Problem 11
Question
Write each equation in its equivalent logarithmic form. $$ 2^{-4}=\frac{1}{16} $$
Step-by-Step Solution
Verified Answer
The equivalent logarithmic form of the given exponential equation is \( \log_{2}\left(\frac{1}{16}\right) = -4\).
1Step 1: Identify the base, the outcome, and the exponent in the given exponential equation.
In the given equation \(2^{-4} = \frac{1}{16}\), the base is 2, the exponent is -4, and the outcome is \(\frac{1}{16}\).
2Step 2: Convert the exponential equation to its logarithmic form.
The resultant logarithmic form would be in the pattern log_b (a) = c, so based on the given equation, it becomes \( \log_{2}\left(\frac{1}{16}\right) = -4\).
Key Concepts
Exponential EquationLogarithmBase and ExponentEquivalent Equations
Exponential Equation
An exponential equation is a type of mathematical equation in which a variable appears in the exponent. This is different from a linear or quadratic equation, where the variable is typically a base component or a multiplier. Exponentials are powerful because they can represent rapid growth or decay through the exponentiation process.
In the equation we were given, \(2^{-4} = \frac{1}{16} \), we see an example of exponential decay. The variable in the exponent can make significant changes in the outcome, even with small variations. For example, multiplying the base by itself repeatedly showcases how quickly the result can escalate or reduce. Exponentials deal with 'powers,' and when these powers are negative, as in our example, they result in fractions or very small numbers.
In the equation we were given, \(2^{-4} = \frac{1}{16} \), we see an example of exponential decay. The variable in the exponent can make significant changes in the outcome, even with small variations. For example, multiplying the base by itself repeatedly showcases how quickly the result can escalate or reduce. Exponentials deal with 'powers,' and when these powers are negative, as in our example, they result in fractions or very small numbers.
Logarithm
A logarithm is the inverse operation to exponentiation, much like how subtraction is the inverse of addition. In simple terms, a logarithm answers the question, 'To what power must the base be raised, to produce this given number?'
The equation \( \log_{2}\left(\frac{1}{16}\right) = -4\) tells us that 2 must be raised to the power of -4 to result in \(\frac{1}{16}\).
The equation \( \log_{2}\left(\frac{1}{16}\right) = -4\) tells us that 2 must be raised to the power of -4 to result in \(\frac{1}{16}\).
- Understanding Logarithms: Logarithms break down exponential problems, making it easier to manage very large or very small numbers.
- Usage: They are beneficial in various fields, such as computer science, biology, and financial modeling, due to their ability to simplify products into sums and capture rates of change effectively.
Base and Exponent
The base and exponent are fundamental components in both exponentials and logarithms. Understanding their relationship is key to grasping more complex mathematical concepts.
In the expression \(2^{-4}\):
When transitioning from exponential form to logarithmic form, the base remains crucial as it forms the base of the logarithm as well. Thus, recognizing and identifying the base and exponent is critical for conversion between forms.
In the expression \(2^{-4}\):
- Base (2): The number that is being multiplied by itself repeatedly. The base determines the "root" of the exponential calculation.
- Exponent (-4): The power to which the base is raised. In this case, a negative exponent indicates that we are dealing with a reciprocal or fraction.
When transitioning from exponential form to logarithmic form, the base remains crucial as it forms the base of the logarithm as well. Thus, recognizing and identifying the base and exponent is critical for conversion between forms.
Equivalent Equations
Equivalent equations are equations that have the same solutions or values. In mathematics, converting different forms of the same equation, like changing from exponential to logarithmic, is a common method to demonstrate equivalence.
When you convert \(2^{-4} = \frac{1}{16}\) into \( \log_{2} (\frac{1}{16}) = -4\), it represents an equivalent equation but in a different form.
When you convert \(2^{-4} = \frac{1}{16}\) into \( \log_{2} (\frac{1}{16}) = -4\), it represents an equivalent equation but in a different form.
- Significance: Demonstrating equivalence is essential for understanding how one form can sometimes make solving or analyzing a problem much more straightforward.
- Application: Recognizing equivalent equations is helpful in solving problems related to growth rates, half-lives in chemistry, and compounding interest in finance, among others.
Other exercises in this chapter
Problem 10
In Exercises \(1-10,\) approximate each number using a calculator. Round your answer to three decimal places. $$ e^{-0.75} $$
View solution Problem 11
In Exercises \(1-40,\) use properties of logarithms to expand each logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions
View solution Problem 12
In Exercises \(1-40,\) use properties of logarithms to expand each logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions
View solution Problem 12
Write each equation in its equivalent logarithmic form. $$ 5^{-3}=\frac{1}{125} $$
View solution