Problem 110
Question
Given \(\quad f(x, y)=x^{2}-4 y, \quad\) find \(\lim _{h \rightarrow 0} \frac{f(x+h, y)-f(x, y)}{h}\).
Step-by-Step Solution
Verified Answer
The limit is \( 2x \).
1Step 1: Understanding the Problem
We are asked to find the limit that represents the derivative of the function \( f(x, y) = x^2 - 4y \) with respect to \( x \). This is essentially finding \( \frac{\partial f}{\partial x} \).
2Step 2: Setting Up the Expression
First, substitute \( x+h \) into the function: \( f(x+h, y) = (x+h)^2 - 4y \). Then calculate \( f(x+h, y) - f(x, y) \).
3Step 3: Expanding the Expression
Expand \( (x+h)^2 \):\[ (x+h)^2 = x^2 + 2xh + h^2 \]Replace back in the function: \[ f(x+h, y) = x^2 + 2xh + h^2 - 4y \].
4Step 4: Calculating the Difference
Compute \( f(x+h, y) - f(x, y) \):\[ x^2 + 2xh + h^2 - 4y - (x^2 - 4y) = 2xh + h^2 \].
5Step 5: Forming the Difference Quotient
Form the difference quotient:\[ \frac{f(x+h, y) - f(x, y)}{h} = \frac{2xh + h^2}{h} \].
6Step 6: Simplifying the Expression
Simplify the quotient by canceling \( h \):\[ \frac{2xh + h^2}{h} = 2x + h \].
7Step 7: Taking the Limit
Take the limit as \( h \to 0 \):\[ \lim_{h \to 0} (2x + h) = 2x \].
8Step 8: Conclusion
The limit is \( 2x \), which represents the partial derivative of \( f(x, y) \) with respect to \( x \).
Key Concepts
Multivariable CalculusLimit CalculationDerivative Rules
Multivariable Calculus
Multivariable Calculus extends the concepts of single-variable calculus into higher dimensions. This means that functions can now depend on more than one variable, such as \( f(x, y) \), which has two inputs, \( x \) and \( y \). When dealing with such functions, it's essential to understand how each variable independently affects the output. This is why we study **partial derivatives**. Unlike ordinary derivatives, which consider changes in only one direction, partial derivatives focus on one variable at a time, treating all other variables as constants. For example, when calculating the partial derivative of \( f(x, y) = x^2 - 4y \) with respect to \( x \), we consider \( x \) as the changing variable and \( y \) as a constant. This involves calculating the derivative as if it were a single-variable problem with respect to \( x \).
- Partial derivatives provide insights into the slope and rate of change.
- They help in understanding multidimensional functions better.
- Essential in fields such as physics, engineering, and economics.
Limit Calculation
One of the fundamental concepts in calculus is **limit calculation**, which extends to multivariable contexts. When finding the derivative, either full or partial, the limit definition of a derivative is incredibly important. For instance, to find \( \frac{\partial f}{\partial x} \) of the given function \( f(x, y)\), we explore the behavior of the function as it approaches a specific point along the \( x \)-axis. This behavior is encapsulated in the limit expression \( \lim_{h \to 0} \frac{f(x+h, y) - f(x, y)}{h} \).
As \( h \) approaches zero, this expression describes the instantaneous rate of change or the slope of the tangent at any point on the function along this axis. Calculating this limit involves a few steps:
As \( h \) approaches zero, this expression describes the instantaneous rate of change or the slope of the tangent at any point on the function along this axis. Calculating this limit involves a few steps:
- Substitute \( x+h \) into the function to understand its behavior near \( x \).
- Expand and simplify the expression to separate out terms that disappear as \( h \) becomes negligibly small.
- Factor and reduce the quotient to reveal the underlying pattern or derivative.
Derivative Rules
In calculus, derivative rules are essential shortcuts for finding the derivatives of functions without resorting to first principles. When dealing with partial derivatives, these rules are extended to functions of multiple variables for swift calculation. For a given function such as \( f(x, y) = x^2 - 4y \), the derivative rules help us understand how to differentiate terms individually and then recombine them.
Key rules that apply include:
Key rules that apply include:
- **Power Rule**: If \( f(x) = x^n \), then \( \frac{d}{dx} x^n = nx^{n-1} \). This helps in instantly calculating derivatives of polynomial terms like \( x^2 \) resulting in \( 2x \).
- **Constant Rule**: The derivative of a constant is zero, and in partial derivatives, constant terms involving other variables remain unchanged.
- **Sum Rule**: The derivative of a sum of functions is the sum of the derivatives. This allows us to separate and individually handle each component, like \( x^2 \) and \(-4y \).
Other exercises in this chapter
Problem 107
Use polar coordinates to find \(\lim _{(x, y) \rightarrow(0,0)} \frac{\sin \sqrt{x^{2}+y^{2}}}{\sqrt{x^{2}+y^{2}}}\). You can also find the limit using L'Hôpita
View solution Problem 108
Use polar coordinates to find \(\lim _{(x, y) \rightarrow(0,0)} \cos \left(x^{2}+y^{2}\right)\).
View solution Problem 111
Given \( f(x, y)=x^{2}-4 y, \quad\) find \(\lim _{h \rightarrow 0} \frac{f(1+h, y)-f(1, y)}{h}\).
View solution Problem 112
For the following exercises, calculate the partial derivative using the limit definitions only. $$ \frac{\partial z}{\partial x}\( for \)z=x^{2}-3 x y+y^{2}$$
View solution