Problem 11
Question
What is the hybridization of the carbon atom in phosgene, \(\mathrm{Cl}_{2}\) CO? Give a complete description of the \(\sigma\) and \(\pi\) bonding in this molecule.
Step-by-Step Solution
Verified Answer
The carbon atom in phosgene is \(\text{sp}^2\) hybridized, forming 3 sigma bonds and 1 pi bond.
1Step 1: Identify the Molecule Structure
Phosgene is a molecule with the formula \( ext{Cl}_2\text{CO}\). The carbon atom forms bonds with two chlorine atoms and one oxygen atom. The geometry around the carbon atom is important to determine the hybridization.
2Step 2: Determine the Total Number of Sigma Bonds
Carbon in phosgene is bonded to two chlorine atoms and one oxygen atom through sigma bonds. Therefore, there are a total of three sigma bonds present around the carbon atom.
3Step 3: Account for the Lone Pairs
In phosgene, all valence electrons of carbon are involved in bonding; the carbon atom does not have any lone pairs.
4Step 4: Calculate the Steric Number
The steric number is the sum of sigma bonds and lone pairs. For carbon in phosgene, the steric number is 3 (3 sigma bonds + 0 lone pairs).
5Step 5: Determine Hybridization Type
With a steric number of 3, the hybridization of the carbon atom is \(\text{sp}^2\). This hybridization corresponds with a trigonal planar shape.
6Step 6: Describe the Sigma and Pi Bonding
The \(\text{sp}^2\) hybridized orbitals of carbon participate in forming three sigma bonds: two \(\text{C-Cl}\) bonds and one \(\text{C-O}\) bond. The remaining unhybridized \(p\) orbital on carbon overlaps with an oxygen \(p\) orbital to form a \(\pi\) bond.
Key Concepts
Sigma BondsPi BondsSteric NumberTrigonal Planar Geometry
Sigma Bonds
Sigma bonds (\( \sigma \) bonds) are a type of covalent bond formed by the head-on or axial overlap of orbitals. In phosgene (\( \text{Cl}_{2}\text{CO} \)), the carbon atom uses its hybridized \( \text{sp}^2 \) orbitals to create sigma bonds. Specifically, these bonds form between the carbon and other atoms, such as chlorine and oxygen. In this molecule:
- Two sigma bonds are formed between carbon and each of the chlorine atoms.
- One sigma bond exists between carbon and the oxygen atom.
Pi Bonds
Pi bonds (\( \pi \) bonds) are a form of covalent bond that results from the side-by-side overlap of unhybridized \( p \) orbitals. In phosgene, after the formation of three sigma bonds through the \( \text{sp}^2 \) hybridization of carbon, there's one \( p \) orbital left unhybridized on carbon. This unhybridized \( p \) orbital overlaps with a corresponding \( p \) orbital on oxygen to form a pi bond.Here's how pi bonds differ:
- Pi bonds are formed after sigma bonds in double or triple bonds.
- They restrict rotational movement around the bond.
- They are generally weaker than sigma bonds due to the lateral overlap of orbitals.
Steric Number
The steric number is a handy concept for predicting the hybridization of an atom in a molecule. It represents the total number of regions of electron density around a central atom, which includes sigma bonds and lone pairs.To find the steric number:
- Count each sigma bond.
- Add any lone pairs on the atom.
- Two chlorine atoms.
- One oxygen atom.
- No lone pairs.
Trigonal Planar Geometry
Trigonal planar geometry is the shape assumed by molecules with a steric number of 3, and it’s a common feature of \( \text{sp}^2 \) hybridized atoms. In the case of phosgene, the carbon atom bonded to two chlorine atoms and one oxygen atom leads to such geometric formation.Key features:
- Molecules are flat, or planar.
- The bond angles are approximately 120°.
- All atoms in the plane are equidistant from each other.
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