Problem 110
Question
A hydrocarbon of molecular formula, \(\mathrm{C}_{\mathrm{s}} \mathrm{H}_{18}\) gives only one monochloro derivative. The hydrocarbon is (a) 2 -methyl heptane (b) octane (c) \(2,2,3,3\)-tetramethyl butane (d) \(2,2,4\)-trimethyl pentane
Step-by-Step Solution
Verified Answer
The hydrocarbon is \(2,2,3,3\)-tetramethyl butane.
1Step 1: Understanding the Problem
We are asked to identify a hydrocarbon that forms only one monochloro derivative when it reacts with chlorine. The compound's molecular formula is given as \(\mathrm{C}_{8}\mathrm{H}_{18}\). The choices provided are different structural isomers based on this molecular formula.
2Step 2: Defining Monochloro Derivative
A monochloro derivative results when one hydrogen atom in the hydrocarbon is replaced by a chlorine atom. If a compound gives only one such derivative, then all hydrogen atoms must be equivalent for substitution, indicating equivalent carbon environments.
3Step 3: Analyzing the Options
Examine each option: (a) 2-methyl heptane: Has different types of hydrogens (primary, secondary, tertiary) leading to multiple chlorination sites.(b) Octane: Contains different carbon environments resulting in multiple derivatives.(c) \(2,2,3,3\)-tetramethyl butane: All hydrogens are equivalent.(d) \(2,2,4\)-trimethyl pentane: Has hydrogens in different positions, leading to multiple derivatives.
4Step 4: Identifying the Correct Hydrocarbon
From Step 3, \(2,2,3,3\)-tetramethyl butane is the only structure where all hydrogen atoms are identical due to its symmetry, resulting in only one possible monochloro derivative.
Key Concepts
Hydrocarbon IsomersMonochloro DerivativeStructural IsomersChemical Symmetry
Hydrocarbon Isomers
Hydrocarbon isomers are different compounds that have the same molecular formula but different arrangements of atoms. This concept is crucial in organic chemistry because it illustrates how the same set of atoms can create substances with vastly different properties.
- Molecular formulae like \(C_nH_{2n+2}\) apply to alkanes, showcasing the diversity among isomers.
- Isomers can be further categorized into structural isomers, where the connectivity of carbon atoms differs, and stereoisomers, which differ only in spatial orientation.
Monochloro Derivative
A monochloro derivative in organic chemistry is a compound formed when one hydrogen atom in a hydrocarbon is substituted with a chlorine atom. This change can significantly alter the properties of the original hydrocarbon.
Key points about monoclorination:
- It results in a single chlorine atom being added.
- The position where substitution occurs is crucial, as it affects the compound's chemical properties.
Structural Isomers
Structural isomers are compounds with the same molecular formula but differing in how their atoms are connected. These variations generate different physical and chemical properties even though they share the same components. To identify structural isomers:
- Examine the arrangement of carbon skeletons.
- Consider how they branch and differ in carbon-hydrogen bonding patterns.
- Understand that each unique configuration can lead to distinct reactions.
Chemical Symmetry
Chemical symmetry in molecules refers to the distribution of similar or equivalent parts, impacting how the molecule interacts with other substances. When a molecule is highly symmetrical, its chemical behavior can be more predictable, particularly in reactions like substitution.
- Symmetry leads to equivalent environments for atoms, meaning all equivalent hydrogens react the same way.
- In symmetrical structures, substitution reactions result in fewer derivatives due to identical carbon environments.
Other exercises in this chapter
Problem 108
Which one of the following compounds would have the highest heat of hydrogenation? (a) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{C}\left(\mathrm{CH}
View solution Problem 109
When 2 -methyl butan-l-ol is dehydrated to give an alkene, the preferred product is (a) but-I-ene (b) but-2-ene (c) 2 -methyl but-l-ene (d) 2-methyl but-2-ene
View solution Problem 111
Chloroethane reacts with magnesium in dry ether to form \(\mathrm{X}\). When \(\mathrm{X}\) is hydrolyzed, a carbon compound \(\mathrm{Y}\) and \(Z\) are formed
View solution Problem 112
Which one of the following compound yields only one product on monobromination? (a) neopentane (b) aniline (c) phenol (d) toluene
View solution