrogen peroxide can transition into a gas, indicated by \( H_{2}O_{2}(g) \).
- In Aqueous Solution: When mixed with water, it is represented as \( H_{2}O_{2}(aq) \), typically seen at lower pressures or room temperatures.
Phase Equilibrium
Phase equilibrium occurs when different physical states or phases of a substance exist together without changing over time.In our reaction, it involves the equilibrium between gaseous hydrogen peroxide \( H_{2}O_{2}(g) \) and its aqueous form \( H_{2}O_{2}(aq) \).
At phase equilibrium, each phase maintains a stable concentration relative to the amount of energy available at a given temperature. The equilibrium constant \( K \), as derived from the reaction's conditions, helps determine how these concentrations relate.For example, a large \( K \) here suggests that maintaining a dynamic yet stable state is more reactive towards forming the aqueous phase.
🔍 **Key Takeaways:**
At phase equilibrium, each phase maintains a stable concentration relative to the amount of energy available at a given temperature. The equilibrium constant \( K \), as derived from the reaction's conditions, helps determine how these concentrations relate.For example, a large \( K \) here suggests that maintaining a dynamic yet stable state is more reactive towards forming the aqueous phase.
🔍 **Key Takeaways:**
- It's a balance without net change over time, despite ongoing molecular exchanges between phases.
- Dependent on pressure and temperature, these conditions influence which phase will predominantly form or dissolve.
Other exercises in this chapter
Problem 108
The Deacon process for producing chlorine gas from hydrogen chloride is used in situations where \(\mathrm{HCl}\) is available as a by-product from other chemic
View solution Problem 109
For the reaction \(\mathrm{SO}_{2}(\mathrm{g}) \rightleftharpoons \mathrm{SO}_{2}(\mathrm{aq}), K=1.25 \mathrm{at}\) \(25^{\circ} \mathrm{C} .\) Will the amount
View solution Problem 111
An equilibrium mixture of \(\mathrm{SO}_{2}, \mathrm{SO}_{3},\) and \(\mathrm{O}_{2}\) gases is maintained in a \(2.05 \mathrm{L}\) flask at a temperature at wh
View solution Problem 112
Using the method in Appendix \(\mathrm{E}\), construct a concept map of Section \(15-6,\) illustrating the shift in equilibrium caused by the various types of d
View solution