Problem 11
Question
Write an exponential function \(y=a b^{x}\) for a graph that includes the given points. $$ (2,122.5),(3,857.5) $$
Step-by-Step Solution
Verified Answer
The exponential function that includes the given points is \(y = 2.5 \cdot 7^x\).
1Step 1: Setting Up the Exponential Equations
First, plug in the x and y values from the two given points into the exponential function to derive two equations. For the point (2,122.5), the equation becomes \(122.5 = ab^2\). For the point (3,857.5), the equation becomes \(857.5 = ab^3\).
2Step 2: Solving the Equations
Solve the first equation for 'a' to get \(a = 122.5 \div b^2\). Substitute this into the second equation to get \(857.5 = (122.5 \div b^2) \cdot b^3\). Simplify this equation by multiplying the right side to give \(857.5 = 122.5b\). Solving for 'b' gives \(b = 857.5 \div 122.5 \approx 7\).
3Step 3: Solve for 'a'
Now substitute 'b' back into the first equation to solve for 'a'. This gives \(a = 122.5 \div (7^2) \approx 2.5\).
4Step 4: Getting the Exponential Function
Substitute 'a' and 'b' into the exponential function to get \(y = 2.5 \cdot 7^x\).
Key Concepts
Equation SolvingAlgebraFunction Graphing
Equation Solving
Solving equations involves determining the unknown values that make the equation true. In this problem, we have two equations derived from the points on the graph of an exponential function. The key is to solve these simultaneously to find values for the variables \(a\) and \(b\).
Here’s a quick breakdown of the method used:
Here’s a quick breakdown of the method used:
- Use the form of the exponential function \(y = ab^x\) and plug in the given points as coordinates to form two equations.
- Solve one of the equations for one variable (like \(a\)) and substitute it into the other equation. This reduces the number of variables.
- Continue the process using algebraic manipulation to find the values of both variables.
Algebra
Algebra is the branch of mathematics dealing with symbols and the rules for manipulating these symbols. It’s the foundation for equation solving and further mathematical concepts like functions.
In this exercise, algebra helps us:
In this exercise, algebra helps us:
- Rearrange equations: Algebra allows us to move terms from one side of an equation to another to isolate variables, aiding us in finding solutions.
- Perform operations like division and multiplication to simplify complex expressions.
- Apply logarithmic identities where needed in more advanced problems, though not necessary here.
Function Graphing
Graphing a function means visually representing the relationship between input values \(x\) and their corresponding output values \(y = ab^x\). In exponential functions like the one in this exercise, graphing helps visualize how rapidly the function grows depending on the values of \(a\) and \(b\).
Some basics of graphing exponential functions include:
Some basics of graphing exponential functions include:
- The base \(b\) determines the growth rate: If \(b > 1\), the function shows exponential growth, and if \(b < 1\), it shows exponential decay.
- The constant \(a\) affects the vertical stretch or compression and the y-intercept of the graph.
- Exponential graphs are not symmetrical, which is different from other graph types like parabolas.
Other exercises in this chapter
Problem 11
Write each logarithmic expression as a single logarithm. \(\log 7+\log 2\)
View solution Problem 11
Write each equation in logarithmic form. $$ 4=\left(\frac{1}{2}\right)^{-2} $$
View solution Problem 12
Solve each equation. Round to the nearest ten-thousandth. Check your answers. $$ 2^{3 x-4}=5 $$
View solution Problem 12
Graph each function as a transformation of its parent function. $$ y=-2(5)^{x+3} $$
View solution